Working with percentages Free-Standing Mathematics Activity © Nuffield Foundation 2012
Download ReportTranscript Working with percentages Free-Standing Mathematics Activity © Nuffield Foundation 2012
Free-Standing Mathematics Activity Working with percentages © Nuffield Foundation 2012 © Nuffield Foundation 2012 A Compound interest Amount invested = £3000 Interest rate = 4% 1 Step-by-step method Interest at end of Year 1 = 4% of £3000 Think about Is the answer the same if you divide by 100, then multiply by 4? = 0.04 x £3000 = £120 Amount at end of Year 1 = £3120 Interest at end of Year 2 = 4% of £3120 = 0.04 x £3120 = £124.80 Amount at end of Year 2 = £3120 + £124.80 = £3244.80 and so on © Nuffield Foundation 2012 A Compound interest Amount invested = £3000 Interest rate = 4% 2 Repeating calculations using a multiplier Amount at end of Year 1 = 104% of £3000 = 1.04 x £3000 = £3120 Amount at end of Year 2 = 1.04 x £3120 = £3244.80 and so on Try repeated calculations like this one on your calculator © Nuffield Foundation 2012 A Compound interest £3000 invested at 4% interest Repeated calculations How much is in the account after 5 years? End of year n Amount £ A 0 3000.00 1 3120.00 2 3244.80 3 3374.59 4 3509.58 5 3649.96 © Nuffield Foundation 2012 A Compound interest Amount invested = £3000 Interest rate = 4% 3 Using indices Amount at end of Year n = 1.04n x £3000 Amount at end of Year 2 = 1.042 x £3000 = £3244.80 Amount at end of Year 5 = 1.045 x £3000 = £3649.96 Try this A An account gives 3% interest per annum. £5000 is invested. How much will be in the account after 6 years? Use each method. Think about What are the advantages and disadvantages of each method? © Nuffield Foundation 2012 B Depreciation A new car costs £16 000. Its value falls by 15% per year What will it be worth when it is 5 years old? In this case the multiplier is 0.85 Age of car (n years) Value (£ A) 0 16 000 1 13 600 2 11 560 3 9826 4 8352 5 7099 © Nuffield Foundation 2012 What will the car be worth when it is 20 years old? Think about What assumption is being made? Is it realistic? B Falling sales Try this B A company’s sales of a product are falling by 6% per annum. They sold 45 000 this year. Estimate the annual sales 6 years from now. In this case the multiplier is 0.94 Formula for annual sales n years from now = 0.94n x 45 000 Estimate of annual sales 6 years from now = 0.946 x 45 000 about 31 000 Check this by repeated calculations. © Nuffield Foundation 2012 C Combining percentage changes A shareholder owns 2000 shares. She expects to get 3% more shares then plans to sell 25% of her shareholding. How many shares will she have after these transactions? Number after receiving 3% extra = 103% of 2000 = 1.03 x 2000 = 2060 Number after selling 25% = 75% of 2060 = 0.75 x 2060 = 1545 What % is this of her original shareholding? 1545 100 = 77.25% or 1.03 x 0.75 = 0.7725 2000 © Nuffield Foundation 2012 C Combining percentage changes Try this C A shop marks up the goods it sells by 30% In a sale it reduces its normal prices by 25% What is the overall % profit or loss on goods sold in the sale? Sale price = 75% of normal price = 75% of 130% of cost price = 0.75 x 1.3 x cost price = 0.975 of cost price The shop makes a 2.5% loss on goods it sells in the sale. © Nuffield Foundation 2012 D Reversing percentage changes The price of a train fare increased by 2.5% recently. It now costs £66.42 How much did it cost before the rise in price? 1.025 x previous price = £66.42 Previous price = £66.42 1.025 Previous price © Nuffield Foundation 2012 = £64.80 D Reversing percentage changes Try this D After a 12.5% discount, insurance costs £25.90 What was the cost before the discount? 0.875 x full price = £25.90 Full price = £25.90 0.875 Full price = £29.60 © Nuffield Foundation 2012 Reflect on your work • Which of the methods do you think is most efficient? • How can a graphic calculator or spreadsheet help? © Nuffield Foundation 2012