Heat Transfer By Conduction

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Transcript Heat Transfer By Conduction

Heat Transfer By Conduction

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K A U S A R A H M A D K U L L I Y Y A H O F P H A R M A C Y

http://staff.iiu.edu.my/akausar PHM3133 Dosage Design 1 2010/11

Contents

2  Practical heat transfer  Heat transfer medium  Heat transfer through multiple layers  Heat transfer at boundary PHM3133 Dosage Design 1 2010/11

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Practical Heat Transfer

3 You stir some hot soup with a silver spoon and notice that the spoon warms up. You stand watching a bonfire , but can’t get too close because of the heat.

It is hard for central air-conditioning in an old house to cool the attic. PHM3133 Dosage Design 1 2010/11

Heat transfer medium

 Water ………………….….  Steam…………………….

 Oil………………..………  Thermal liquid………..….

 Air…………………….

 Pebbles/Sand/Iron balls… 4 ……. water-bath …….

fluid energy mill …..oil-bath ……….????

…oven, spray drier …high temperature equipment PHM3133 Dosage Design 1 2010/11

Thermal conductivity, k

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k = “thermal conductivity”

good thermal conductors ---  high k

[k] = J/s-m-

C (

C or K)

good thermal insulators … low k Exercise What is k for vacuum? Polystyrene cup?

PHM3133 Dosage Design 1 2010/11

Material Copper Graphite Glass wool

Values of k (J/s-m-K)

6 Uses Temperature/ K 373 (100  C) 323 (50  C) 373 k 379 138 0.062

?

?

Piping insulation Water Air Steam 373 473 (200  C) 373 PHM3133 Dosage Design 1 2010/11 0.67

0.0311

0.0235

circulation fluid energy mill

Thermal conductivity of air

7 PHM3133 Dosage Design 1 2010/11 Temperature

Rate of heat transfer

8 H = Q/t = rate of heat transfer, Unit: J/s

T H Hot

H = k A ( T H T C )/ L Q/t = k A  T/  x L

T C Cold

Area A PHM3133 Dosage Design 1 2010/11

Find the rate of heat transfer

9 Outside: T C = 0  C Inside: T H = 25  C Q/t = k A  T/  x   T = T H -T C = 25  C Wood: thickness x = 0.02 m area A = 35 m 2 k = 0.080 J/s ● m ●  C Plug in….

Q/t = 0.080 x 35 x 25/0.02

H=3500 J/s H=3500 Watts PHM3133 Dosage Design 1 2010/11

Heat transfer through multiple layers

10 Δx = x1 + x2 + x3  T  Air is better than wool! And cheaper!! Therefore important for insulation.Hence

…layered clothing! Low k  For effective heat transfer, choose material with high thermal conductivity.

PHM3133 Dosage Design 1 2010/11

Examples: heat transfer through multiple layers 11  Heat transfer between fluids…..air heater  Heat transfer through a wall ….pot on stove  Heat transfer in pipes and tubes…. heat exchanger  Heat exchange between a fluid and a solid boundary……fluidised bed PHM3133 Dosage Design 1 2010/11

Find the rate of heat transfer in multiple layers 12 x 1 = 0.02 m A 1 = 35 m 2 k 1 = 0.080 J/s-m-C Assume H 1 = H 2  k 1 A(T 0 -T C )/x 1 = k 2 A(T H -T 0 )/x 2 solve for T 0 = temp at junction  T 0 =2.27 C

Outside: T C = 0

C Inside: T H = 25

C

then solve for H 1 or H 2  H=318 Watts x 2 = 0.075 m A 1 = 35 m 2 k 1 = 0.030 J/s-m-C PHM3133 Dosage Design 1 2010/11

Thermal Resistance

13 Q/t = k A  T/  x H/A =  T k/  x =  T/ R R =  x/k [Joules/s ● m 2 ], R is the thermal resistance R “adds” for multiple layers Q/tA =  T/ k  x

R

1 =  T/(R 1 +R 2 +R 3 +...)

= x

1

/k

1 etc PHM3133 Dosage Design 1 2010/11

Insulation

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Insulation for piping

is critical to ensure minimum heat loss  Typical insulators are  Glass wool/rock wool  Aluminum sheets PHM3133 Dosage Design 1 2010/11

Heat exchange between a fluid and a solid boundary 15  At the boundary, heat transfer is influenced by conduction and convection : H =

h

A(T 1 – T 1, wall ),

h

is the film coefficient T1, wall A PHM3133 Dosage Design 1 2010/11 T 1

Fluid

Film coefficient, h (J/m

2

-s-K)

16 h Water (heat-exchanger) 1700-11350 Gases 17-285 Organic solvents Oils 340-2840 57-680 …….why?

PHM3133 Dosage Design 1 2010/11

Overall heat transfer coefficient

17 Taking into account k and h, k, thermal conductivity and h,film coefficient Q =

U

AdT U is the overall heat transfer coefficient PHM3133 Dosage Design 1 2010/11

U values

Overall heat transfer coefficient 18 Convection Sea breeze….

1 Radiation Else, heat from sun produces roasted human……  Indirect i.e. through wall conduction House is our shelter… 2 20 Contactive mechanism i.e. gaseous phase heat carrier passes directly through the solids bed 200 PHM3133 Dosage Design 1 2010/11

Common heat transport fluids

19  from Perry’s Chemical Engineers’ Handbook 6th Ed.

Fluid Steam Water Oil Molten salts Silicon compounds Flue gas or air Temperature ( o F) Pressure (psig)

200-1100 300-400 30-600 290-1100 100-700

0-4500 90-230 0 0 0 30-2000 0-100

PHM3133 Dosage Design 1 2010/11

Heat transfer equipment: Fluidised bed dryer 20   Hence, drying of solids using fluidised bed technique is very popular!

http://www.pharmaceuticalonline.com/product.mvc/Fluid-Bed-Dryers 0002?VNETCOOKIE=NO PHM3133 Dosage Design 1 2010/11

Relationship between Energy and Temperature 21 PHM3133 Dosage Design 1 2010/11 Temperature (K)

References

22 Aulton, M. E. (Ed.) (1988). Pharmaceutics – The Science of Dosage Form Design. Churchill Livingstone.

PHM3133 Dosage Design 1 2010/11