General Structure of Wave Mechanics (Ch. 5) • • • • Sections 5-1 to 5-3 review items covered previously use Hermitian operators to represent observables (H,p,x) eigenvalues.
Download ReportTranscript General Structure of Wave Mechanics (Ch. 5) • • • • Sections 5-1 to 5-3 review items covered previously use Hermitian operators to represent observables (H,p,x) eigenvalues.
General Structure of Wave Mechanics (Ch. 5) • • • • Sections 5-1 to 5-3 review items covered previously use Hermitian operators to represent observables (H,p,x) eigenvalues of Hermitian operators are real and give the expectation values eigenvectors for different eigenvalues are orthogonal and form a complete set of states • any function in the space can be formed from a linear series of the eigenfunctions • some variables are conjugate (position, momentum) and one can transform from one to the other and solve the problem in either’s “space” eigenfunctions : ui ( x ) i | j ui | u j ( x, t ) C N * u i u j dx ij dot product uN ( x )e iEt / p * pop dx * ( i P460 - math concepts ) d x x 1 Notation • • • • there is a very compact format (Dirac notation) that is often used |i> = |ui> = eigenfunction <c|f is a dot product between 2 function |i><j| is an “outer” product (a matrix). For example a rotation between two different basis • if an index is repeated there is an implied sum eigenfunctions : ui ( x ) i | j ui | u j ( x) C N u u dx * i uN ( x ) j ij dot product CN n n n n n projectionoperator P460 - math concepts 2 Degeneracy (Ch. 5-4) • If two different eigenfunctions have the same eigenvalue they are degenerate (related to density of states) • any linear combination will have the same eigenvalue Ou i aui Ou j au j O (ui u j ) a (ui u j ) • usually pick two linear combinations which are orthogonal • can be other operators which have only some specific linear combinations being eigenfunctions. Choice may depend on this (or on what may break the degeneracy) • example from V=0 sin kx, coskx, e ikx ,e ikx 2k 2 E 2m sin kx, coskx orthogonal: sin kx coskxdx 0 eikx , e ikx orthogonal: ( e ikx )*eikxdx 0 P460 - math concepts 3 Degeneracy (Ch. 5-4) • Parity and momentum operators do not commute ( x ) ( x ) ) i x x ( x ) pop ( P ( x )) i x [ P, pop ] Ppop pop P 2i P x P ( pop ( x )) P ( i • and so can’t have the same eigenfunction • two different choices then depend on whether you want an eigenfunction of Parity or of momentum sin kx, coskx eikx , eikx Parity m om entum P460 - math concepts 4 Uncertainty Relations (Supplement 5-A) • If two operators do not commute then their uncertainty product is greater then 0 • if they do commute 0 • start from definition of rms and allow shift so the functions have <U>=0 ( A) 2 A2 A 2 A2 * A2 dx U A A U 0, ( U ) 2 ( A) 2 • define a function with 2 Hermitian operators A and B U and V and l real f ( x ) (U ilV ) ( x ) U A A V B B • because it is positive definite I (l ) f *f d x 0 • can calculate I in terms of U and V and [U,V] I ((U ilV ) ) * (U ilV ) dx * (U dag ilV dag )(U ilV ) dx U dag U T * U Herm itian * (U ilV )(U ilV ) dx P460 - math concepts 5 Uncertainty Relations • rearrange I * * (Supplement 5-A) (U ilV )(U ilV ) dx (U 2 il (UV VU ) l2V 2 ) dx • But just the expectation values I U 2 il ( UV VU ) l2 V 2 U 2 il [U ,V ] l2 V 2 • can ask what is the minimum of this quantity dI i [U ,V ] 0 lmin dl 2 V2 • use this “uncertainty” relationship from operators alone I (lmin ) U 2 ilmin [U ,V ] l2min V 2 0 1 i[U ,V ] 2 4 1 i[ A, B ] 2 4 U 2 V 2 ( A) 2 ( B ) 2 P460 - math concepts 6 Uncertainty Relations -- Example • take momentum and position operators • in position space xop x pop i x px i x i ix x x x px xp [ p, x ] i xp ix • that x and p don’t commute, and the value of the commutator, tells us directly the uncertainty on their expectation values ( A) 2 ( B ) 2 px 1 i[ A, B ] 2 4 1 1 i[ p, x ] 2 4 2 P460 - math concepts i ( i) 2 2 7 Time Dependence of Operators • the Hamiltonian tells us how the expectation value for an operator changes with time A t * ( x, t ) A ( x, t )dx d A A t * ( x , t ) ( x, t )dx dt t * * [ ( x , t )] A ( x , t ) dx ( x , t ) A [ ( x, t )]dx t t • but know Scrod. Eq. 1 * 1 i H ( H )* H * * t i t i H *T H ( H )* A *HA • and the H is Hermitian • and so can rewrite the expectation value d A A t dt t d A A t dt t i i * * HA dx AHdx i H , A t t P460 - math concepts 8 Time Dependence of Operators II • so in some sense just by looking at the operators (and not necessarily solving S.Eq.) we can see how the expectation values changes. d A i H , A A t t dt t • if A doesn’t depend on t and [H,A]=0 <A> doesn’t change and its observable is a constant of the motion • homework has H(t); let’s first look at H without t-dependence • and look at the t-dependence of the x expectation value d i x dt H , x V ( x ), x 0 d x dt p 2 i p2 H V ( x) 2m p2 2m V ( x ), x , x p p , x p , x p 2 p i p m P460 - math concepts 9 Time Dependence of Operators III • and look at the t-dependence of the p expectation value d i p dt H , p i p2 2m V ( x ), p i p ,V ( x ) ( pV Vp ) p (V ) V ( p ) d d dV (V ) V i dx i dx i dx • rearrange giving p ,V ( x ) and dV d i dx dt d2 m dt2 x p dV ( x ) dt dV ( x ) dt • like you would see in classical physics P460 - math concepts 10