Chapter 6:Synchronous Sequential Circuits
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Transcript Chapter 6:Synchronous Sequential Circuits
Chapter 5
Synchronous
Sequential
Circuits
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Logic Circuits- Review
Logic Circuits
Combinational
Circuits
•Consists of logic gates
whose outputs are
determined from the current
combination of inputs.
•Performs an operation that
can be specified by a set of
Boolean functions.
Sequential
Circuits
•Employ storage elements in
addition to logic gates.
•Outputs are a function of the
inputs and the state of the
storage elements.
•Output depend on present
value of input + past input.
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Overview
Storage
Elements and Analysis
Introduction to sequential circuits
Types of sequential circuits
Storage elements
Latches
Flip-flops
Sequential
State
circuit analysis
tables
State diagrams
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Introduction to Sequential Circuits
Inputs
A
Sequential
circuit contains:
Storage
Elements
Storage elements:
Latches or Flip-Flops
Combinatorial Logic:
Implements
Combinational
Logic
State
a multiple-output
switching function
Inputs are signals from the outside.
Outputs are signals to the outside.
Other inputs, State or Present State,
are signals from storage elements.
The remaining outputs, Next State are
inputs to storage elements.
Next
State
Outputs
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Introduction to Sequential Circuits
Inputs
Outputs
Combinational
Logic
Storage
Elements
State
Sequential Logic
Output function
Outputs = g(Inputs, State)
Next state function
Next State = f(Inputs, State)
Next
State
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Types of Sequential Circuits
Depends on the times at which:
storage elements observe their inputs, and
storage elements change their state
Synchronous
Behavior defined from knowledge of its signals at discrete
instances of time
Storage elements observe inputs and can change state
only in relation to a timing signal (clock pulses from a clock)
Asynchronous
Behavior defined from knowledge of inputs at any instant
of time and the order in continuous time in which inputs
change
If clock just regarded as another input, all circuits are
asynchronous!
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5.3 Storage Elements :Latches
Storage
elements
Maintain
a binary state (0 or 1) indefinitely as
long as power is delivered to the circuit
Switch states (01 or 10) when directed by
an input signal
Most
basic storage element
Used mainly to construct Flip-Flops
Asynchronous storage circuit
Types of latches:
SR Latches
S`R` Latches
D Latches
X=X
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Basic (NOR) S – R Latch
Cross-coupling
S – R Latch:
two NOR gates gives the
Graphic Symbol
R (reset)
S
Q
R
Q
S (set)
Q
Q
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Basic (NOR)
S – R Latch
S
R
Q t+1
0
0
Q t+1=Q
No change
0
1
Reset to 0
1
0
Set to 1
1
1
undefined
S
R
Q
Q t+1
Q’ t+1
0
0
0
Q t+1=Q =0
1
0
0
1
1
0
0
1
0
0
1
0
1
1
0
1
1
0
0
1
0
1
0
1
1
0
1
1
0
Undefined
؟
1
1
1
undefined
؟
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Basic (NAND) Ś – Ŕ Latch
“Cross-Coupling”
the Ś -Ŕ Latch:
Graphic Symbol
S
Q
R
Q
two NAND gates gives
S (set)
R (reset)
Q
Q
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Basic (NAND)
Ś – Ŕ Latch
S
R
Q t+1
0
0
Undefined
0
1
Reset to 1
1
0
Set to 0
1
1
Q t+1=Q
No change
S
R
Q
Q t+1
Q’ t+1
0
0
0
?
?
0
0
1
?
?
0
1
0
1
0
0
1
1
1
0
1
0
0
0
1
1
0
1
0
1
1
1
0
0
1
1
1
1
1
0
Clocked S - R Latch
Adding two NAND
gates to the basic
Ś - Ŕ NAND latch
gives the clocked
S – R latch:
S`
S
Q
1
C
1
Has a time sequence R
behavior similar to the
basic S-R latch except that
the S and R inputs are only
observed when the line C is
high.
C means “control” or
“clock”.
Q
R`
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D Latch(Transparent Latch)
Adding
an inverter to the S-R Latch,
gives the D Latch:
Note that there are no “indeterminate”
states!
The graphic symbol for a
D Latch is:
D
Q
D
Q
Q
C
Q
C
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D Latch(Transparent Latch)
D
Q t+1
0
0
1
1
Q D
0 0
0 1
1 0
1 1
Q(t+1)
0
1
0
1
Chapter 5: Sequential Circuits
5.4: Flip-Flops
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Flip-Flops
The
latch timing problem
Master-slave flip-flop
Edge-triggered flip-flop
Other flip-flops
- JK flip-flop
- T flip-flop
The Latch Timing Problem
In a sequential circuit, paths may exist through
combinational logic:
From one storage element to another
From a storage element back to the same storage
element
The combinational logic between a latch output
and a latch input may be as simple as an
interconnect
For a clocked D-latch, the output Q depends on the
input D whenever the clock input C has value 1
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The Latch Timing Problem
(continued)
Consider the following circuit:
Suppose that initially Y = 0.
Clock
D
Q
C
Q
Clock
Y
As long as C = 1, the value of Y continues to change!
The changes are based on the delay present on the
loop through the connection from Y back to Y.
This behavior is clearly unacceptable.
Desired behavior: Y changes only once per clock pulse
Y
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The Latch Timing Problem
(continued)
A
solution to the latch timing problem is to
break the closed path from Y to Y within
the storage element
The commonly-used, path-breaking
solutions replace the clocked D-latch
with:
a master-slave flip-flop
an edge-triggered flip-flop
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Master-Slave Flip-Flop
Master
D
D
C
C
Slave
Y
D
Q
C
Consists of two clocked
D latches in series
with the clock on the
second latch inverted
What happened when c=1?
The data from D input is transferred to the master .
The slave is disabled .
Any change in the input change the master output ( Y ) but
can’t effect the slave output .
Q
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Master
What
D
D
C
C
Slave
Y
happened
when C=0?
The master is disabled .
The slave is enable.
The value of ( Y ) is
transferred to the slave as input .
The output ( Q ) is equal ( Y ) .
Conclusion:
The output of the F.F. can change only during
the transition of clock from 1 to 0 or at
Trigger .
D
C
Q
Q
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Timing
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Timing
A
trigger: The state of a latch or flip-flop is
switched by a change of the control input.
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Graphic Symbols
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Graphic Symbols
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Other flip-flops
•
•
•
Other F-Fs can be built using D F-F
There are four operation on a F-F
- set to 1
- Reset to 0
- toggle ( complement ) of Q
- nothing
There are tow F-F
- JK F-F
- T F-F
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JK Flip-Flops
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JK Flip-Flops
D = JQ’ + K’Q
J
K
Q t+1
0
0
No change
Q t+1 = Q
0
1
Reset to 0
1
0
Set to 1
1
1
Complement
Q t+1= Q’
T Flip-Flops
T Flip-Flops
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T Flip-Flops
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Characteristic Table
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Characteristic Table
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Characteristic Equations
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State Equation
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State Equation
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Analysis
This
circuit consist of :
2 D F-F A and B
Input x
Output Y
Qt+1 = D
A= D A
B = DB
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State Table
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State Diagram
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Input / output
state
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Analysis
1 D F-F ( A )
2 Input X , Y
Qt+1 = D
D=AXy
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Analysis
2 JK F-F (A , B)
Input x
Q t+1 = JQ’ + K’Q
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Analysis
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T F-F ( A, B )
1 input X
1 output Y
Qt+1 = T Q
The input equations are
T_A = BX
T_B = X
The out put equation is
Y = AB
The characteristic equations are :
At+1 = T_A A
= BX A
= BX(A’) + (BX)’A
= A’BX + AB’ + AX’
Bt+1 = X B
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