Transcript Document 7606842

B. Reaksi oksidasi dan reduksi dalam senyawa organik
H3C CH3
H2C CH2
HC CH
oxidation
fewer C-H bonds
reduction
more C-H bonds
H2C=CH2 + H2O2  HO–CH2–CH2–OH
H2C=CH2 + H2O  CH3–CH2–OH
H2C=CH2 + H2  CH3–CH3
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Penentuan bilangan oksidasi ]
1. Untuk setiap atom dalam ikatan, atom elektropositif
bilangan oksidasinya +1, dan atom yang elektronegatif
bilangan oksidasi -1
(If the atoms are the same, each atom gets a 0.)
-1
Cl
+1
+1 +1
-1 C
+1
-1
O
-1
H
.
2. Jumlah atom
-1 total
Cl
+1
H
+1 +1
-1 C
+1
-1
O
Oxidation number of carbon is
+1 +1 +1 -1 = +2
-1
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Soal : tentukan bilangan oksidasi untuk karbon dalam tiap
molekul
H C N
H O
2
H C
1
C O H
Br
H
H C
OH
Cl
Check Answer
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Jawaban:
H C N
C = +2
H O
2
H C
1
C O H
C1 = +3; C2 = -1
Br
H
H C
Cl
C=0
OH
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Tentukanlah apakah reaksi berikut oksidasi, reduksi
atau bukan keduanya.
Br Br
H2C
CH2
+
Br2
H2C
CH2
H H
H2C
CH2
+ H2O
H C C H
H OH
Check Answer
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Jawaban:
Br Br
H2C
CH2
+
Br2
H2C
CH2
Oxidation: Each carbon
changes from a -2 to a -1.
H H
H2C
CH2
+ H2O
H C C H
H OH
Neither. One carbon changes from a -2 to a -3 (gets
reduced), but the other carbon goes from a -2 to a -1
(gets oxidized.) No net change.
Check Answer
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B. Reaksi halogenasi
250oC – 400oC
sinar
CH4 + X2
H
OH
H C H
H C H
H
H
H
CH3X + HX
O
O
O
C
C
C
H
H
OH
O
oxidation
more C-O bonds, fewer C-H bonds
reduction
fewer C-O bonds, more C-H bonds
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