Chapter 4 Calculating the Derivative
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Transcript Chapter 4 Calculating the Derivative
Chapter 4
Calculating the
Derivative
JMerrill, 2009
Review
Find the derivative of (3x – 2x2)(5 + 4x)
-24x2 + 4x + 15
Find the derivative of
2
5x 4 x 5
2
(x 1)
2
5x 2
x
2
1
4.3
The Chain Rule
Composition of Functions
A composition of functions is simply putting 2
functions together—one inside the other.
Example: In order to convert Fahrenheit to
Kelvin we have to use a 2-step process by first
converting Fahrenheit to Celsius.
5
C (F 3 2)
o
o
89 F = 31.7 C
9
K C 273
31.7oC = 304.7K
But if we put 1 function inside the other function,
then it is a 1-step process.
Composition of Functions
The composite of f(x) and g(x) is denoted f
which means the same as f(g(x)).
g
x
We are used to writing f(x). f(g(x)) simply
means that g(x) is our new x in the f
equation.
We can also go the other way. g f x
means g(f(x)).
Given
f(g(3)) =
= f(6)
= 4(6)2 – 2(6)
= 144 – 12
= 132
f ( x) 4 x 2 x
2
g(3) = 6
g ( x) 2 x
Given
f
f ( x)
1)
ff ((xx 1)
g (x) x 1
x
g
g x
ff ((gg((xx))))
1
g(x) = x+1
1
f
x
g ( f ( x ))
1
g
x
x 1
1
1
x
Substitute x+1
In place of the
x in the f equation
The new x in the g
equation
=
The Chain Rule
Chain Rule Example
Use the chain rule to find Dx(x2 + 5x)8
Let u = x2 + 5x
Another way to think
of it: The derivative of
Let y = u8
dy
dy du
dx du dx
8u
7
the outside times the
derivative of the inside
2 x 5
2
8 x 5x
7
2x 5
Chain Rule – You Try
Use the chain rule to find Dx(3x - 2x2)3
Let u = 3x - 2x2
Let y = u3
The derivative of the
outside times the
derivative of the inside
dy
dy du
dx du dx
3u
2
3 4 x
3 3x 2x
2
2
3 4 x
Chain Rule
Find the derivative of y = 4x(3x + 5)5
This is the Product Rule inside the Chain Rule.
Let u = 3x + 5; y = u5
4
5
4 x 5u (3) (3x 5 ) ( 4 )
4
5
4 x 5(3x 5 ) (3) 4(3x 5 )
4 x 15(3x 5 )
4
4
4(3 x 5 )
6 0 x(3x 5 ) 4(3x 5 )
5
5
Chain Rule
6 0 x (3x 5 )
4
4 (3x 5 )
5
F a c to r o ut th e c o m m o n f a c to r
4
4 (3x 5 ) 1 5 x (3x 5 )
4
4 (3x 5 ) (18 x 5 )
Chain Rule
3x 2
7
Find the derivative of
x 1
This is the Quotient Rule in the Chain Rule
Let u = 3x + 2; let y = u7
6
7
( x 1) 7 u (3) (3x 2) (1)
( x 1)
2
6
7
( x 1) 7 ( 3x 2) (3) (3x 2)
( x 1)
2
6
7
2 1 ( x 1)(3x 2) (3x 2 )
( x 1)
2
Chain Rule
7
6
2 1 ( x 1)(3x 2) (3x 2)
( x 1)
2
F a c to r o ut th e c o m m o n f a c to r
6
(3x 2) 2 1( x 1) (3x 2)
( x 1)
(3 x 2 )
6
2 1x 2 1 3x 2
( x 1)
(3x 2)
6
2
2
18 x 2 3
( x 1)
2
4.4
Derivatives of Exponential Functions
Derivative of ex
Derivative of ax
x
Dx 3 (l n 3)3
x
Other Derivatives
Examples – Find the Derivative
y = e5x
e
g( x )
e
5x
(g '(x )
(5) 5 e
5x
Examples – Find the Derivative
y = 32x+1
g( x )
g '( x )
2x 1
(2)
ln a a
ln 3 3
2 ln 3 3
2x 1
Example
dy
2
x 1
Find
if y e
5x 2
dx
Use the product rule
y e
x
2
1
1
x2 1
Dx 5 x 2 2 5 x 2 Dx e
1
1
2
5 x 2 2 (5 )
x 1
e
(2x )
2
5
2 5x 2
Example
y e
e
2
x 1
1
Dx 5 x 2 2
5
2
x 1
2 5x 2
5e
2
x 1
2 5x 2
5 x 2 Dx
2
x 1
5 x 2 2x e
2
x 1
5 x 2 2x e
x2 1
e
Example Continued
5e
2
x 1
2
x 1
2xe
2 5x 2
5e
2
x 1
e
2
x 1
( 4 x )(5 x 2)
2 5x 2
e
2
x 1
5 4 x (5 x 2)
2 5x 2
e
2
x 1
2 5x 2
5x 2
2 5x 2
2
20 x 8x 5
2 5x 2
Get a common
denominator to
add the 2 parts
together
4.5
Derivatives of Logarithmic Functions
Definition
Bases – a side note
Everything we do is in Base 10.
We count up to 9, then start over. We change our numbering
every 10 units.
1
11
21
Two
tens
2
12
22
and
3
13
23…
One
Ones
…one
group
of
Place
4
14
s
ten and
5
15
1, 2,
6
16
3…ones
7
17
8
18
9
19
10
20
Bases
The Yuki of Northern California used Base 8.
They counted up to 7, then started over. The numbering
changed every 8 units.
1
13
25
Two
eights
2
14
26
and
One
3
15
27…
Ones
…one
eight
Place
4
16
s
and
5
17
3…ones
6
20
7
21
So, 17 in Base 8 = 15 in Base 10
10
22
11
23
258 = 2 eights + 5 ones = 21
12
24
Bases
The Mayans used Base 20.
The Sumerians and people of Mesopotamia
used Base 60.
Definition
Example
Find f’(x) if f(x) = ln 6x
Remember the properties of logs
ln 6x = ln 6 + ln x
d
dx
(ln 6)
0
1
x
d
dx
1
x
(ln x )
Definitions
Examples – Find the Derivatives
y = ln 5x
If g(x) = 5x, then g’(x) = 5
dy
dx
g '(x )
g(x )
5
5x
1
x
F’(x)
f(x) = 3x ln x2
Product Rule
d
2
2
f '( x ) (3x )
ln x ln x (3)
dx
2x
2
3x 2 ln x (3)
x
6 3 ln x
2