Transcript ICECHART.pptx

#5 of 11-6 LIMITING REAGENT SET
INTRODUCTION OF ICE BOX STOICHIOMETRY SOLUTION TABLES.
ICE BOX SOLUTION TABLES:
•ARE THE MOST EFFICIENT TO SOLVE FOR EVERYTHING
•WHAT IS EVERYTHING?
•REAGENTS LEFT OVER (UNCONSUMED)
•PRODUCT YIELD
•REACTANTS CONSUMED TO 0.0 MOLES.
5) Sulfur and oxygen react in a combination reaction to produce sulfur
trioxide, an environmental 5)
pollutant:
2S (s) + 3O2 (g)  2SO3 (g)
In a particular experiment, the reaction of 1.0 g S with 1.0 g O2 produced
0.80 g of SO3. Calculate the amount of excess reagent that remains not
having reacted (in excess).
Defining X
X is defined by the LIMMITING REAGENT. Divide the moles of the limiting reagent
by the coefficient of the balanced reaction. In this example oxygen is the limiting
reagent, therefore
2S
3 X = 0.03125 mol
X = 0.01041666 mole
+
3O2

2SO3
0.031191 mol
0.03125 mol
0.0
-2 X
-3 X
+2 X
0.031191 mol -2x
0.0
2 (.01041666 )
= 0.020833
0.031191 mol -2x : 0.031191 mol - 2 (0.01041666 mol)
0.031191 mol -(0.020833) = 01041666 mol S remains