650-VOLTAIC CELL PPT

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Transcript 650-VOLTAIC CELL PPT

VOLTAIC
CELL
VOLTMETER
SLIDE ONE
OVERVIEW
ANIMATION
SO4
SO4
2-
2-
Na+
Na+
SO42Na+ Na+
2e-
-
Fe
Fe
2eFe2+
SO42-
Fe0(s)  2e- + Fe2+
ANODE (ANOX)
Pb2+ Pb
Na+ Na+
Pb
Pb2+
+
+
+
Pb
2e- + Pb2+  Pb0(s)
CATHODE (REDCAT)
VOLTAIC
AS THE Fe(S) IS
CELL
OXIDIZED, IT
DISSOLVES AND
SLIDE TWO
THE ANODE
LOSES MASS AND
THE ANODE
2e- ARE
AS THE Fe(S) IS
OXIDIZED, IT
DISSOLVES AND THE
VOLTMETER
ANODE LOSES MASS,
THE IRON(II) IONS
WILL MAKE THE
ANODE SOLUTION
POSITIVE,
THEREFORE THE
+
Na
NEGATIVE SALT
SO42- Na+
2SO
4
SO42Na+ Na+BRIDGE ION MOVES IN
TO NEGATE THE +
CHARGE
RELEASED
2eFe
Fe
Fe2+
SO4
Fe0(s)  2e- + Fe2+
ANODE (ANOX)
2-
NSBTA
Negative salt bridge to
anode
Pb2+
Never sell booze to
adolescents!
Pb
Pb
2e- + Pb2+  Pb0(s)
CATHODE (REDCAT)
VOLTAIC
CELL
VOLTMETER
SLIDE
THREE
e- FLOW
2eFe
Fe
Fe0(s)  2e- +
ELECTRONS ALWAYS
MOVE FROM Na
ANODE
+
2SOCATHODE
TO
4
Na+
SO42(FATCAT). THE
Na+ Na+
ELECTRONS BUILD UP
IN THE ANODE
Fe2+ MAKING IT NEGATIVE,
TRAVEL TO THE
SO42-CATHODE WHERE A
METAL ION GAINS
Pb2+
THEM IN REDUCTION,
THE CATHODE IS
POSITIVE.
VOLTMETER ALWAYS
Fe2+ POINTS TO CATHODE, 2e +
ANODE (ANOX)
2ePb
Pb
Pb2+  Pb0(s)
CATHODE (REDCAT)
VOLTAIC
CELL
VOLTMETER
SLIDE
FOUR
THE
CATHODE
THE POSITIVE SALT ION
MIGRATES TO THE
CATHODE TO REPLACE +
CHARGE LOST AS Pb(II)
Na+
2SO4 Na+
ARE REDUCED TO2-Pb
SO42SOLID.SO4
Na+ Na+
2eFe
Fe
2eFe2+
SO42AS ELECTRONS ARE
GAINED BY Pb(II) IONS
FROM THE CATHODE,
THE IONS BECOME
REDUCED INTO Pb(S)
Fe0(s)  2e- + Fe2+
ANODE (ANOX)
Pb2+ Pb
Na+ Na+
Pb
Pb2+
Pb
THE SOLID
LEAD
BONDS
(METALLIC
BONDING)
THE
CATHODE
WHICH
GAINS
MASS. THIS
IS
ELECTROPL
ATING.
2e- + Pb2+  Pb0(s)
CATHODE (REDCAT)