Transcript Slide 1
The Mole, Avogadro’s Number & Molar Mass Packet #20 COUNTING ATOMS BY WEIGHING Counting Atoms by Weighing I • C(s) + O2(g) CO2 (g) • Suppose a scientist has a small pile of carbon and wants to know how many oxygen molecules are required to convert all of the carbon into carbon dioxide. • What can the scientist learn from the chemical equation? • The balanced equation illustrates that one diatomic oxygen molecule (O2) is required for each carbon atom. Counting Atoms by Weighing II • C(s) + O2(g) CO2 (g) • To determine how many oxygen atoms are needed by the scientist, the scientist must know how many carbon atoms are present in his/her pile. • To determine this, the scientist must count the number of atoms through the weight of the sample provided. AMU to grams Conversion • AMU • Atomic mass unit • 1 amu = 1.66 * 10-24 g • The periodic table provides a list of the average amu for each atom • Aka atomic mass • Why? • The atomic mass, listed on the periodic table, is measured in amu’s. • These amu’s can be converted into grams using the equation provided. Problem Example #1A • Calculate the mass, in amu, for 1000 neutral carbon atoms • (1000 atoms) * (12.01 amu/ atom) • (1000 atoms) * (12.01 amu/ atom) • = 12,010 amu Problem Example 1B • Let’s assume that when the scientist weighed the pile of natural carbon, the amount weighed was 3.00 * 1020 amu. How many carbon atoms does the scientist have? • Remember: -1 carbon atom = 12 amu • Conversion factor • Calculation • 3.00 * 1020 amu * (1 carbon atom/12 amu) • 3.00 * 1020 amu * (1 carbon atom/12 amu) • 2.50 * 1019 carbon atoms Problem Examples 2 - 5 • Calculate the mass, in amu, of a sample of aluminum that contains 75 atoms. • Calculate the mass, in amu, of a sample that contains 23 atoms. • Calculate the number of sodium atoms present in a sample that has a mass of 1172.49 amu. • Calculate the number of oxygen atoms in a sample that has a mass of 288 amu. THE MOLE Introduction • A mole is a counting unit • Similar to a dozen Mole • Dozen = 12 • A mole is equal to 6.02 * 1023 items • This is known as Avogadro’s number Counting Unit 6.02 * 1023 atoms Avogadro’s number Introduction II • How many cars (individual cars) are found in 1 mole of cars (group)? • 1 mole of cars = 6.02 * 1023 cars • How many cookies (individual cookies) are found in 1 mole of cookies (group)? • 1 mole of cookies = 6.02 * 1023 cookies. Introduction III • Example III • One mole of carbon (element) • 1 mole C = 6.02 * 1023 atoms • Remember • An element is a substance composed of atoms that are all the same. MOLAR MASS Molar Mass an of Atom • The molar mass of an atom is equivalent to the atom’s atomic mass. Molar Mass Example 1A • What is the molar mass of 1 mole of oxygen (mono)? • 16 grams Molar Mass Example 1B • What is the molar mass of 3 mole of oxygen? • 3 * 16 grams Molar Mass Example 1C • How many moles are found within 64 grams of oxygen? • 4 moles Molar Mass of a Molecule/Compound • The molar mass of a molecule/compound is equivalent of sum of the atomic masses of the all the atoms within the molecule/compound. Molar Mass of a Molecule/Compound II • Calculate the molar mass of one mole of sulfur dioxide (SO2). • 1 mole of sulfur = 32.07 g • 1 mole of diatomic oxygen (16.00 * 2 ) = 32 g • 1 mole of SO2 = 64.07 g Molar Mass of a Molecule/Compound II • Calcium carbonate (calcite), CaCO3 is the principal mineral found in limestone, marble chalk, pearls and the shells of marine animals such as clams. a. Calculate the molar mass of calcite. • b. 100.09 g A certain sample of calcite contains 4.86 mol. What is the mass in grams of this sample? • 486 g of CaCO3 Molar Mass of a Molecule/Compound III • Juglone, a dye known for centuries, is produced form the husks of black walnuts. It is also a natural herbicide that kills off competitive plants around the black walnut tree but does not affect grass and other non-competitive plants. The molecular formula is C10H6O3. Molar Mass of a Molecule/Compound IV • Calculate the molar mass of juglone • 174.1 g = molar mass of juglone • A sample of 1.56 g of juglone was extracted from black walnut husks. How many moles of juglone does this sample represent? • 8.96 * 10-3 mol juglone Molar Mass of a Molecule/Compound V • Isopentyl acetate, C7H14O2, the compound responsible for the scent of bananas, can be produced commercially. Interestingly, bees release about 1 ug (1 * 10-6 g) of this compound when they sting. This attracts other bees, which join the attack. How many moles and how many molecules of isopentyl acetate are released in a typical bee sting? • 5 * 1015 molecules REVIEW Example #1 • How many amu are in 1 mole of carbon? • 12 amu • How many amu’s are in 2 moles of carbon? • (12 amu / 1 mole )* (2 moles) • (12 amu / 1 mole )* (2 moles) = 24 amu • How many grams are in 2 moles of carbon? • Already calculated: -2 moles of carbon = 24 amu • 1 amu = 1.66 * 1024 • (1.66 * 10^24/1 amu ) * (24 amu) • (1.66 * 10^24/1 amu ) * (24 amu) =