投影片 1 - National Cheng Kung University
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Transcript 投影片 1 - National Cheng Kung University
This differs from
03._CrystalBindingAndElasticConstants.ppt
only in the section “Analysis of Elastic Strain” in which a modified
version of the Kittel narrative is used.
3. Crystal Binding and Elastic Constants
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•
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Crystals of Inert Gases
Ionic Crystals
Covalent Crystals
Metals
Hydrogen Bonds
Atomic Radii
Analysis of Elastic Strains
Elastic Compliance and Stiffness Constants
Elastic Waves in Cubic Crystals
Introduction
Cohesive energy energy
required to break up crystal
into neutral free atoms.
Lattice energy (ionic crystals)
energy required to break
up crystal into free ions.
Kcal/mol = 0.0434 eV/molecule
KJ/mol = 0.0104 eV/molecule
Crystals of Inert Gases
Atoms:
• high ionization energy
• outermost shell filled
• charge distribution spherical
Crystal:
•transparent insulators
•weakly bonded
•low melting point
•closed packed (fcc, except He3 & He4).
Van der Waals – London Interaction
Ref: A.Haug, “Theoretical Solid State Physics”, §30, Vol I, Pergamon Press (1972).
Van der Waals forces = induced dipole – dipole interaction between neutral atoms/molecules.
Atom i charge +Q at Ri and charge –Q at Ri + xi.
( center of charge distributions )
Q2
Q2
Q2
Q2
V
R
R x2 x1
R x1
R x2
ˆ a 3
1
1
R
2
R 2R a a
1
Ra
R
R
2
2
2
ˆ x x R
ˆ x R
ˆ x 2 R
ˆ x
R
2
1
2
1
2
2 1/2
x2 x1
2
V
ˆ a
R
2R
2
2
Rˆ x
a2
2
2R
R R 2 R1
ˆ
RRR
1
x 2 2 x12 2x1 x 2
Q2
ˆ x R
ˆ x x x
3 R
2
1
1
2
3
R
Q2
3 x1 x2 y1 y2 2 z1 z2
R
R R zˆ
H H0 V
H0 = sum of atomic hamiltonians
E E0 0 V 0
j0
j V 0
E0 E j
2
0 = antisymmetrized product of
ground state atomic functions
1st order term vanishes if overlap of atomic functions negligible.
2nd order term is negative & R6 (van der Waals binding).
Repulsive Interaction
Pauli exclusion principle
(non-electrostatic) effective repulsion
Alternative
repulsive term:
Lennard-Jones potential:
12 6
V 4
R
R
, determined from gas phase data
e R /
Equilibrium Lattice Constants
Neglecting K.E.
12
6
1
N 4
2
p
R
p
R
i j i j
i j
E U tot
12
For a fcc lattice:
At equilibrium:
6
1
12
12.13188
i j pi j
12 12.13229
For a hcp lattice:
dE
0
dR
1
6
14.45392
i j pi j
6 14.45489
12
6
1
N 4 1212 13 6 6 7
2
R
R
1/6
2
12
6
R0
1.09 for fcc lattices
Experiment (Table 4):
Error due to zero point motion
R n.n. dist
Cohesive Energy
6
12
1
U tot R N 4 12 6
2
R
R
62
1
Utot R0 N
2
12
62
N 4
812
N 4 2.15
for fcc lattices
For low T, K.E. zero point motion.
For a particle bounded within length ,
p
p2
K .E.
2m
quantum correction is inversely proportional to the atomic mass:
~ 28, 10, 6, & 4% for Ne, Ar, Kr, Xe.
2
2m
2
1
2
Ionic Crystals
ions: closed outermost shells
~ spherical charge distribution
Cohesive/Binding energy
= 7.9+3.615.14 = 6.4 eV
Electrostatic (Madelung) Energy
Interactions involving ith ion:
R/ q2
e
R
Ui j
2
q
pi j R
ji
At equilibrium:
j i
n.n.
otherwise
Utot NUi
For N pairs of ions:
Ui Ui j
pi j
q2
R/
N z e
R
﹦Madelung constant
z R / q 2
dU tot
2
0 N e
R
dR
U tot 0
z ﹦number of n.n.
ρ ~ .1 R0
N q 2
1
R 0 R 0
→
2
0
R e
R0 /
q2
z
N q 2
Madelung Energy
R0
Evaluation of Madelung Constant
App. B: Ewald’s method
ji
pi j
1
i fixed
1 1
2 1
2 3 4
KCl
2 ln 2
Kcal/mol = 0.0434 eV/molecule
Prob 3.6
Covalent Crystals
H2
• Electron pair localized midway of bond.
• Tetrahedral: diamond, zinc-blende structures.
• Low filling: 0.34 vs 0.74 for closed-packed.
Pauli exclusion →
exchange interaction
Ar : Filled outermost shell → van der Waal interaction (3.76A)
Cl2 : Unfilled outermost shell → covalent bond (2A)
s2 p2 → s p3 → tetrahedral bonds
Metals
Metallic bonding:
• Non-directional, long-ranged.
• Strength: vdW < metallic < ionic < covalent
• Structure: closed packed (fcc, hcp, bcc)
• Transition metals: extra binding of d-electrons.
Hydrogen Bonds
•
•
•
•
Energy ~ 0.1 eV
Largely ionic ( between most electronegative atoms like O & N ).
Responsible (together with the dipoles) for characteristics of H2O.
Important in ferroelectric crystals & DNA.
Atomic Radii
Standard ionic radii
~ cubic (N=6)
Na+ = 0.97A
F = 1.36A
NaF = 2.33A
obs = 2.32A
Bond lengths:
F2 = 1.417A
Na –Na = 3.716A
NaF = 2.57A
Tetrahedral:
C = 0.77A
Si = 1.17A
SiC = 1.94A
Obs: 1.89A
Ref: CRC Handbook of Chemistry & Physics
Ionic Crystal Radii
E.g. BaTiO3 : a = 4.004A
Ba++ – O– – : D12 = 1.35 + 1.40 + 0.19 = 2.94A → a = 4.16A
Ti++++ – O – – : D6 = 0.68 + 1.40 = 2.08A → a = 4.16A
Bonding has some covalent character.
Analysis of Elastic Strains
Let
xˆ i
be the Cartesian axes of the unstrained state
xi
be the the axes of the stained state
Using Einstein’s summation notation, we have
xi xˆ i i j xˆ j i j i j xˆ j
x1 x1 1 211 1k 1k 1 211 112 122 132
Position of atom in unstrained lattice: r ri xˆ i
Its position in the strained lattice is defined as r ri xi
Displacement due to deformation:
R r r r x xˆ ri i j xˆ j ui xˆ i
i
i
i
ui rj ji
Define ( Einstein notation suspended ):
eii ii
ui
xi
ei j i j ji
ui u j
x j xi
i j
Dilation
V axˆ 1 bxˆ 2 cxˆ 3 abc
V x1 x2 x3 1i 1i axˆ i 2 j 2 j bxˆ j 3k 3k cxˆ k
1i 1i 2 j 2 j 3k 3k V i j k
where
i jk
even permutation of 123
1
1 for ijk odd permutation of 123
0
otherwise
V V 123 1i i 23 2 j 1 j 3 3k i jk O 2
V 1 11 22 33 O 2
V V
11 22 33 O 2 Tr O 2
V
Stress Components
Xy = fx on plane normal to y-axis = σ12 .
(Static equilibrium → Torqueless) i j ji
X y Yx
Elastic Compliance & Stiffness Constants
ei j Si j k l k l
S = elastic compliance tensor
Contracted indices
i
j
1 1
2 2
1
2
3
2
3
1
3
4
5
6
3
3
1
2
1 11 X x
4 23 32 Yz Z y
e S
C e
C = elastic stiffness tensor
Elastic Energy Density
Let
then
U
1
C e e
2
1
U
C e C e
2
e
C
1
C C
2
1
C C e C e
2
C C
Landau’s notations:
1
U Ci j k l ui j uk l
2
1
C u u
2
1
C e e
2
i j
eii
for
1
ei j
i j
2
1, 2,3
for
u e
4,5,
6
1 u u j
ui j i
2 x j xi
uii
u
ui j u ji
Elastic Stiffness Constants for Cubic Crystals
Invariance under reflections xi → –xi C with odd numbers of like indices vanishes
Invariance under C3 , i.e.,
x yzx
x z y x
x z y x
x y z x
All C i j k l = 0 except for (summation notation suspended):
Ciiii C1111
Ciik k C1122
C C11
C C12
Ci k ik C1212
, 1, 2,3
C C44
1
1
U C11 e12 e22 e32 C12 e1e2 e2 e3 e3e1 C44 e42 e52 e62
2
2
1 C11
2 C12
3 C12
4 0
5 0
6 0
C12
C12
0
0
C11
C12
0
0
C12
0
C11
0
0
C44
0
0
0
0
0
C44
0
0
0
0
0 e1
0 e2
0 e3
0 e4
0 e5
C44 e6
4,5, 6
C11 C12 C12
C12 C11 C12
C12 C12 C11
0
0
0
0
0
0
0
0
0
where
S11
0
0
0
C44
0
0
0
0
0
0
C44
0
1
0
S11
0
S12
S12
0
0
0
0
0
C44
0
C11 C12
C11 2C12 C11 C12
S11 S12
1
C11 C12
S12
S11
S12
0
0
0
S12
S12
S11
0
0
0
S12
0
0
0
S44
0
0
0
0
0
0
S44
0
0
0
0
0
0
S44
C12
C11 2C12 C11 C12
S11 2S12
1
C11 2C12
S44
1
C44
Bulk Modulus & Compressibility
1
1
U C11 e12 e22 e32 C12 e1e2 e2 e3 e3e1 C44 e42 e52 e62
2
2
Uniform dilation:
e1 e2 e3
e4 e5 e6 0
3
δ = Tr eik = fractional volume change
U
B
1
C11 2C12 2
6
1
B2
2
1
C11 2C12 = 1/κ
3
B = Bulk modulus
κ = compressibility
U
p
See table 3 for values of B & κ .
1 V
V p
2 U p V p
B
V
2
Elastic Waves in Cubic Crystals
Newton’s
2nd
2 ui i k
2
t
xk
law:
ik Cik jl u jl
→
don’t confuse ui with uα
u jl
2 ul
2 ui
2 u j
1
2 Ci k jl
Ci k jl
x x x x
t
xk
2
k
l
k j
2 ul
Ci k jl
xk x j
2 u3
2 u3
2 u1
2 u1
2 u2
2 u2
2 u1
2 u1
2 C1111 2 C1122
C1133
C1212
C1221 2 C1313
C1331 2
t
x1
x1x2
x1x3
x2x1
x2
x3x1
x3
2 u2
2 u2 2 u1 2 u3 2 u1
2 u3
2 u1
C1111 2 C1122
2
2
C1212
x1
x1x2 x1x3
x2x1 x2 x3x1 x3
Similarly
2 u2
2 u1 2 u1
2 u3
2 u1
2 u1
2 C11 2 C12 C44
C44 2 2
t
x1
x
x
x
x
1
3
1 2
x2 x3
2 u3
2 u2 2 u2
2 u2
2 u2
2 u1
2 C11 2 C12 C44
C44 2
2
t
x2
x
x
x
x
x
x
2
1
3
2 3
1
2 u2
2 u3 2 u3
2 u3
2 u3
2 u1
2 C11 2 C12 C44
C44 2 2
t
x3
x
x
x
x
x1
3 1
x2
3 2
Dispersion Equation
2 ui
2 ul
2 Cik jl
t
xk x j
ui u0 i ei k r t
→
2
il
Ci k j l kk k j
2 u0i Cik jl kk k j u0l
u
2 i l Ci k j l kk k j
2 I C k 0
0l
0
0
dispersion equation
Ci j k Cimn j km kn
Waves in the [100] direction
2 I C k 0
k k 1,0,0
→
Ci j k Cimn j km kn
Ci j k Ci11 j k 2
C1111 C1112
C k k 2 C2111 C2112
C
3111 C3112
C1113
0
C1111
C2113 k 2 0
C2112
0
C3113
0
L
C11
k
T
C44
k
u0 1,0,0
u0 0,1,0
u0 0,0,1
C11 C16
k 2 C61 C66
C
51 C56
0
C11 0
0 k 2 0 C44
0
C3113
0
C15
C65
C55
Longitudinal
Transverse, degenerate
0
0
C44
Waves in the [110] direction
2 I C k 0
k
k
1,1, 0
2
→
Ci j k Cimn j km kn
Ci j k Ci11 j
C1111 C1221 C1122 C1212
k
C k C2121 C2211 C2112 C2222
2
0
0
2
L
T 1
1
C11 C12 2C44 k
2
1
C11 C12 k
2
T 2
C44
k
k2
Ci12 j Ci 21 j Ci 22 j
2
C11 C44
2
k
0
C12 C44
2
C3113 C3223
0
0
u0 1,1,0
u0 1, 1,0
u0 0,0,1
C12 C44
C11 C44
0
Lonitudinal
Transverse
Transverse
0
0
2C44
Prob 3.10