Transcript Introduction to Database System
The Relational Model
What DB models exist?
Most widely current model: Relational Model Vendors: IBM DB2, Microsoft, Oracle, Sybase, etc… “Legacy systems” have older models E.g., IBM’s IMS (hierarchical), CODASYL network model Recent and future competitors: object-oriented model: ObjectStore, Versant Object-relational model: Oracle, DB2 Semi-structured: XML Integrated in all major relational database systems Native XML database systems 421B: Database Systems - The Relational Model 2
Definitions
Relational Database: a set of relations Relation: Consists of two parts: Schema: specifies name of relation, plus a set of attributes, plus the domain/type of each attribute E.g., Students(sid:
string
, name:
string
, login:
string
, faculty:string, gpa:
real
) Instance: set of tuples (all tuples are distinct). A relation can be seen as a table: Column headers = attribute names, rows = tuples/records, columns/fields = attribute values #Rows = cardinality #Fields = degree / arity If clear from context, we say instead of “instance of a relation” simply “relation” Database Schema: collection of relation schemas 421B: Database Systems - The Relational Model 3
Example of Students Relation
sid name login faculty gpa 53666 Bartoli bartoli@cs Science 3.4
53688 Chang chang@eecs Eng 3.2
53650 Chang chang@math Science 3.8
...
Column headers = attributes All rows are distinct (set-oriented) Rows are not ordered (a permutation of rows represents still the same table) Columns are per definition not ordered but in practice we often assume a fixed order with this, a single tuple can be represented as (53666, Bartoli, bartoli@cs, Science, 3.4) 421B: Database Systems - The Relational Model 4
Relational DDL and DML
Data Definition Language (DDL): defines the schema of a database Data Manipulation Language (DML): “manipulates” the data, i.e., the instances of the relations Insert, update, delete tuples “Query” the relations: retrieve tuples that fulfill certain criteria (hence, often called “query language”) The Relational Model offers simple and powerful querying of data with precise semantics independent of how data is stored or whether changes in the physical structure are made (physical data independence) 421B: Database Systems - The Relational Model 5
The SQL Query Language
Developed by IBM (system R) in the 1970s Need for a standard since it is used by many vendors Standards: SQL-86 … SQL-99 / SQL3 (adds object-relational features) SQL:2003 (adds XML features) 421B: Database Systems - The Relational Model 6
SQL Data Types
All attributes must have a data type.
SQL supports several basic data types Character and string types CHAR(n) denotes a character string of fixed length (containing trailing blanks for padding if necessary).
VARCHAR(n) denotes a string of up to n characters (between 0 and n characters). SQL permits reasonable coercion between values of character string types Integer Types INT or INTEGER (names are synonyms) SHORTINT 421B: Database Systems - The Relational Model 7
Data Types (contd.)
Floating point numbers FLOAT or REAL (names are synonyms) DOUBLE PRECISION DECIMAL(n,d): real number with fixed decimal point. Value consists of n digits, with the decimal point d positions from the right.
Dates and time: DATE: has the form ‘YYYY-MM-DD’ TIME: has the form ‘15:00:02’ or ‘15:00:02.5’ May be compared and converted to string types Bit strings User defined domains New name for a data type Possibility to define restrictions on values of domain (< 10) 421B: Database Systems - The Relational Model 8
Data Definition: Table Creation
Defines all attributes of the relation The type/domain of each attribute is specified DBMS enforce correct type whenever a tuple is added or modified SQL is case insensitive It is possible to define default values Special NULL value: ‘unknown’
CREATE TABLE Students (sid CHAR(20), name VARCHAR2(20), login CHAR(10), faculty VARCHAR(20), gpa REAL DEFAULT 0.0) CREATE TABLE Enrolled (sid CHAR(20), cid CHAR(20), grade CHAR(2))
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DROP TABLE Students
Destroys the relation Students.
The schema information and the tuples are deleted.
ALTER TABLE Students ADD COLUMN firstYear:integer
The schema of students is altered by adding a new field; every existing tuple in the current instance is extended with a
null
value in the new field.
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Insert a single tuple using:
INSERT INTO Students (sid,name,login,faculty,gpa) VALUES(53688,’Chang’,’cheng@eecs’,’Eng’,3.2)
INSERT INTO Students (sid,name,login,faculty) VALUES(53688,’Chang’,NULL,’Eng’)
Can delete all tuples satisfying some condition
DELETE FROM Students WHERE name = ‘Chang’
Can update all tuples satisfying some condition
UPDATE Students SET gpa = 3.4
WHERE sid = 53688
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Querying the Data
than 3.5
SELECT name, gpa FROM Students WHERE gpa < 3.5
sid name login faculty gpa 53666 Bartoli bartoli@cs Science 3.4
53688 Chang chang@eecs Eng 3.2
53650 Chang chang@math Science 3.8
name gpa Bartoli 3.4
Chang 3.2
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Integrity Constraints (ICs)
Integrity Constraints must be true for any instance of the database; e.g., domain constraints ICs are specified when schema is defined ICs are checked when relations are modified A legal instance of a relation is one that satisfies all specified ICs.
DBMS should not allow illegal instances If DBMS checks ICs, stored data is more faithful to real-world meaning (also checks for entry errors) Of course, DBMS can only check what is specified in the schema 421B: Database Systems - The Relational Model 13
Primary Key Constraints
A set of fields is a key for a relation if No two distinct tuples can have same values in all key fields, and This is not true for any subset of the key.
If there are two or more keys, one of the candidates is chosen to be the primary key. The primary key attributes of a tuple may not be NULL.
A set of fields that contains a subset of fields fulfilling the key constraint is called a superkey E.g.
sid
is a key for
Students
. (What about
name
?). The set
(sid,gpa)
is a superkey 421B: Database Systems - The Relational Model 14
Primary and Candidate Keys in SQL
Possibly many candidate keys exist, one of which is chosen as the primary key Each student has a unique id.
CREATE TABLE Students (sid CHAR(20) PRIMARY KEY, name VARCHAR2(20),
For a given student and course, there is a single grade; further, no two students in a course receive the same grade
… CREATE TABLE Enrolled
Application dependent Defined carelessly, an IC can prevent the storage of database instances that arise in practice!
(sid CHAR(20), cid CHAR(20), grade CHAR(2), PRIMARY KEY (sid,cid), UNIQUE (cid,grade))
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Foreign Key
Foreign Key: Set of fields in one relation that is used to “refer” to a tuple in another relation.
Must correspond to the primary key of the second relation. Represents a “logical pointer”.
Examples in relation
Enrolled, sid
is a foreign key referring to Students:
Students(sid:CHAR(20),name:VARCHAR(20),login:CHAR(10), faculty:VARCHAR(20), gpa:REAL) Enrolled(sid:CHAR(20),cid:CAHR(20),grade:CHAR(2))
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Referential Integrity
Foreign Key Constraint: the foreign key value of a tuple must represent an existing tuple in the referred relation Enrollment may only contain a tuple of a student who exists in the Students relation If all foreign key constraints are enforced, referential integrity is achieved, i.e., no dangling references 421B: Database Systems - The Relational Model 17
Foreign Keys in SQL
Only students listed in the Students relation should be allowed to enroll for courses
CREATE TABLE Enrolled (sid CHAR(20), cid CHAR(20), grade CHAR(2), PRIMARY KEY (sid,cid) FOREIGN KEY (sid) REFERENCES Students)
sid name login faculty gpa 53666 Bartoli bartoli@cs Science 3.4
53688 Chang chang@eecs Eng 3.2
53650 Chang chang@math Science 3.8
sid cid grade 53666 Topology112 C 53666 Reggae203 B 53650 Topology112 A 53668 History105 B 421B: Database Systems - The Relational Model 18
Enforcing Referential Integrity
An
Enrolled
tuple with a sid is inserted such that no tuple with this sid exists in
Students
A
Students
Disallow insertion tuple is deleted Delete all
Enrolled
tuples that refer to it Disallow the deletion of a
Students
tuple to which
Enrolled
tuples point Set sid in
Enrolled
tuples that refer to it to “ (in SQL set sid in
Enrolled default sid”
tuples that refer to it to NULL value) The primary key of a
Students
tuple is changed Update the sid of all
Enrolled
value Further options similar to delete tuples that refer to the original 421B: Database Systems - The Relational Model 19
Referential Integrity in SQL/92
SQL standard supports all 4 options on deletes and updates Default is
NO ACTION
delete/update is rejected
CASCADE
also delete/update all tuples that refer to the deleted/updated tuple
SET NULL / SET DEFAULT
Set foreign key value of referencing tuple to NULL / given default
CREATE TABLE Enrolled (sid CHAR(20), cid CHAR(20), grade CHAR(2), PRIMARY KEY (sid,cid) FOREIGN KEY (sid) REFERENCES Students ON DELETE CASCADE ON UPDATE SET NULL)
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Where do ICs come from?
ICs are based on the semantics of the real-world enterprise that is being described in the database relations We can check a database instance to see if an IC is violated, but we can NEVER infer that an IC is true by looking at an instance An IC is a statement about all possible instances For example, we might think that the student name is a key because in a given instance there do not exist two tuples with the same name; but it might happen in the future.
Key and foreign key ICs are the most common; more general ICs supported, too. (Discussed later in the course) 421B: Database Systems - The Relational Model 21
Logical Design: ER to Relational
Entity sets to tables
eid name salary Employees Departments did dname budget
Employees(eid, name, salary) CREATE TABLE Employees (eid CHAR(11), name VARCHAR(20), salary REAL, PRIMARY KEY (eid))
Departments(did, dname, budget) CREATE TABLE Departments (did INTEGER, dname CHAR(20), budget REAL, PRIMARY KEY (did))
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Many-to-many Relationship Sets
Map relationship set to table. Attributes of the table Keys for each participating entity set (as foreign keys) This set of attributes forms the key for the relation All descriptive attributes
since eid name Employees salary Works_in Departments did dname budget
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Works_in(eid, did, since) CREATE TABLE Works_In (eid CHAR(11), did INTEGER, since DATE, PRIMARY KEY (eid,did), FOREIGN KEY (eid) REFERENCES Employees, FOREIGN KEY (did) REFERENCES Departments )
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Relationships Sets with Key Constraints
Alternative 1: map relationship set to table Many-one from entity set E1 to entity set E2: key of E1 i.e., key of entity-set with the key constraint is the key for the new relationship table (
did
is now the key) One-one: key of either entity set Separate tables for entity sets (
Employees
and
Departments
)
eid name Employees salary Manages Departments since did dname budget
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Manages(eid, did, since) CREATE TABLE Manages (eid CHAR(11), did INTEGER, since DATE,
PRIMARY KEY (did),
FOREIGN KEY (eid) REFERENCES Employees, FOREIGN KEY (did) REFERENCES Departments )
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Alternative II: include relationship set in table of the entity set with the key constraint Possible because there is at most one relationship per entity Not useful if many entities do not have a relationship (wasted space, many not filled values)
eid name salary Employees Manages Departments since did dname budget
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CREATE TABLE DepartmentsM (did INTEGER, dname CHAR(20), budget REAL,
eidmgr CHAR(11),
since DATE, PRIMARY KEY (did),
FOREIGN KEY (eidmgr)
REFERENCES EMPLOYEES(eid))
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Include relationship set in table of the entity set with the key constraint and the participation constraint We can capture participation constraints involving one entity set in a binary relationship if it also has a key constraint, but little else (at least within the table definitions)
eid name salary
DepartmentsM(did, dname, budget, eidmgr, since) Employees Manages Departments since did dname budget
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CREATE TABLE DepartmentsM (did INTEGER, dname CHAR(20), budget REAL, eidmgr CHAR(11) NOT NULL, since DATE, PRIMARY KEY (did), FOREIGN KEY (eidmgr)
Renaming
In the case the keys of the participating entity sets have the same names we must rename attributes accordingly
name
Reports_To(super-eid, sub-eid) eid salary Employees
supervisor subordinate
Reports_To CREATE TABLE Reports_To (supervisor_eid CHAR(11), subordinate_eid CHAR(11), PRIMARY KEY (supervisor_eid, subordinate_eid), FOREIGN KEY (supervisor_eid) REFERENCES Employees(eid), FOREIGN KEY (subordinate_eid) REFERENCES Employees(eid))
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Translating Weak Entity Sets
Weak entity set and identifying relationship set are translated into a single table When the owner entity is deleted, all owned weak entities must also be deleted
eid name salary
Dependants_Policy(pname, dob, cost, eid) Employees Policy Dependants pname cost dateofbirth CREATE TABLE Dependants_Policy (pname CHAR(20), dob DATE, cost REAL, eid CHAR(11), PRIMARY KEY (pname,eid), FOREIGN KEY (eid) REFERENCES Employees, ON DELETE CASCADE)
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Translating ISA Hierarchies
General Approach: distribute information among relations Relation of superclass stores the general attributes and defines key Relations of subclasses have key of superclass and addit. attributes sub-relation must be deleted
Employees(eid, name, salary) Contract_Emps(contract_id,eid)
eid name
salary CREATE TABLE Employees (eid CHAR(20), name CHAR(20),salary REAL, PRIMARY KEY (ssn))
hours_worked hourly_wages Employees Hourly_Emps ISA Contract_id Contract_Emps
CREATE TABLE Contract_Emps (contract_id INTEGER, eid CHAR(11), PRIMARY KEY (eid), FOREIGN KEY (eid) REFERENCES Employees, ON DELETE CASCADE)
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Translating ISA Hierarchies (contd.)
Object-oriented approach: Sub-classes have all attributes; Pro/Contra: + A query asking for all hourly employees only has to go to one relation (in general approach it has to read two relations) - Query on general attributes of all employees has to read all three tables - If an entity is both Hourly_emps and Contract_emps, name and salary are stored twice => undesired redundancy if an entity is in a sub-class it does not appear in the super-class relation;
Employees(eid, name, salary) Hourly_Emps(eid,name,salary, hourly_wages,hours_worked) Contract_Emps(eid, name, salary,contract_id) CREATE TABLE Employees (eid CHAR(20) PRIMARY KEY, name CHAR(20),salary REAL) CREATE TABLE Hourly_Emps (eid CHAR(20) PRIMARY KEY, name CHAR(20),salary REAL, hourly_wages REAL, hours_worked REAL) CREATE TABLE Contract_Emps (eid CHAR(20) PRIMARY KEY, name CHAR(20),salary REAL, contract_id INTEGER)
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Translating ISA Hierarchies (contd.)
Last Alternative: one big relation Create only one relation for the root entity set with all attributes found anywhere in its network of subclasses. Put NULL in attributes not relevant to a given entity
Employees(eid,name,salary, hourly_wages,hours_worked, CREATE TABLE Employees (eid CHAR(20), name CHAR(20), salary REAL, hourly_wages REAL, hourly_worked REAL, contract_id INTEGER, PRIMARY KEY (eid))
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Translating Aggregation
No key constraints Projects(pid,started_on,pbudget) Departments(did,dname,budget) Employees(eid,name,salary) Sponsors(pid,did,since) Monitors(pid,did,eid,until) Key constraint from Sponsors to Employees
name
Sponsors(pid,did,eid,since,until) No Monitors Key constraint from Projects(pid, started_on, pbudget, did, since) No Sponsors Monitors(pid, eid, until)
Employees eid salary Monitors until pid Started_on pbudget Projects since Sponsors did dname budget Departments
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Relational Model: Summary
A tabular representation of data Simple and intuitive, currently the most widely used model.
Integrity constraints can be specified based on application semantics (up to a certain degree). DBMS checks for violations Two important ICs : primary and foreign keys In addition, we always have domain constraints Powerful and natural query languages exist Rules to translate ER to relational model 421B: Database Systems - The Relational Model 33
Review: Binary vs. Ternary
Putting any constraints in upper picture: Key constraint on Policies (to guarantee that each policy only owned by one employee), would also mean that the policy can only cover one dependent
ssn name Employees pid
Constraints of lower picture: Each dependant determined by one policy Each policy is owned by one employee
ssn name lot Policies Employees covers lot purchaser pname dob Dependants cost pname dob Dependants beneficiary cost Policies pid
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Binary vs. Ternary
Key constraints allow us to combine Purchaser with Policies and Beneficiary with Dependants Participation constraints lead to NOT NULL constraints (or primary key in case of weak entity) What if policy is a weak entity?
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Policies(pid, cost, eid) Dependants(pname, dob, pid) CREATE TABLE Policies (pid INTEGER, cost REAL, eid CHAR(11) NOT NULL, PRIMARY KEY (pid), FOREIGN KEY (eid) REFERENCES Employees ON DELETE CASCADE) CREATE TABLE Dependants (pname CHAR(20), dob DATE, pid INTEGER, PRIMARY KEY (pname,pid), FOREIGN KEY (pid) REFERENCES Policies, ON DELETE CASCADE)
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