Dilution Practice - Dr. Vernon-

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Transcript Dilution Practice - Dr. Vernon-

Dilution Practice
Remember!
M1 V1 = M2 V2
M1 = concentration of stock solution
V1 = volume of stock solution
M2 = goal concentration
V2 = goal volume
#1
• With a 5.0M stock solution of NH3, you need to make
0.50L of 1.0 M solution. How much stock solution do
you need?
• M1 = 5.0 M
• V1 = ??
• M2 = 1.0M
• V2 = 0.50L
• V1 = 0.1L = 100 mL
• How much distilled water will you add to arrive at your
desired solution?
• 500 mL – 100 mL stock solution = 400 mL water added
#2
• With a 6.0M stock solution of NaOH, you need to make
0.250L of 1.0 M solution. How much stock solution do you
need?
• M1 = 6.0 M
• V1 = ??
• M2 = 1.0M
• V2 = 0.250L
• V1 = 0.0417L = 41.7 mL
• How much distilled water will you add to arrive at your
desired solution?
• 250 mL – 41.7 mL stock solution = 208.3 mL water added
#3
• With 100 mL of a 6.0M stock solution, how
much 0.5M dilute solution can you make?
• M1 = 6.0 M
• V1 = 100mL = 0.1L
• M2 = 0.5M
• V2 = ??
• V2 = 1.2L
#4
• If you dilute 175 mL of a 1.6 M solution of LiCl
to 1.0 L, determine the new concentration of
the solution.
• M1 = 6.0 M
• V1 = 175mL = 0.175 L
• M2 = ?
• V2 = 1.0L
• M2 = 0.28 M
#5
• You need to make 10.0 L of 1.2 M KNO3. What
molarity would the potassium nitrate solution
need to be if you were to use only 2.5 L of it?
• M1 = ?
• V1 = 2.5 L
• M2 = 1.2 M
• V2 = 10.0 L
• M1 = 4.8 M
#6
• If I add 25 mL of water to 125 mL of a 0.15 M
NaOH solution, what will the molarity of the
diluted solution be?
• M1 = 0.15 M
• V1 = 125 mL = 0.125L
• M2 = ?
• V2 = 25 mL + 125 mL = 150 mL total = 0.150L
• M2 = 0.125 M
#7
• If I add water to 100 mL of a 0.15 M NaOH
solution until the final volume is 150 mL, what
will the molarity of the diluted solution be?
• M1 = 0.15 M
• V1 = 100 mL = 0.100L
• M2 = ?
• V2 = 150 mL = 0.150L
• M2 = 0.1 M
#8
• I have 345 mL of a 1.50 M NaCl solution. If I boil
the water until the volume of the solution is 250.
mL, what will the molarity of the solution be?
• M1 = 1.50 M
• V1 = 345 mL = 0.345L
• M2 = ?
• V2 = 250. mL = 0.250L
• M2 = 2.07 M
#9
• How much water would I need to add to 500. mL
of a 2.4 M KCl solution to make a 1.0 M solution?
• M1 = 2.4 M
• V1 = 500 mL = 0.500L
• M2 = 1.0M
• V2 = ?
• V2 = 1.2 L total, this means you would need to
add 0.7 L of pure water to your original solution
#10
• Draw what happens when calcium nitrate
dissolves in water. What pieces does it
separate into? In what ratio?
• Ca+2 (aq), 2 NO3- (aq)