Transcript Mrs. Rivas

Slide 1

Homework

Mrs. Rivas

(5-1) Algebra Find the value of x.
1.

𝟐(πŸπ’™ + 𝟏) = πŸπŸ–
πŸ’π’™ + 𝟐 = πŸπŸ–
πŸ’π’™ = πŸπŸ”
𝒙 = πŸ’


Slide 2

Homework

Mrs. Rivas

(5-1) Algebra Find the value of x.
2.

𝟐(πŸ‘π’™) = πŸ‘πŸŽ
πŸ”π’™ = πŸ‘πŸŽ
𝒙 = πŸ“


Slide 3

Homework

Mrs. Rivas

(5-1) Algebra Find the value of x.
3.

𝟐(πŸ‘π’™) = 𝟐𝟏
πŸ”π’™ = 𝟐𝟏
𝒙 = πŸ‘. πŸ“


Slide 4

Homework

Mrs. Rivas

X is the midpoint of 𝑴𝑡. Y is the midpoint of 𝑢𝑡.
4. Find XZ.

πŸ—


Slide 5

Homework

Mrs. Rivas

X is the midpoint of 𝑴𝑡. Y is the midpoint of 𝑢𝑡.
5. If XY = 10, find MO.

𝟐𝟎


Slide 6

Homework

Mrs. Rivas

X is the midpoint of 𝑴𝑡. Y is the midpoint of 𝑢𝑡.
6. If π‘šοƒπ‘€ is 64, find π‘šοƒπ‘Œ .

πŸ”πŸ’

πŸ”πŸ’


Slide 7

Homework

Mrs. Rivas

Use the diagram at the right for Exercises 7 and 8.
7. What is the distance across the lake?

πŸ“. πŸ“


Slide 8

Homework

Mrs. Rivas

Use the diagram at the right for Exercises 7 and 8.

8. Is it a shorter distance from A to B
or from B to C? Explain.

BC is shorter. BC is half od 8 and
AB is half od 11.

πŸ“. πŸ“

πŸ’


Slide 9

Homework

Mrs. Rivas

(5-2) Algebra Find the indicated variables and measures.
10. x, EH, EF

πŸ“π’™ + πŸ‘
ο€­πŸ“π’™
πŸ‘
+𝟏
πŸ’
𝟐
𝑬𝑯 = πŸ“π’™ + πŸ‘ = πŸ“ 𝟐 + πŸ‘ = πŸπŸ‘
𝑬𝑭 = πŸ•π’™ βˆ’ 𝟏 = πŸ• 𝟐 βˆ’ 𝟏 = πŸπŸ‘

= πŸ•π’™ βˆ’ 𝟏
ο€­πŸ“π’™
= πŸπ’™ βˆ’ 𝟏
+𝟏
= πŸπ’™
= 𝒙


Slide 10

Homework

Mrs. Rivas

(5-2) Algebra Find the indicated variables and measures.
11. x, mTPS, mRPS

πŸπ’™ – πŸ” = πŸ‘π’™ – πŸπŸ“
ο€­πŸπ’™
ο€­πŸπ’™
– πŸ” = 𝒙 – πŸπŸ“
+ πŸπŸ“
+ πŸπŸ“
πŸπŸ— = 𝒙
π’Žβˆ π‘»π‘·π‘Ί = πŸπ’™ βˆ’ πŸ” = 𝟐 πŸπŸ— βˆ’ πŸ” = πŸ‘πŸ
π’Žβˆ π‘Ήπ‘·π‘Ί = πŸ‘π’™ βˆ’ πŸπŸ“ = πŸ‘ πŸπŸ— βˆ’ πŸπŸ“ = πŸ‘πŸ


Slide 11

Homework

Mrs. Rivas

(5-2) Algebra Find the indicated variables and measures.

12. a, b

πŸ‘π’‚ – 𝟐
πŸπ’‚ – 𝟐
πŸπ’‚
𝒂

=
=
=
=

𝒂 + 𝟏𝟎
𝟏𝟎
𝟏𝟐
πŸ”

πŸ‘π’ƒ – πŸπŸ“ = πŸπ’ƒ + πŸ“
𝒃 – πŸπŸ“ = πŸ“
𝒃 = 𝟐𝟎


Slide 12

Homework
1.

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Slide 13

Homework
2.

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Slide 14

Homework
3.

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Slide 15

Homework
4.

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Slide 16

Homework
5.

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Slide 17

Homework
6.

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Slide 18

Homework
7.

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Slide 19

Homework
8.

Mrs. Rivas

𝒙 + πŸ“ = πŸ‘π’™ + πŸ•
βˆ’πŸπ’™ + πŸ“ = πŸ•
βˆ’πŸπ’™ = 𝟐
𝒙 = βˆ’πŸ


Slide 20

Homework
9.

Mrs. Rivas

𝒙 + 𝟐 = πŸπ’™ – πŸ‘
βˆ’π’™ + 𝟐 = – πŸ‘
βˆ’π’™ = – πŸ“
𝒙 = πŸ“


Slide 21

Homework
10.

Mrs. Rivas

πŸ“π’™ + πŸ• = 𝒙 + πŸ–
πŸ’π’™ + πŸ• = πŸ–
πŸ’π’™ = 𝟏
𝟏
𝒙 =
πŸ’


Slide 22

Homework

Mrs. Rivas

(5-4) In βˆ†ABC, X is the centroid.
11. If CW = 15, find CX and XW.

𝟐
π‘ͺ𝑿 = π‘ͺ𝑾
πŸ‘
𝟐
π‘ͺ𝑿 = (πŸπŸ“)
πŸ‘
πŸ‘πŸŽ
π‘ͺ𝑿 =
πŸ‘
π‘ͺ𝑿 = 𝟏𝟎

πŸπŸ“

𝑿𝑾 = π‘ͺ𝑾 βˆ’ π‘ͺ𝑿

𝑿𝑾 = πŸπŸ“ βˆ’ 𝟏𝟎
𝑿𝑾 = πŸ“


Slide 23

Homework

Mrs. Rivas

(5-4) In βˆ†ABC, X is the centroid.
12. If BX = 8, find BY and XY.

𝟐
𝑩𝑿 = 𝑩𝒀
πŸ‘
𝟐
πŸ– = 𝑩𝒀
πŸ‘
πŸ‘
𝟐
πŸ‘
πŸ– = 𝑩𝒀
𝟐
πŸ‘
𝟐
πŸπŸ’
= 𝑩𝒀
𝟐
𝟏𝟐 = 𝑩𝒀

πŸ–

𝑿𝒀 = 𝑩𝒀 βˆ’ 𝑩𝑿
𝑿𝒀 = 𝟏𝟐 βˆ’ πŸ–
𝑿𝑾 = πŸ’

𝟏𝟐


Slide 24

Homework

Mrs. Rivas

(5-4) In βˆ†ABC, X is the centroid.
13. If XZ = 3, find AX and AZ.

𝟏
𝑿𝒁 = 𝑨𝒁
πŸ‘
𝟏
πŸ‘ = 𝑨𝒁
πŸ‘
πŸ‘
𝟏
πŸ‘
πŸ‘ = 𝑨𝒁
𝟏
πŸ‘
𝟏
πŸ— = 𝑨𝒁

πŸ—
πŸ‘

𝑨𝑿 = 𝑨𝒁 βˆ’ 𝑿𝒁
𝑨𝑿 = πŸ— βˆ’ πŸ‘
𝑨𝑿 = πŸ”


Slide 25

Homework

Mrs. Rivas

Is 𝑨𝑩 a median, an altitude, or neither? Explain.
15.

14.

Median; 𝑨𝑩 bisects
the opposite side.

Altitude; 𝑨𝑩 is
perpendicular to the
opposite side.


Slide 26

Homework

Mrs. Rivas

Is 𝑨𝑩 a median, an altitude, or neither? Explain.
17.

16.

Altitude; 𝑨𝑩 is
perpendicular to the
opposite side.

Neither; 𝑨𝑩 is not
perpendicular to nor does
it bisect the opposite side.


Slide 27

Homework
In Exercises 18–22, name each segment.
18. a median in βˆ†ABC

π‘ͺ𝑱

Mrs. Rivas


Slide 28

Homework
In Exercises 18–22, name each segment.
19. an altitude for βˆ†ABC

𝑨𝑯

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Slide 29

Homework
In Exercises 18–22, name each segment.
20. a median in βˆ†AHC

𝑰𝑯

Mrs. Rivas


Slide 30

Homework
In Exercises 18–22, name each segment.
21. an altitude for βˆ†AHB

𝑨𝑯

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Slide 31

Homework
In Exercises 18–22, name each segment.
22. an altitude for βˆ†AHG.

𝑨𝑯

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Slide 32

Homework

Mrs. Rivas

23. A(0, 0), B(0, ο€­2), C(ο€­3, 0). Find the orthocenter of βˆ†ABC.


Slide 33

Homework

Mrs. Rivas

24. In which kind of triangle is the centroid at the same point as the
orthocenter?

equilateral


Slide 34

Homework

π‘΄π’†π’…π’Šπ’‚π’

𝑰𝒏𝒄𝒆𝒏𝒕𝒆𝒓

π‘¨π’π’•π’Šπ’•π’–π’•π’†

π‘·π’π’Šπ’π’• 𝒐𝒇
π’„π’π’π’„π’–π’“π’“π’†π’π’„π’š

π‘ͺ𝒐𝒏𝒄𝒖𝒓𝒓𝒆𝒏𝒕 π’π’Šπ’π’†π’”

𝑢𝒓𝒕𝒉𝒐𝒄𝒆𝒏𝒕𝒆𝒓

Mrs. Rivas

π‘ͺπ’†π’π’•π’“π’π’Šπ’…

π‘ͺπ’Šπ’“π’„π’–π’Žπ’„π’†π’π’•π’†π’“

𝑽𝒆𝒓𝒕𝒆𝒙