Integration - University of Michigan

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Transcript Integration - University of Michigan

Math Review with Matlab:
Calculus
Integration
S. Awad, Ph.D.
M. Corless, M.S.E.E.
D. Cinpinski
E.C.E. Department
University of Michigan-Dearborn
Calculus: Integration
Math Review with Matlab
U of M-Dearborn ECE Department
Integration
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Definite and Indefinite Integrals
Integral Pairs
Closed Form Integrals
Int Command
Closed Form Example
Multiple Independent Variable Example
Numerical Integration
Quad Command
Numerical Integration Example
Closed Form and Numerical Integration Example
2
Calculus: Integration
Math Review with Matlab
U of M-Dearborn ECE Department
Definite & Indefinite Integrals

A definite integral represents the area under a curve
f(x) between the lower limit a and the upper limit b
I DEFINITE  f ( x)dx
b
a

An integral is considered to be indefinite if the upper
and lower limits are not specified
I INDEFINITE  f ( x)dx
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Calculus: Integration
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Integral Pairs


Some indefinite integrals can be thought of as the
inverse of differentiation
A few common integral pairs are shown below
 adx  ax  c
n1
ax
n
ax
 dx  n 1  c
ax
e
ax
e
 dx  a  c

a
 x dx  a ln(x)  c
a sin(bx)
a
cos(
bx
)
dx

c

b
 a cos(bx)
a
sin(
bx
)
dx

c

b
Note that due to initial conditions, arbitrary integral pairs are
not unique and may differ by a constant of integration, c
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Closed Form Integrals
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Closed form integrals are integrals which can be
expressed as explicit functions
The integral pairs on the previous slide are examples of
closed form integrals
Techniques such as partial fraction expansion,
integration by parts, and integration by substitution
can be used to express some integrals in closed form
It is not always possible to find the closed form for the
integral of an arbitrary function
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Calculus: Integration
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Evaluation of Definite Integral
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If a closed form indefinite integral exists, it can be used to
evaluate a definite integral over a region of integration
An integral from an arbitrary lower limit
to a fixed upper limit is denoted as:
F ( x)   f (u)du
x
Thus definite integral from a lower limit a to an upper limit b
can be evaluated using:

b
a

b
a
f ( x)dx   f ( x)dx   f ( x)dx
a
b
x0
x0
f ( x)dx  F (b)  F (a)  F ( x) a
b
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Calculus: Integration
Math Review with Matlab
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Int Command

The int command is used to solve integrals which can
be expressed in closed form
int(s) returns the indefinite integral of the symbolic
variable s with respect to its default symbolic variable
int(s,v) returns the indefinite integral of the symbolic
variable s with respect to the symbolic variable v
int(s,a,b) returns the definite integral of the symbolic
variable s with respect its default symbolic variable from a to b
int(s,v,a,b) returns the definite integral of the symbolic
variable s with respect to the symbolic variable v from a to b
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Calculus: Integration
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Closed Form Example

Given the function, f(x):
1) Use the int command to determine the
Closed Form Indefinite Integral, F(x):
f ( x)  sin(2x)
F ( x)   f ( x)dx
2) From the closed form integral, F(x), determine
the definite integral of f(x) from 0 to p/2
3) Use the int command to directly determine
the definite integral of f(x) from 0 to p/2
4) Determine and plot a function A(z)
representing the general area under f
from 0 to any arbitrary point z
A 2 
 /2
 f ( x)dx
0
z
A( z)   f ( x)dx
0
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Calculus: Integration
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Indefinite Closed Form


Matlab can be used to verify the integral pair shown on a
previous slide
The integration variable parameter does not need to be
specified since x is the only variable in the expression, hence
it will be the default variable of integration
» syms x
» f=(sin(2*x));
f ( x)  sin(2x)
» F=int(f)
F =
-1/2*cos(2*x)
 cos(2x)
F ( x)   f ( x) 
2
9
Calculus: Integration
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Definite Integral Evaluation

The definite integral can be
evaluated from the indefinite integral
using the relationship:

» Fb=subs(F,'x',pi/2)
Fb =
0.5000
» Fa=subs(F,'x',0)
Fa =
-0.5000
 cos(2x)
F ( x) 
2
F ( / 2)  0.5
F (0)  0.5
» A_pidiv2 = Fb - Fa
A_pidiv2 =
1
b
a
f ( x)dx  F (b)  F (a)
 /2
A 2   sin(2x)dx  1
0
10
Calculus: Integration
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Matlab Direct Evaluation

Since f(x) has a closed form, the int command can be
used to directly determine the definite integral
» f=(sin(2*x));
» F_definite=int(f,0,pi/2)
F_definite =
1
 /2
A / 2   sin(2x)dx  1
0
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Area Under Curve

A general function, A(z), used to plot the area under the
curve f(x) to an arbitrary point z can be determined as follows:
»
»
»
»
syms z
F_z = subs(F,x,z);
F_0 = subs(F,x,0);
A_z = F_z - F_0
A_z =
-1/2*cos(2*z)+1/2
z
A( z)   f ( x)dx
0
A( z)  F ( x) x z  F ( x) x0
cos(2 z) 1
A( z)  

2
2
» A_z_pidiv2=subs(A_z,z,pi/2)
A_z_pidiv2 =
1
A( 2)  1
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Graphical Definite Integral


»
»
»
»
»
»
Area under f(x)
from 0 to /2 = 1
Definite Integral
Evaluation A(/2)
subplot(2,1,1)
ezplot(f,0,pi)
grid on
subplot(2,1,2)
ezplot(A_z,0,pi)
grid on
Area  1
A 2  1
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Calculus: Integration
Math Review with Matlab
U of M-Dearborn ECE Department
Multiple Independent
Variable Example


Given the function f(t,x,y):
f (t, x, y)  t  2tx  3txy
Use Matlab to determine the closed form integrals with
respect to the different independent variables:
1) Integrate f with respect to t :
F (t )   f (t, x, y)dt
2) Integrate f with respect to x :
F ( x)   f (t, x, y)dx
3) Integrate f with respect to y :
F ( y)   f (t, x, y)dy
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Calculus: Integration
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Default Integration

Integrating with respect to the default independent
variable will integrate with respect to x
» syms t x y
» f=sym('t + 2*t*x + 3*x*y*t');
» Fx = int(f)
f (t, x, y)  t  2tx  3txy
Fx =
t*x+t*x^2+3/2*x^2*y*t
3 2
F ( x)  tx  tx  tyx
2
2
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Calculus: Integration
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Other Independent Variables

Integration of f(t,x,y) with respect to t or y must be
explicitly specified as an input argument to int
» Ft=int(f,t)
f (t, x, y)  t  2tx  3txy
Ft =
1/2*t^2+t^2*x+3/2*x*y*t^2
1 2
3 2
2
F (t )  t  xt  xyt
2
2
» Fy=int(f,y)
Fy =
t*y+2*x*y*t+3/2*x*y^2*t
3 2
F ( y)  ty  2txy  txy
2
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Calculus: Integration
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Numerical Integration
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Some functions do not have closed form integrals
A definite integral can be numerically approximated
provided that the function is defined over the region of
interest
Numerical integration is performed by subdividing the
integration region into very small regions, approximating
the area in each region, and summing the areas
If as the length of the subintervals tends to 0 and the
summation of areas tends to a unique limit, I, the
definite integral over the interval is I
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Calculus: Integration
Math Review with Matlab
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Quad Command

The quad command is used to numerically evaluate an
integral
Q = quad('f',a,b) approximates the integral of f(x)
from a to b


'f' is a string containing the name of an m-function to be
integrated. Function f must return a vector of output values
when given an input vector.

Q = Inf is returned if an excessive recursion level is
reached, indicating a possibly singular integral.
Typically a new m-function will be created for f when
numerically evaluating an integral
18
Calculus: Integration
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Numerical Integration Example

Given the function, f(x):

The definite integral, F:
f ( x)  sin(x)e
F
 x2
 2
 f (x)dx
0
1) Use the symbolic toolbox to verify that the f(x) does not
have a closed form indefinite integral
2) Plot f(x) to ensure that the function is continuously
defined over the integration region
3) Numerically integrate f(x) to determine F
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Calculus: Integration
Math Review with Matlab
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No Closed Form

No closed form can be found using Matlab’s
symbolic toolbox
» f_sym = sin(x)*exp(-x^2);
» int(f_sym)
Warning: Explicit integral could not be found.
> In C:\MATLABR11\toolbox\symbolic\@sym\int.m at
line 58
ans =
int(sin(x)*exp(-x^2),x)
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Calculus: Integration
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Continuous Plot


A plot verified that
f(x) is continuous
over the integration
region
Numerical
integration is
possible
» ezplot(f_sym)
» grid on
Continuous
0

2
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Calculus: Integration
Math Review with Matlab
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Numerical Integration

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Must numerically evaluate the integral using the quad
command which requires a function as an input
Create a new m-function describing the function:
f ( x)  sin( x)e

 x2
The function must return a vector so be sure to use .*
and .^ notations where appropriate
function f = f_sin_exp_sqr( x )
f=sin(x).*exp(-x.^2);
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Calculus: Integration
Math Review with Matlab
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Numerical Integration

Use the quad command to perform the numerical
integration and evaluate the definite integral
» F_num_int = quad('f_sin_exp_sqr',0,pi/2)
F_num_int =
0.4024
 2
 sin(x)e
 x2
dx  0.4024
0
23
Calculus: Integration
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Closed Form and Numerical
Integration Example

Given the function f(x):

The definite integral, F:
1
f ( x)  e  tan ( x)
x
4
F   f ( x)dx
0
1) Plot f(x) to ensure that the function is continuously defined
over the integration region
2) Use the symbolic toolbox to evaluate the definite integral
3) Numerically integrate f(x) to determine the definite integral
24
Calculus: Integration
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Continuous Plot


»
»
»
»
Use ezplot to plot the
function
Verified continuous
from x=0 to x=4
syms x
f_sym=exp(x)+atan(x);
ezplot(f_sym)
grid on
25
Calculus: Integration
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Symbolic Evaluation

Use the symbolic toolbox int command to evaluate
definite integral from the closed form integral
» defint_sym=int(f_sym,0,4)
Symbolic Expression
F_sym =
exp(4)+4*atan(4)-1/2*log(17)-1
» defint_dbl=double(F_sym)
defint_dbl =
57.4848
 e
4
x
1

 tan ( x) dx  57.4848
0
26
Calculus: Integration
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Numerical Evaluation

Create a new m-function to represent f(x):
function f = f_exp_atan( x )
f=exp(x)+atan(x);

Use quad command to numerically evaluate the definite
integral and verify the previous symbolic result
» defint_numint=quad('f_exp_atan',0,4)
defint_numint =
57.4850

57.4850  57.4848
Small difference to numerical approximation
27
Calculus: Integration
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Summary
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Definite integrals are evaluated over a continuous
interval and result in a number
Closed form indefinite integral functions exist for some
functions independent of the integration limits
The definite integrals can be evaluated from the
closed form indefinite integral if it exists
If a closed form indefinite integral does not exist, the
definite integral of continuous functions can still be
numerically approximated
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