Transcript chapter 4
Signal Conditioning Elements (SCE) 1. Voltage dividers Vo R2 Vs R1 R2 Example :Potentiometer circuit 7/24/2016 Measurement & Transducers 2 Deflection bridges Deflection bridges are used to convert the output of resistive, capacitive and inductive sensors into a voltage signal Amplifiers Amplifiers are necessary in order to amplify low-level signals, e.g. thermocouple or strain gauge bridge output voltages, to a level which enables them to be further processed Oscillators and resonators Thévenin equivalent circuit for a deflection bridge Bridge Parameters a. Range of output 1 1 Z3 Z4 1 1 Z Z2 I min Vmin Vmax 1 1 Z4 Z3 1 1 Z I max Z2 7/24/2016 V S V S Measurement & Transducers 5 b. Sensitivity S ΔVout ΔZ Z c.Maximum power dissipation VS2 Z1 ˆ w 2 Z1 Z 4 7/24/2016 Measurement & Transducers 6 d. Non linearity Vmax Vmax I - I min Videal I max I min I max I min E th Videal 100 N̂ Vmax 7/24/2016 Measurement & Transducers 7 Design of resistive deflection bridges Output voltage for resistive deflection bridge R1 = RI, and R2, R3 and R4 are fixed resistors Relationship between resistances in a balanced Wheatstone bridge Often we require VMIN = 0, i.e. the bridge to be balanced when I = IMIN; Output voltage for single-element strain gauge bridge Four-element strain gauge bridge strain-gage arrangements in a Wheatstone bridge Case 1. -utilizing a single active gage in position R1 - it is often employed for both static and dynamic strain-gage measurement if temperature compensation is not required. -The resistance R1 = Rg and the other three resistances are selected to maximize the circuit sensitivity while maintaining the balance condition R1R3 = R2R4. 7/24/2016 Measurement & Transducers 12 The sensitivity Ss of the strain-gage—Wheatstone bridge system is defined as the product of the sensitivity of the gage Sg and the sensitivity of the bridge circuit S. Thus, Rg Rg Vo S s S g Sc R R g g 7/24/2016 Vo Measurement & Transducers 13 -the dummy gage is inserted in arm R4 of the bridge instead of arm R2. -The active gage remains in arm R1 - fixed-value resistors are used in arms R2 and R3. - With this positioning of the dummy gage -the system sensitivity is the same as that given by case 1. - Temperature compensation is achieved in the same manner that was illustrated in Case 2, but without loss of circuit efficiency. - When a dummy gage is to be used to effect temperature compensation, arm R4 of the bridge is the preferred location for the dummy gage. 7/24/2016 Measurement & Transducers 14 Case 4. - Four active gages are used in this Wheatstone bridge arrangement: - - it is used to measure transverse and axial strain 7/24/2016 Measurement & Transducers 15 Load Cell : Force measurement Link-type Load Cell 7/24/2016 Measurement & Transducers 16 Beam-type load cells 7/24/2016 Measurement & Transducers 17 Ring-type load cell. 7/24/2016 Measurement & Transducers 18 Output voltage for single-element Thermoresistor bridge Output voltage for double -elements Thermoresistor bridge Output voltage for cantilever and torque elements Output voltage for Pillar load cell Design of reactive deflection bridges Bridge for capacitive level sensor Output voltage for capacitance level bridge Thus in order to get :ETh = 0 at minimum level hMIN, we require C0 = ChMIN(R3 /R2), giving: if R3 /R2 is made large compared with 1, this approximates to the linear form: Output voltage for capacitance push-pull bridge This gives: Output voltage for inductive push-pull bridge This gives: Amplifiers Why do we need Amplifiers? Signal Amplification (I,V,,P) Signal processing Inverting Buffering Filtering Compression Integration Differentiation Converters * (How) Ideal operational amplifier characteristics typical operational amplifier characteristics (Ideal vs. OPA27) Transfer characteristics of Op Amp Inverting amplifier The output voltage of inverting Amplifier Since V+ = V− = 0 Also giving Non-inverting amplifier The output voltage of Non-inverting amplifier Since i+ = 0, V+ = VIN Also since V+ = V− we have , RF and R1 form a potential divider, we have Voltage follower. Differential amplifier Strain gauge bridge connected to differential amplifier Instrumentation amplifier • High input impedance • High common mode rejection ratio • Low input offset voltage • Low temperature coefficient of offset voltage. Voltage adder. Parameters influence the d.c. performance of the amplifier Input offset voltage VOS The existence of input offset voltage VOS means that VOUT is unequal to zero when both V− and V+ = 0 volts, i.e. Where AOL -D.C. open-loop gain Some operational amplifiers have facilities for adjusting VOS to zero, i.e. for obtaining VOUT = 0 when V+ = V− = 0. The effect of VOS on inverting amplifier Appropriate temperature coefficient VOS is dependent on the temperature TE °C of the amplifier environment Example If VOS is set to zero at TE = 15 °C; then if TE subsequently increases to 25 °C, the resulting input offset voltage is γ (25 − 15), i.e. ≈ 6 μV, which causes a change of approximately 0.6 × 106 μV, i.e. 0.6 V in the output of the open-loop operational amplifier Common mode voltage Common mode voltage affects on Vout where ACM is the common mode gain Common Mode Rejection Ratio (CMRR) The equivalent circuit for an open-loop amplifier a.c. performance of a practical operational amplifier Gain–frequency relation for open-loop amplifier where f B = 1/2πτ is the −3 dB cut-off frequency Typical gain–frequency characteristics for operational amplifier Instrumentation amplifiers • High input impedance • High common mode rejection ratio • Low input offset voltage • Low temperature coefficient of offset voltage. Oscillators and resonators Oscillators Inductive Oscillators Capacitive Oscillators resonator Mathematical model of resonator Examples of resonators Vibrating plate element Vibrating tube element. Other types of Op. Amps Example Find vo for the following circuit. It follows that and 7/24/2016 Measurement & Transducers 56 Therefore From KVL, we have and 7/24/2016 Measurement & Transducers 57 Example. Find vo for the following circuit. With the noninverting input connected to ground, we have vp = 0 = vn. From KVL and it follows that 7/24/2016 Measurement & Transducers 58 Since no current flows into the op amp, iC = iR.With and we have 7/24/2016 Measurement & Transducers 59 Logarithmic amplifiers - When a sensor’s output dynamic is of a high amplitude (10 mV to 10 V, for example), it can be useful to compress the signal by using a logarithmic amplifier. - After amplification and digitization, the signal can be easily transmitted across a transmission line. At reception, it is enough to carry out the reverse operation to restore the measurement signal. This principle allows us to lower noise sensitivity. - Logarithmic amplifiers also help us “linearize” sensors, carry out multiplications, divisions, elevations in the square, and extractions of the root squared. To construct this type of amplifier , we use the feature of a P-N junction with an equation (Ebres-Moll equation) in the following form: where q is the electron charge k the Boltzmann’s constant T is the absolute temperature U is the direct voltage and i0 is the flow of reverse current 7/24/2016 Measurement & Transducers 60 Schemata of logarithmic amplifier principle 7/24/2016 Measurement & Transducers 61