Transcript STOIC-3.74AP.ppt

3.74
1.50 g. NH3
= 0.08823 mol NH3
( )
1 mol
17.00g
STEP 1-Convert to moles
2.75 g. O2
(
)
1 mol
32.00g
= 0.08595 mol O2
STEP 1.5 assess limiting reagent
THEO
ACTUAL
NH3
O2
=
4
5
=
0.08823
0.08595
0.80
=
1.02
The actual ratio is
GREATER than the
theoretical, therefore
the reactant on top is
in excess, the one on
the bottom is limiting,
oxygen limits!
4 NH3
0.08823
-4X
0.08823 4(0.01719)
+ 5 O2
0.08595(lim)
-5X
0
4 NO
6H O
0
0
+ TO THE2
X IS CALIBRATED
LIMITING REAGENT, OXYGEN.
5 X = 0.08595 MOL
+4X
+6X
LET X = 0.01719 MOL
4 (0.01719)
6 (0.01719)
0.01947 MOL
0.06876 MOL
0.10314 MOL
0.330 g.
REMAIN
2.06 g.
THEO YEILD
1.85 g.
THEO YEILD
(( 1.50-0.33)+2.75=3.91
REACTED REACTANTS
=
3.91 g.
PRODUCTS