Document 7243845

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Transcript Document 7243845

SWAPS

Swaps are a form of derivative instruments. Out of the variety of assets underlying swaps we will cover:

INTEREST RATES SWAPS, CURRENCY SWAPS, and COMMODITY SWAPS.

We will also see that a combination of hedging with futures and swapping the basis, leads to risk-free strategies.

1

SWAPS A SWAP is a contractual arrangement between two parties for an exchange of cash flows. The amounts of money involved are based on a

NOTIONAL AMOUNT OF

CAPITAL Notional as in conceptual

2

It follows that in a swap we have: 1.

Two parties 2.

A notional amount 3.

Cash flows 4.

A payment schedule 5.

An agreement as to how to resolve problems

3

1. Two parties: The two parties in a swap are sometimes labeled as

party

and

counterparty.

They may arrange the swap directly or indirectly.

In the latter case, there are two swaps, each between one of the parties and the intermediary.

4

2. The NOTIONAL AMOUNT is the basis for the determination of the cash flows. It is almost never exchanged by the parties.

For example:

$100,000,000 £50,000,000 50,000 barrels of crude oil

5

3. The cash flows may be of two types: a fixed cash flow or a floating cash flow.

Fixed interest rate vs.

Floating interest rate Fixed price Vs.

Market price

6

3. The cash flows The interest rates, fixed or floating, multiply the notional amount in order to determine the cash flows.

Ex: ($10M)(.07)=$700,000; Fixed.

($10M)(L

t

+30bps); Floating.

The price, fixed or market, multiply the commodity notional amount in order to determine the cash flows.

Ex: (100,000bbls)($24,75) =

$2,475,000; Fixed.

(100,000bbls)(S

t

); Floating.

7

4. The payments

are always net.

The agreement determines the cash flows timing as annual, semiannual or monthly, etc. Every payment is the net of the two cash flows

8

5. How to resolve problems: Swaps are Over The Counter (OTC) agreements. Therefore, the two parties always face

credit risk operational risk, etc.

Moreover, liquidity issues such as getting out of the agreement, default possiblilities, selling one side of the contract, etc., are frequently encountered problems.

9

The

goals

of entering a swap are: 1.

Cost saving.

2.

Changing the nature of cash flow each party receives or pays from fixed to floating and vice versa.

10

1. INTEREST RATE SWAPS

Example:

Plain Vanilla

Fixed for Floating rates swap

A swap is to begin in two weeks.

Party A will pay a fixed rate 7.19% per annum on a semi-annual basis, and will receive the floating rate: six-month LIBOR + 30bps from from Party B. The notional principal is $35million. The swap is for five years.

Two weeks later, the six-month LIBOR rate is 6.45% per annum. 11

The fixed rate in a swap is usually quoted on a

semi-annual bond equivalent yield

basis. Therefore, the amount that is paid every six months is:  

Notional amount

   

Days Period in

  

$35,000,00 0 (182) 365

$1,254,802 .74.

7 .

19 100 Fixed Rate 100

This calculation is based on the assumption that the payment is every 182 days. 12

The floating side is quoted as a money market yield basis. Therefore, the first payment is:  

Notional amount

   

Days Period in

 

Floating 100

$35,000,00 0 (182) 360

$1,194,375 .

( 6 .

45

.30) 100 Rate

Other future payments will be determined every 6 months by the six-month LIBOR at that time.

13

Party

A

FIXED 7.19% FLOATING LIBOR 30 bps

Party

B

As in any SWAP, the payments are

netted

. In this case, the first payment is: Party A pays Party B the net difference: $1,254,802.74 - $1,194,375.00

= $60,427.74.

14

This example illustrates five points: 1. In interest rate swaps, payments are netted. In the example, Party A sent Party B a payment for the net amount.

2. In an interest rate swap, principal is not exchanged. This is why the term “notional principal” is used.

3. Party A is exposed to the risk that Party B might default. Conversely, Party B is exposed to the risk of Party A defaulting. If one party defaults, the swap usually terminates.

15

4. On the fixed payment side, a 365 day year is used, while on the floating payment side, a 360-day year is used. The number of days in the year is one of the issues specified in the swap contract.

5. Future payments are not known in advance, because they depend on future realizations of the Six month LIBOR.

Estimates of future LIBOR values are obtained from LIBOR yield curves which are based on Euro Strip of Euro dollar futures strips.

16

Example: A FIXED FOR FLOATING SWAP Two firms need financing for projects and are facing the following interest rates: PARTY F1 : F2 : FIXED RATE FLOATING RATE 15% 12% LIBOR + 2% LIBOR + 1%

F2 HAS

ABSOLUTE ADVANTAGE

in both markets, but F2 has

RELATIVE ADVANTAGE

only in the market for fixed rates. WHY?

The difference between what F1 pays more than F2 in floating rates, (1%), is less than the difference between what F1 pays more than F2 in fixed rates, (3%). 17

Now, suppose that the firms decide to enter a FIXED for FLOATING swap based on the notional of

$10.000.000

. The payments: Annual payments to be made on the first business day in March for the next five years. 18

The SWAP always begins with each party borrowing capital in the market in which it has a RELATIVE ADVANTAGE.

Thus, F1 borrows S $10,000,000 in the market for floating rates, I.e., for LIBOR + 2% for 5 years.

F2 borrows $10,000,000 in the market for fixed rates, I.e., for 12%. NOW THE TWO PARTIES EXCHANGE THE TYPE OF CASH FLOWS BY ENTERING THE SWAP FOR FIVE YEARS 19

A fundamental implicit assumption:

The swap will take place only if

F1 wishes to borrow capital for a FIXED RATE, While F2 wishes to borrow capital for a FLOATING RATE.

That is, both firms want to change the nature of their payments.

20

Two ways to negotiate the contract: 1. Direct negotiations between the two parties. 2. Indirect negotiations between the two parties. In this case each party separately negotiates with an intermediary party.

21

Usually, The intermediary is a financial institution – a swap dealer - who possesses a portfolio of swaps. The intermediary charges both parties commission for its services and also as a compensation for the risk it assumes by entering the two swaps

22

FIXED FOR FLOATING SWAP 1. A DIRECT SWAP: FIRM F1 FIXED RATE FLOATING RATE 15% LIBOR + 2% F2 12% LIBOR + 1% notional: $10M LIBOR 12% LIBOR+2% F2 F1 12% The result of the swap: F1 pays fixed 14%, better than 15%.

F2 pays floating LIBOR, better than LIBOR + 1%

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2. AN INDIRECT SWAP FIRM FIXED RATE FLOATING RATE F1 15% LIBOR + 2% F2 12% LIBOR + 1% The notional amount: $10M 12% F2 L+25bps I 12% L 12,25% F1 L + 2% F1 pays 14,25% fixed: Better than 15%. F2 pays L+25bps : Better than L+1%. The Intermediary gains 50 bps = $50,000.

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Notice that the two swaps presented above are two

possible

contractual agreements. The direct, as well as the indirect swaps, may end up differently, depending on the negotiation power of the parties involved. Nowadays, it is very probable for intermediaries to be happy with 10 basis points. In the present example, another possible swap arrangement is:

12% F2 L+5bp L I 12% 12%+5bp F1 L+2%

Clearly, there exist many other possible swaps between the two firms in this example.

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Warehousing

In practice, a swap dealer intermediating (making a market in) swaps may not be able to find an immediate off-setting swap. Most dealers will warehouse the swap and use interest rate derivatives to hedge their risk exposure until they can find an off-setting swap. In practice, it is not always possible to find a second swap with the same maturity and notional principal as the first swap, implying that the institution making a market in swaps has a residual exposure. The relatively narrow bid/ask spread in the interest rate swap market implies that to make a profit, effective interest rate risk management is essential.

26

EXAMPLE: A RISK MANAGEMENT SWAP MARKET BONDS LOAN FL 1 10% BANK LOAN 12% FL 2 FL 1 = Floating rate 1.

FL 2 = Floating rate 2.

COUNTERPARTY A FIRM A BORROWS AT A FIXED RATE FOR 5 YEARS

27

THE BANK’S CASH FLOW: 12% - FLOATING 1 + FLOATING 2 – 10% = 2% + SPREAD SPREAD = FLOATING 2 - FLOATING 1 RESULTS THE BANK EXCHANGES THE RISK ASSOCIATED WITH THE DIFFERENCE BETWEEN FLOATING 1 and 12% WITH THE RISK ASSOCIATED WITH THE SPREAD = FLOATING 2 - FLOATING 1 .

The bank may decide to swap the SPREAD for fixed, risk-free cash flows. 28

EXAMPLE: A RISK MANAGEMENT SWAP MARKET SHORT TERM BOND FL 1 10% BANK COUNETRPARTY a FL 2 FL 2 FL 1 12% COUNTERPARTY b FIRM A

29

THE BANK’S CASH FLOW: 12% - FL 1 + FL 2 – 10% + (FL 1 - FL 2 ) = 2% RESULTS THE BANK EXCHANGES THE RISK ASSOCIATED WITH THE SPREAD = FL 2 - FL 1 WITH A FIXED RATE OF 2%. THIS RATE IS A RISK-FREE RATE!

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VALUATION OF SWAPS

The swap coupons (payments) for short-dated fixed-for-floating interest rate swaps are routinely priced off the Eurodollar futures strip (Euro strip). This pricing method works provided that: (1) Eurodollar futures exist.

(2) The futures are liquid.

As of June 1992, three-month Eurodollar futures are traded in quarterly cycles - March, June, September, and December - with delivery (final settlement) dates as far forward as five years. Most times, however, they are only liquid out to about four years, thereby somewhat limiting the use of this method.

31

The successive three-month Eurodollar While identical contracts trade on different futures exchanges, the International Monetary Market (IMM) is the most widely used. It is worth mentioning that the Eurodollar futures are the most heavily traded futures anywhere in the world. This is partly as a consequence of swap dealers' transactions in these markets. Swap dealers synthesize short-dated swaps to hedge unmatched swap books and/or to arbitrage between real and synthetic swaps.

Euro strip

is a series of futures contracts.

32

Eurodollar futures provide a way to do that. The prices of these futures imply

unbiased estimates

of three-month LIBOR expected to prevail at various points in the future. Thus, they are conveniently used as estimated rates for the floating cash flows of the swap. The swap fixed coupon that equates the present value of the fixed leg with the present value of the floating leg based on these unbiased estimates of future values of LIBOR is then the

dealer’s

mid rate.

33

The estimation of a “fair” mid rate is complicated a bit by the facts that: (1) The convention is to quote swap coupons for generic swaps on a semiannual bond basis, and (2) The floating leg, if pegged to LIBOR, is usually quoted on a money market basis. Note that on very short-dated swaps the swap coupon is often quoted on a money market basis. For consistency, however, we assume throughout that the swap coupon is quoted on a bond basis.

34

The procedure by which the dealer would obtain an unbiased mid rate for pricing the swap coupon involves three steps. The first step: Use the implied three-month LIBOR rates from the Euro strip to obtain the

implied

annual effective LIBOR for

the full tenor

of the swap.

The second step: Convert this full tenor LIBOR to an effective rate quoted on an annual bond basis. The third step: Restate this effective bond basis rate on the actual payment frequency of the swap.

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NOTATIONS:

Let the swap have a tenor of m months (m/12 years). The swap is to be priced off three-month Eurodollar futures, thus, pricing requires n sequential futures series; n equivalently, m = 3n.

=

m/3 or, Step 1: Use the futures Euro strip to Calculate the implied effective annual LIBOR for the full tenor of the swap:

r

0,3n    t n   1

[1

(r

3(t 1),3(t)

N(t) 360 )]

  k 

1, where : k

 

360 N(t) ; N(t) denotes the actual number of days covered by the t th Eurodolla r futures.

36

N(t) is the total number of days covered by the swap, which is equal to the sum of the actual number of days in the succession of Eurodollar futures.

Step 2: Convert the full-tenor LIBOR, which is quoted on a money market basis, to its fixed-rate equivalent FRE(0,3n), which is stated as an effective annual rate on an annual bond basis. This simply reflects the different number of days underlying bond basis and money market basis:

FRE(0,3n)

r

0,3n

365 360 .

37

Step 3: Restate the fixed-rate on the same payment frequency as the floating leg of the swap. The result is the swap

coupon, SC.

Let f denote the payment frequency, then the coupon swap is given by: 1

SC

{[1

FRE(0,3n)]

f

1}(f), which, upon substituti on of FRE(0,3n), can be rewritten as : SC

{[1

r

0,3n

365 ]

f

360

1 

1}(f).

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Example:

For illustration purposes let us observe Eurodollar futures settlement prices on April 24, 2001.

Eurodollar Futures Settlement Prices April 24,2001.

CONTRACT PRICE LIBOR FORWARD DAYS

JUN01 95.88

4.12

0,3 92 SEP91 DEC91 MAR92 95.94

95.69

95.49

4.06

4.31

4.51

3,6 6,9 9,12 91 90 92 JUN92 SEP92 DEC92 MAR93 JUN93 SEP93 DEC93 MAR94 JUN94 95.18

94.92

94.64

94.52

94.36

94.26

94.11

94.10

94.02

4.82

5.08

5.36

5.48

5.64

5.74

5.89

5.90

5.98

12,15 15,18 18,21 21,24 24,27 27,30 30,33 33,36 36,39 SEP94 93.95

6.05

39,42 92 91 91 92 92 91 90 92 92 91 39

These contracts imply the three-month LIBOR (3-M LIBOR) rates expected to prevail at the time of the Eurodollar futures contracts’ final settlement, which is the third Wednesday of the contract month. By convention, the implied rate for three-month LIBOR is found by deducting the price of the contract from 100. Three-month LIBOR for JUN 91 is a spot rate, but all the others are forward rates implied by the Eurodollar futures price. Thus, the contracts imply the 3-M LIBOR expected to prevail three months forward, (3,6) the 3-M LIBOR expected to prevail six months forward, (6,9), and so on. The first number indicates the month of commencement (i.e., the month that the underlying Eurodollar deposit is lent) and the second number indicates the month of maturity (i.e., the month that the underlying Eurodollar deposit is repaid). Both dates are measured in months forward. 40

In summary, the spot 3-M LIBOR is denoted r zero.

0,3 , the corresponding forward rates are denoted r from a Euro strip.

3,6 , r 6,9 , and so on. Under the FORWARD column, the first month represents the starting month and the second month represents the ending month, both referenced from the current month, JUNE, which is treated as month Eurodollar futures contracts assume a deposit of 91 days even though any actual three-month period may have as few as 90 days and as many as 92 days. For purposes of pricing swaps, the actual number of days in a three-month period is used in lieu of the 91 days assumed by the futures. This may introduce a very small discrepancy between the performance of a real swap and the performance of a synthetic swap created 41

Suppose that we want to price a one-

year fixed-for-floating interest rate

swap against 3-M LIBOR. The fixed rate will be paid quarterly and, therefore, is quoted quarterly on bond basis. We need to find the fixed rate that has the same present value (in an expected value sense) as four successive 3-M LIBOR payments.

r

Step 1: The one-year implied LIBOR rate, based on k =360/365, m = 12, n = 4 and f=4 is: 0,3n     t n   1

[1

(r

3(t 1),3(t)

N(t) 360 )]

   k 

1

      

(1 (1

 

.0412

.0431

92 360 )(1 90 360 )(1

 

.0406

.0451

91 360 ) 92 360 )

      360 365 

4.34%, on money market basis.

42 

1

Step 2

and

3:

SC

{[1

FRE(0,3n)]

1 f

1}(f), which, upon substituti on of FRE(0,3n), can be rewritten as : SC

{[1

r

0,3n

365 ]

f

360

1 

1}(f)

{[1

.

0 434 365 ]

4

360

1 

4.33% on a

1}(4) quarterly bond basis.

The swap’s coupon is the dealer mid rate. To this rate , the dealer will add several basis points.

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Client

4.33%+s FIXED

7.19

Swap dealer + 30

In this swap, four net payments will take place during the one year tenure of the swap depending the three-month LIBOR realizations.

This completes the example.

Next

, suppose that the swap is for semiannual payments against 6-month LIBOR.

The first two steps are the same as in the previous example. Step 3 is different because f = 2, instead of 4.

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1

SC

[1

(.0434

365 )

2 

1 )]( 360 SC

4.35%, on a semiannual 2 ); bond basis.

Client

4.35%+s FIXED

6-M LIBOR

FLOATING

Swap dealer

45

The procedure above allows a dealer to quote swaps having tenors out to the limit of the liquidity of Eurodollar futures on any payment frequency desired and to fully hedge those swaps in the Euro Strip.

The latter is accomplished by purchasing the components of the Euro Strip to hedge a dealer-pays-fixed-rate swap or, selling the components of the Euro Strip to hedge a dealer-pays-floating-rate swap.

Example

futures; n : Suppose that a dealer wants to price a three-year swap with a semiannual coupon when the floating leg is six-month LIBOR. Three years: m=36 months requiring 12 separate Eurodollar swap is 

=

12. Further, f = 2 and the actual number of days covered by the

N(t) = 1096.

Step 1: The implied LIBOR rate for the entire period of the swap: 46

r 0,36    t 12   1 [1  (r 3(t 1),3(t) 360 N(t) 360 )]   1096  1           (1 (1 (1 (1     .0412

.0451

.0536

.0574

92 360 92 360 91 360 91 360 )(1 )(1 )(1 )(1      5.17%, on money .0406

.0482

.0548

.0589

91 360 92 360 92 360 90 360 market )(1 )(1 )(1 )(1     basis.

.0431

.0508

.0564

.0590

90 360 91 360 92 360 ) ) 92 360 ) )           360 1096  1 Step 2: The Fixed Rate Equivalent effective annual rate on a bond basis is: FRE = (5.17%)(365/360) = 5.24%.

47

Finally, Step 3: The equivalent semiannual Swap Coupon is calculated: SC = [(1.0524) .5

– 1](2) = 5.17%.

The dealer can hedge the swap by buying or selling, as appropriate, the 12 futures in the Euro Strip.

The full set of fixed-rate for 6-M LIBOR swap tenors out to three and one-half years, having semiannual payments, that can be created from the Euro Strip are listed in the table below. The swap fixed coupon represents the dealer's mid rate. To this mid rate, the dealer can be expected to add several basis points if fixed-rate receiver, and deduct several basis points if fixed-rate payer. The par swap yield curve out to three and one-half years still needs more points.

48

Implied Swap Pricing Schedule Out To Three and One-half Years as of April 24,2001* Tenor of swap Swap coupon mid rate

6 12 18 4.35% 24 30 36 5.17% 42

*

All swaps above are priced against 6-month LIBOR flat and assume that the notional principal is non amortizing.

49

Swap Valuation

The example below illustrates the valuation of an interest rate swap, given the coupon payments are known. Consider a financial institution that receives fixed payments at the annual rate 7.15% and pays floating payments in a two-year swap. Payments are made every six months. The data are:

Payments dates Days between payment Dates Treasury Bills Prices B(0,T) Euro Dollar Deposit L(0,T)

t 1 = 182 t 2 = 365 t 3 = 548 182 183 183 .9679

.9362

.9052

.9669

.9338

.9010

t 4 = 730 182 .8749

.8684

B(0,T)=PV of $1.00 paid at T.L(0,T)=PV of 1Euro$ paid at T. These prices are respectively, derived from the Treasury and Eurodollar term structures.

50

The fixed side of the swap.

At the first payment date, t 1 , the dollar value of the payment is:

V

FIXED

(t

1

, t

1

)

N

P

(.0715) 182 365 ,

where N P principal.

denotes the notional The present value of receiving one dollar for sure at date t payment is: 1 , is 0.9679. Therefore, the present value of the first fixed swap V FIXED (0, t 1 )  [.

9679 ] V R (t 1 , t 1 ).

51

By repeating, this analysis, the present value of all fixed payments is: V

FIXED

(0) = N = N

P

[(.9679)(.0715)(182/365) + (.9362)(.0715)(183/365) + (.9052)(.0715)(183/365) + (.8749)(.0715)(182/365)]

P

[.1317].

This completes the fixed payment of the swap. 52

On the floating side of the swap, the pattern of payments is similar to that of a floating rate bond, with the important proviso that there is no principal payment in a swap. Thus, when the interest rate is set, the bond sells at par value. Given that there is no principal payment, we must subtract the present value of principal from the principal itself. The present value of the floating rate payments depends on L(0, t at date t 4 :

4

) - the present value of receiving one Eurodollar

V

FLOATING

(0)

N

P

[ 1

 

N

P

.

8684 N ]

P

[L(0,

(.1316)N

P

.

t

4

)]

53

The value of the swap to the financial institution is:

Value of Swap = V FIXED (0) - V FLOATING (0) = N P [.1317 - .1316] = (.0001)N P .

If the notional principal is $45M, the value of the swap is $4,500.

In this example, the Treasury bond prices are used to discount the cash flows based on the Treasury note rate. The Eurodollar discount factors are used to measure the present value of the LIBOR cash flows. This practice incorporates the different risks implicit in these different cash flow streams. This completes the example. 54

SWAP VALUATION:

The general formula To generalize the above example, we replace algebraic symbols for the numbers.

Consider a swap in which there are n payments occurring on dates T

k j

expressed as a percent; N

P

notional principal; and B(0,T sure at date T

j

.

j j

, where the number of days between payments is , j = 1,…, n. Let R be the swap rate, represents the ) is the present value of receiving one dollar for The value of the fixed payments is:

V

FIXED

(0)

N

P j n   1

{B(0, T

j

R )[ 100 ][ k

j

365 ]}.

55

Arriving at the value of the floating rate payments requires more analysis.

1. If the swap is already in existence, let λ denote the pre specified LIBOR rate. At date T

1

, the payment is:

N

P

[λ k

1

360 ]

and a new LIBOR rate is set.

On T 1 , the value of the remaining floating rate payments is:

N P – N P {L(T 1 , T N )}.

where L(T

1 , T N

) is the present value at

date T

We are now ready to calculate the total value of the floating rate payments at date T 1

1

. of a Eurodollar deposit that pays one dollar at date T

n .

56

The total value of the floating rate payments at date T 1 is:

V

FLOATING

(T

1

)

 

N N

P P

λ k

1 

360 N

P

L(T

1

, T

n

).

The value of the floating rate payments at date 0 is the PV of:

V

FLOATING

(T

1

) : V

FLOATING

(0)

N

P   

λ k

1

360

1

  

L(0, T

1

) N

P

L(0, T

n

).

This holds true because L(T

1

, T

n

)L(0, T

1

)

L(0, T

n

).

57

2. If the swap is initiated at date 0, then the above equation simplifies as follows: Let λ(0) denote the current LIBOR rate. By definition:

1 L(0, T

1

)

and because 1

λ(0) T

1

360 k

1 

T

1

, the value of the floating rate payments is : V

FLOATING

(0)

N

P   

λ(0) T

1

360

1

  

L(0, T

1

) N

P

L(0, T

n

).

V

FLOATING

(0)

N

P

[1 L(0, T

n

)].

58

IN CONCLUSION: The value of the swap for the party receiving fixed and paying floating is the difference between the fixed and the floating values. For example, the value of a swap that is initiated at time 0 is: THE SWAP VALUE for the party receiving fixed and paying V SWAP  V FIXED (0) V FLOATING (0) floating is : N P    j n   1 {B(0, T j R )[ 100 ][ k j 365 ]}  N P [1  L(0, T n ]    .

Notice that this value can be positive ,zero, or negative depending upon current rates.

This conclude the analysis of

plain vanilla

swap valuation.

59

PAR SWAPS

A

par swap

is a swap for which the present value of the fixed payments equals the present value of the floating payments, implying that the net value of the swap is zero. Equating the value of the fixed payments and the value of the floating rate payments yields the FIXED RATE, R, which makes the swap value zero. For PAR SWAP : V FIXED (0)  V FLOATING (0) N P    j n   1 {B(0, T j R )[ 100 ][ k j 365 ]}  N P [1  L(0, T n ]    .

60

PAR SWAP Valuation

The example below illustrates the valuation of an interest rate par swap.

Consider a financial institution that receives fixed payments at the rate 7.15% per annum and pays floating payments in a two-year swap. Payments are made every six months. The data are:

Payments dates Days between payment Dates Treasury Bills Prices B(0,T) Euro Dollar Deposit L(0,T)

t 1 = 182 t 2 = 365 t 3 = 548 182 183 183 .9679

.9362

.9052

.9669

.9338

.9010

t 4 = 730 182 .8749

.8684

B(0,T)=PV of $1.00 paid at T.L(0,T)=PV of 1Euro$ paid at T. These prices are respectively, derived from the Treasury and Eurodollar term structures.

61

PAR SWAP VALUATION: Solve for R, the equation: N P [ (R/100)(.9679)(182/365) + (R/100)(.9362)(183/365) + (R/100)(.9052)(183/365) + (R/100)(.8749)(182/365) ] = N P [1 - .8684] The equality implies: R/100 = .1316/1.8421

R = 7.14% per annum.

62

2. CURRENCY SWAPS

Nowadays markets are global.

Firms cannot operate with disregard to international markets trends and prices. Capital can be transfered from one country to another rapidly and efficiently. Therefore, firms may take advantage of international markets even if their business is local. For example, a firm in Denver CO. may find it cheaper to borrow money in Germany, exchange it to USD and repay it later, exchanging USD into German marks. Currency swaps are basically, interest rate swaps accross countries 63

Case Study of a currency swap:

IBM and The World Bank

A famous example of an early currency Swap took place between IBM an the World Bank in August 1981, with Salomon Brothers As the intermediary.

The complete details of the swap have never been published in full.

The following description follows a paper published by D.R. Bock in Swap Finance, Euromoney Publications.

64

In the mid 1970s, IBM had issued bonds in German marks, DEM, and Swiss francs, CHF. The bonds maturity date was March 30, 1986. The issued amount of the CHF bond was CHF200 million, with a coupon rate of 6 3/16% per annum. The issued amount of the DEM bond was DEM300 million with a coupon rate of 10% per annum.

During 1981 the USD appreciated sharply against both currencies. The DEM, for example, fell in value from $.5181/DEM in March 1980 to $.3968/DEM in August 1981.

Thus, coupon payments of DEM100 had fallen in USD cost from $51.81 to $39.68. The situation with the Swiss francs was the Same. Thus, IBM enjoyed a sudden, unexpected capital gain from the reduced USD value of its foreign debt liabilities. 65

In the beginning of 1981, The World Bank wanted to borrow capital in German marks and Swiss francs against USD. Around that time, the World Bank had issued comparatively little USD paper and could raise funds at an attractive rate in the U.S. market.

Both parties could benefit from USD for DEM and CHF swap. The World Bank would issue a USD bond and swap the $ proceeds with IBM for cash flows in CHF and DEM.

The bond was issued by the World Bank on August 11, 1981, settling on August 25, 1981. August 25, 1981 became the settlement date for the swap. The first annual payment under the swap was determined to be on March 30, 1982 – the next coupon date on IBM's bonds. I.e., 215 days (rather than 360) from the swap starting date.

66

The swap was intermediated by Solomon Brothers.

The first step was to calculate the value of the CHF and DEM cash flows. At that time, the annual yields on similar bonds were at 8% and 11%, respectively.The

initial period of 215-day meant that the discount factors were calculated as follows:

Discount F actor

1

n

(1

y)

360

,

Where: y is the respective bond yield, 8% for the CHF and 11% for the DEM and n is the number of days till payment.

67

The discount factors were calculated:

Date Days CHF DEM

3.30.82

215 .9550775

.9395764

3.30.83

3.30.84

3.30.85

575 935 .8843310

.8188250

1295 .7581813

.8464652

.7625813

.6870102

3.30.86

1655 .7020104

.6189281.

Next, the bond values were calculated: NPV(CHF) = 12,375,000[.9550775 + .8843310

+ .8188250 + .7581813] + 212,375,000[.7020104] = CHF191,367,478. NPV(DEM)= 30,000,000[.9395764 + .8464652

+.7625813+.6870102] +330,000,000[.61892811] = DEM301,315,273.

68

The terms of the swap were agreed upon on August 11, 1981. Thus, The World Bank would have been left exposed to currency risk for two weeks until August 25. The World Bank decided to hedge the above derived NPV amounts with 14-days currency forwards.

Assuming that these forwards were at $.45872/CHF and $.390625/DEM, The World Bank needed a total amount of $205,485,000; $87,783,247 to buy the CHF and $117,701,753 to buy the DEM.

$205,485,000.

This amount needed to be divided up to the various payments. The only problem was that the first coupon payment was for 215 days, while the other payments were based on a period of 360 days.

69

Assuming that the bond carried a coupon rate of 16% per annum with intermediary commissions and fees totaling 2.15%, the net proceeds of .9785 per dollar meant that the USD amount of the bond issue had to be: $205,485,000/0.9785 = $210,000,000.

The YTM on the World Bank bond was 16.8%. As mentioned above, the first coupon payment involved 215 days only.

Therefore, the first coupon payment was equal to: $210,000,000(.16)[215/360] = $20,066,667.

70

The cash flows are summarized in the following table:

Date USD CHF DEM

3.30.82

3.30.83

20,066,667 12,375,000 33,600,000 12,375,000 30,000,000 30,000,000 3.30.84

33,600,000 12,375,000 30,000,000 3.30.85

YTM

33,600,000 12,375,000 3.30.86 243,600,000 212,375,000 330,000,000

8% 11%

30,000,000

16.8% NPV

205,485,000 191,367,478 301,315,273 By swapping its foreign interest payment obligations for USD obligations, IBM was no longer exposed to currency risk and could realize the capital gain from the dollar appreciation immediately. Moreover, The World Bank obtained Swiss francs and German marks cheaper than it would had it gone to the currency markets directly.

71

Foreign Currency Swaps

EXAMPLE: a “

plain vanilla

foreign currency swap.

Counterparty F1 has issued bonds with face value of £50M with a annual coupon of 11.5%, paid semi-annually and maturity of seven years.

Counterparty F1 would prefer to have dollars and to be making interest payments in dollars. Thus counterparty F1 enters into a foreign currency swap with counterparty F2 - usually a financial institution. In the first phase of the swap, party F1 exchanges the principal amount of £50M with party F2 and, in return, receives principal worth $72.5M. Usually, this exchange is done in the current exchange rate, i.e., S = $1.45/£ in this case.

72

The swap agreement is as follows: Party F1 agrees to make to counterparty F2 semi – annual interest rate payments at the rate of 9.35% per annum based on the Dollar denominated principal for a seven Year period.

In return, counterparty F1 receives from party F2 a semi-annual interest rate at the annual rate of 11.5%, based on the sterling denominated principal for a seven year period.

The swap terminates at the maturity seven years later, when the principals are again exchanged: party F1 receives the principal worth £50M and counterparty F2 receives the principal Amount of $72.5M.

73

DIRECT SWAP FIXED FOR FIXED $ 9.35% F1 F2 £ 11.5% £11.5% Great Britain F1 BORROWS £50M AND DEPOSITS IT IN COUNTERPARTY F2’s ACCOUNT IN LONDON U.S.A

F2 DEPOSITS $72.5M IN COUNTERPARTY F1’S ACCOUNT IN NEW YORK CITY At maturity, the original principals are exchanged to terminate the swap.

74

By entering into the foreign currency swap, counterparty F1 has successfully transferred its sterling liability into a dollar liability.

In this case, party F2 payments to party F1 were based on the the same rate of party’s F1 payments in Great Britain £11.5%. Thus, party F1 was able to exactly offset the sterling interest rate payments.

This is not necessarily always the case. It is quite possible that the interest rate payments counterparty F1 receives from counterparty F2 only partially offset the sterling expense. In the same example, the situation may change to: 75

DIRECT SWAP FIXED FOR FIXED $9.55% F1 F2 £11.25% £11.5% Great Britain F1 BORROWS £50M AND DEPOSITS IT IN COUNTERPARTY F2’s ACCOUNT IN LONDON U.S.A

F2 DEPOSITS $72.5M IN COUNTERPARTY F1’S ACCOUNT IN NEW YORK CITY At maturity, the original principals are exchanged to terminate the swap.

76

THE ANALYSIS OF CURRENCY SWAPS F1 IN COUNTRY A LOOKS FOR FINANCING IN COUNTRY B AT THE SAME TIME F2 IN COUNTRY B, LOOKS FOR FINANCING IN COUNTRY A COUNTRY A F1 COUNTRY B F2 PROJECT OF F2 PROJECT OF F1

77

CURRENCY SWAP

IN TERMS OF THE BORROWING RAES, EACH FIRM HAS

COMPARATIVE ADVANTAGE

ONLY IN ONE COUNTRY, EVEN THOUGH IT MAY HAVE

ABSOLUTE ADVANTAGE

IN BOTH COUNTRIES.

THUS, EACH FIRM WILL BORROW IN THE COUNTRY IN WHICH IT HAS COMPARATIVE ADVANTAGE AND THEN, THEY EXCHANGE THE PAYMENTS THROUGH A SWAP.

78

CURRENCY SWAP FIXED FOR FIXED CP = Chilean Peso R = Brazilian Real Firm CH1, is a Chilean firm who needs capital for a project in Brazil, while, A Brazilian firm, BR2, needs capital for a project in Chile. The market for fixed interest rates in these countries makes a swap beneficial for both firms as follows:

79

FIRM CHILE BRAZIL CH1 $12% R16% BR2 $15% R17%

With these rates, CH1 has absolute advantage in both markets but, comparative advantage in Chile only. CH1 borrows in Chile in Chilean Pesos and BR2 borrows in Brazil in Reals. The swap begins with the interchange of the principal amounts borrowed at the current exchange rate.

The figures below show a direct swap between CH1 and BR2 as well as an indirect swap.

The swap terminates at the end of the swap period when the original principal amounts exchange hands once more. 80

ASSUME THAT THE CURRENT EXCHANGE RATE IS: R1 = CP250 ASSUME THAT CH1 NEEDS R10.000.000 FOR ITS PROJECT IN BRAZIL AND THAT BR2 NEEDS EXACTLY CP2,5B FOR ITS PROJECT IN CHILE.

FIRM CH1 BR2 AGAIN: CHILE BRAZIL $12% $15% R16% R17%

81

DIRECT SWAP FIXED FOR FIXED R15% CH1 BR2 $12% $12% R17% CHILE CH1 BORROWS CP2.5B AND DEPOSITS IT IN BR2’S ACCOUNT IN SANTIAGO BRAZIL BR2 BORROWS R10M AND DEPOSITS IT IN CH1’S ACCOUNT IN SAO PAULO CH1 pays R15%; BR2 pays CP12% + R2%

82

INDIRECT SWAP FIXED FOR FIXED INTERMEDIARY R15.50% $12% $14.50% R17% CH1 BR2 $12% CHILE CH1 BORROWS CP2.5B AND DEPOSITS IT IN BR2’S ACCOUNT IN SANTIAGO R17% BRAZIL BR2 BORROWS R10M AND DEPOSITS IT IN CH1’S ACCOUNT IN SAO PAULO

83

CH1: BR2: THE CASH FLOWS: PAYS R15.50% PAYS CP14.50% THE INTERMEDIARY REVENUE: CP2.50 – R1.50% CP2,5B(0.025) – R10M(0.015)(250) = CP62,500,000 - CP37,500,000 = CP25,000,000 Notice:

In this case, CH1 saves 0.25% and BR2 saves 0.25%, while the intermediary bears the exchange rate risk. If the Chilean Peso depreciates against the Real the intermediary’s revenue declines. When the exchange rate reaches CP466,67/R the intermediary gain is zero. If the Chilean Peso continues to depreciate the intermediary loses money on the deal.

84

FIXED FOR FLOATING CURRENCY SWAP

A Mexican firm needs capital for a project in Great Britain and a British firm needs capital for a project in Mexico. They enter a swap because they can exchange fixed interest rates into floating and borrow at rates that are below the rates they could obtain had they borrowed directly in the same markets.

In this case, the swap is

Fixed-for-Floating rates,

i.e., One firm borrows fixed, the other borrows floating and they swap the cash flows therby, changing the nature of the payments from fixed to floating and vice – versa. 85

DIRECT SWAP FIXED FOR FLOATING INTEREST RATES MX1 MEXICO MP15% GREAT BRITAIN £LIBOR + 3% GB2 MP18% £LIBOR + 1% ASSUME:

The current exchange rate is:

£1 = MP15.

MX1 needs £5.000.000 in England and GB2 needs MP75.000.000 in Mexico.

THUS:

MX1 borrows MP75m in Mexico and deposits it in GB2’s account in Mexico D.F., Mexico, While GB2 borrows £5,000,000 in Great Britain and deposits it in MX1’s account in London, Great Britain.

86

DIRECT SWAP FIXED FOR FLOATING £L + 1% MX1 GB2 MP15% MP15% £L + 1% MEXICO MX1 BORROWS MP75M AND DEPOSITS IT IN GB2’S ACCOUNT IN MEXICO D.F., MEXICO.

ENGLAND GB2 BORROWS £5,000,000 AND DEPOSITS IT IN MX1’S ACCOUNT IN LONDON, GREAT BRITAIN MX1 pays £L+1%; GB2 pays MP15%

87

DIRECT SWAP FIXED FOR FLOATING AGAIN:

MX1 pays £L+ 1%; GB2 pays MP15%.

What does this mean?

It means that both firms pay interest for the capitals they borrowed in the markets where each has comparative advantage.

BUT, with the swap, MX1 pays in pounds £L+ 1%, a better rate than £LIBOR + 3%, the rate it would have paid had it borrowed directly in the floating rate market in Great Britain. GB2 pays MP15% fixed, which is better than the MP18% it would have paid had it borrowed directly in Mexico. 88

A

plain vanilla CURRENCY SWAPS VALUATION

Under the terms of a swap, party A receives French francs (FF) interest rate payments and making dollar ($) interest payments. Let us measure the amount in . Also, use the following notation:

B FF

= PV of the payments in FF from party B, including the principal payment at maturity.

V

B $

= PV of the payments in $ from party A, including the principal payment at maturity.

S 0

(FF/$) = the current exchange rate.

Then, the value of the swap to counterparty A in terms of sterling is:

V

FF

= B

FF

- S

0

(FF/$)B

$

.

89

Note that the value of the swap depends upon the shape of the domestic term structure of interest rates and the foreign term structure of interest rates.

EXAMPLE: A ‘PLAIN VANILLA’ CURRENCY SWAP VALUATION

Consider a financial institution that enters into a two-year foreign currency swap for which the institution receives 5.875% per annum semiannually in French francs (FF) and pays 3.75% per annum semi-annually in U.S. dollars ($). The principals in the two currencies are FF58.5M $10M, reflecting the current exchange rate:

S 0 (FF/$) = 5.85.

Information about the U.S. and French term structures of interest rates is given in following table: 90

Domestic and Foreign Term Structure* Maturity Price of a zero coupon Bond Months $ FF

6 .0840 (3.22%) .9699 (6.09%) 12 18 24 .9667 (3.38%) .9456 (5.59%) .9467 (3.65%) .9190 (5.63%) .9249 (3.90%) .8922 (5.70%) *Figures in parenthesis are continuously compounded yields.

The coupon payment of the semi-annual interest payments in French Francs is:

[FF58.5M] 5.875

100

FF 1,718,437.

( 1 2 ) 50.

91

Therefore, the present value of the interest rate payments in U.S Dollars plus principal is: PV(Cash Flows) $  B FF S($/FF)    FF1,718,43 7.59[.9699

  .9190

FF58,500,0   .9456

.8922] 00(.8922)    [$.1709/FF ]  $10,014,36 4.

The coupon payment of the semi-annual interest payments in U.S Dollars is:

[$10M] 3.75

100 ( 1 2 )

$ 187,500.

92

Therefore, the present value of the interest rate payments in U.S Dollars plus principal is:

$187,500[.

9840

.9667

B

$     

.9467

$10,000,00

.8249] 0(.9249)

  

$9,965,681 .

Therefore, the

value of the foreign currency swap

is:

PV(Cash Flow)

$ 

$10,014,36 4 B

$

9,965,681

$48,683.

93

3.COMMODITY SWAPS

The huge success of domestic interest rate swaps and foreign currency swaps lead investors and firms to look for other markets for swaps. In the 1980s and the 1990s swaps began trading on a large range of underlying assets. Among these are: Commodities, stocks, stock indexes, bonds and other types of debt instruments. The assets underlying the swaps in these markets are agreed upon quantities of the commodity. Here, we analyze commodity swaps using mainly energy commodities – natural gas and crude oil. For example, 100,000 barrels of crude oil. 94

How does a commodity swap works:

In a typical commodity swap: party A makes periodic payments to counterparty B at a

fixed price per unit

for a given notional quantity of some commodity.

Party B pays party A an agreed upon

floating price

for a given notional quantity of the commodity underlying the swap.

The commodities are usually the same. The floating price is usually defined as the market price or an average market price, the average being calculated using spot commodity prices over some predefined period.

95

Example: A Commodity Swap

Consider a refinery that has a constant demand for 30,000 barrels of oil per month and is concerned about volatile oil prices. It enters into a three-year commodity swap with a swap dealer. The current spot oil price is $24.20 per barrel.

The refinery agrees to make monthly payments to the swap dealer at a fixed rate of $24.20 per barrel.

The swap dealer agrees to pay the refinery the average daily price for oil during the preceding month.

The notional principal is 30,000 barrels. 96

Spot oil market Oil Spot Price $24.20/bbl Refinery Average Spot Price Swap Dealer The commodity: 30,000 bbls.

97

Note that in the swap no exchange of the notional commodity takes place between the counterparties.

The refinery has reduced its exposure to the volatile oil prices in the markets. It still, however, bear some risk. This is because there may be a difference between the spot price and the average spot price. The refinery is still buying oil and paying the spot price, and from the swap dealer it receives the last month's average spot price. It also pays to the swap dealer $24.20 per barrel over the life of the contract. Therefore, the spread between the spot and last month average prices presents some risk to the refinery.

98

A NATURAL(NG) SWAP: FIXED FOR FLOATING.

MC – a marketing firm buys NG from a producer for the fixed price of $9.50/UNIT (1,000 cubic feet). At the same time MC finds an end user and sells the NG. The end user insists on paying a floating market price index. The index is published daily according NG prices in different locations.

MC’s risk is that the index falls below $9.50. MC enters a FIXED FOR FLOATING swap in which it pays the swap dealer the index and recieves $9.55/tcf The notional amount of NG is equal to the amount purchased and sold by MC.

99

A FISED-FOR-FLOATING NATURAL GAS SWAP PRODUCER $9.50

Gas MC INDEX Gas END USER $9.55

SWAP DEALER INDEX MC’s cash flow is: - $9.50 + Index + $9.55 – Index = $0.05/UNIT

100

FLOATING FOR FLOATING NATURAL GAS SWAP

There are several different energy indexes for various energy commodities. Thus, it is very possible that MC will buy the natural gas for one index and sell it to the end user for another index. In these cases, both cash flows are based on floating rates and MC faces the exposure of the floating spread. MC may be able to enter a swap and fix a positive spread for its revenues. 101

FLOATING-FOR-FLOATING NATURAL GAS SWAP producer INDEX1 Gas MC INDEX2 USER Gas INDEX1 INDEX2 - $0.08

Swap Dealer In this case MC’s cash flow is : (Index2) – (Index1) + (Index1) – ( Index2 - $0.08) = $0.08/UNIT.

102

Valuation of Commodity of Swaps

The value of a “plain vanilla” commodity swap.

In a "plain vanilla" commodity swap, counterparty A agrees to pay counterparty B a fixed price, P(fixed, t

i

), per unit of the commodity at dates t A the spot price, S(t

i

1 , t 2 ,. . ., t n .

Counterparty B agrees to pay counterparty ) of the commodity at the same dates t 1 , t 2 ,. . ., t n .

The notional principal is N commodity The net payment to counterparty A at date t 1 is:

P

units of the

V(t 1 , t 1 )

[S(t 1 ) - P(fixed, t 1 )]N P .

103

The value of this payment at date 0 is the present value of

V(t 1 , t 1 )

:

V(0, t 1 ) = PV 0 { V(t 1 , t 1 ) } = PV 0 [S(t 1 )] – P(fixed, t 1 ) B(0, t 1 )N P ,

where

B(0, t 1 )

is the value at date 0 of receiving one dollar for sure at date t 1 . In the absence of carrying costs and convenience yields, the present value of the spot price S(t 1 ) would be equal to the current spot price. In practice, however, there are carrying costs and convenience yields.

104

It can be shown that the use of forward prices incorporates these carrying costs and convenience yields. Drawing on this insight, an alternative expression for the present value of the spot price PV as follows: 0 [S(t 1 )] in terms of forward prices may be derived Consider a forward contract that expires at date t 0 is: 1 written on this commodity with the forward price = F(0, t expires at date t

S(t

1

1

is:

1 ) - F(0, t

). The cash flow to the forward contract when it

1

).

The value of the forward contract at date

PV 0 [S(t 1 )] - F(0, t 1 )B(0, t 1 ).

105

Like any forward, the forward price is set such that no cash is exchanged when the contract is written. This implies that the value of the forward contract, when initiated, is zero. That is:

PV 0 [S(t 1 )] = F(0, t 1 )B(0, t 1 ).

Using this expression, the value at date 0 of the first swap payment is:

V(0,t l ) = [F(0,t 1 ) - P(fixed,t 1 )]B(0, t l )N P .

106

Repeating this argument for the remaining payments, it can be shown that the

value of the commodity swap at date 0 is:

V

0  j n   1

[F(0, t

j

)

P(Fixed)]B (0, t

j

)N

p

.

Note that the value of the commodity swap in this expression depends only on the forward prices, F(0,t coupon bond prices, B(0, t

1 j

), of the underlying commodity and the zero ), all of which are market prices observable at date 0.

107

FINAL EXAMPLE:

From the derivatives trading room of BP: Hedging the sale and purchase of Natural Gas, using NYMEX Natural Gas futures and Creating a sure profit margin swapping the remaining spread. First, let us define:

The following two indexes: 1. L3D - LAST THREE DAYS

A weighted average of NYMEX NG futures prices during the last three trading days of the contract.

2. IF - INSIDE FERC

A weighted average of NG spot prices at various places. 108

April 12 – 11:45AM From BP’s derivative trading room 1. The 1 st call:

BP agrees to buy NG from BM in August for IF.

2. The 2 nd call:

BP hedges the NG purchase going long NYMEX’ August NG futures.

3. The 3 rd

call: BP finds a buyer for the gas - SST. But, SST negotiates the purchase price to be at some discount off the current August NYMEX NG futures. Let $X be the discount amount. $X is left unknown for now.

109

A PARTIAL SUMMARY DATE SPOT April 12 Buy from BM.

Sell to SST.

FUTURES Long August NYMEX Futures.

F 4,12; aug = $3.87.

August 12 (i) Buy NG from BM Short August NYMEX S 1 = IF . Futures.

(ii) Sell NG to SST for S 2 = F 4, 12; aug – $X F aug; aug = L3D PARTIAL CASH FLOW: (F 4,12; aug – $X) – IF + L3D - F 4,12; aug = L3D – $X – IF.

110

How can BM eliminate the spread risk?

BP decides to enter a spread swap.

Clearly, this is a floating for floating swap.

4. The 4 th

call: BP enters a swap whereby BP pays the Swap dealer

L3D – $.09

and receives

IF

from the Swap dealer. The swap is described as follows: 111

A FLOATING FOR FLOATING SWAP L3D - $.09

BP SWAP DEALER IF

The principal amount underlying the swap is the same amount of NG that BP buys from BM and sells to SST. 112

SUMMARY OF CASH FLOWS MARKET Spot: CASH FLOW F 4, 12; AUG - $X - IF Futures: + L3D - F 4, 12; AUG Swap: TOTAL BP decides to make 3 cents per unit.

Solving

$.03 = $.09 - $X

for

$X

yields:

+ IF - (L3D – $.09) = $.09 - $X. $X = $.06.

5. The 5 th call BP

calls

SST

and both agree that

SST

buys the NG from August for today’s

BP

in

NYMEX - $.03. I.e., $3.87 - $.06 = $3.81.

THE END

113

THE BP EXAMPLE MARKET SWAP: SWAP DEALER L3D - .09

IF SPOT: BM IF NG LONG F 4,12;AUG BP F 4,12;AUG - $.06

SST NG SHORT L3D FUTURES NYMEX

114

4.

BASIS SWAPS

A basis swap is a risk management tool that allows a hedger to eliminate the BASIS RISK associated with the hedge. Recall that a firm faces the CASH PRICE RISK, opens a hedge, using futures, in order to eliminate this risk. In most cases, however, the hedger firm will face the BASIS RISK when it operates in the cash markets and closes out its futures hedging position. We now show that if the firm wishes to eliminate the basis risk, it may be able to do so by entering a:

BASIS SWAP.

In a BASIS SWAP, The long hedger pays the initial basis, I.e., a fixed payment and pays the terminal basis, I.e., a floating payment. The short hedger, pays the terminal basis and receives the initial basis.

1.

TIME

0 k

THE FUTURES SHORT HEDGE: CASH S 0 S k FUTURES BASIS F 0,t F k, B 0 = S 0 B k,t = S k - F 0,t - F k,t

The selling price for the SHORT hedger is:

F 0,t + B k,t .

2. THE SWAP OF THE SHORT HEDGE: SHORT HEDGER B 0 B k,t SWAP DEALER 3. THE SHORT HEDGER’S SELLING PRICE: F 0,t + B k,t + B 0,t - B k,t = F 0,t = F 0,t = S 0 .

+ B + S 0,t 0 - F 0,t

1.

TIME

0 k

THE FUTURES LONG HEDGE: CASH S 0 S k FUTURES BASIS F 0,t F k, B 0 = S 0 - F 0,t B k,t = S k - F k,t

The purchasing price for the LONG hedger:

F 0,t + B k,t .

2. THE SWAP OF THE LONG HEDGER LONG HEDGER B 0 B k,t SWAP DEALER 3. THE LONG HEDGER’S PURCHASING PRICE: F 0,t + B k,t + B 0,t - B k,t = F 0,t = F 0,t = S 0 + B + S 0,t 0 - F 0,t

1. PRICE RISK FUTURES HEDGING 2. BASIS RISK BASIS SWAP 3. NO RISK AT ALL THE CASH FLOW IS: THE CURRENT CASH PRICE!

BASIS SWAP Buy gas at “Screen - 10”

$3.60

NYMEX

L3D $3.50

GAS PRODUCER POWER PLANT

GAS Power plant is a long hedger.Initial basis = –$.10. The terminal basis is S – L3D. Power plant may swap the bases: final purchasing price of: $3.60 + S – L3D + (S - L3D - $.10) = $3.50.