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Power
We all know what P(Type I Error) = is:
= P (rej. H0 / H0 true)
= P(Type II Error)
= P (acc. H0 / H0 false)
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Power is : “the ability to detect out
a small deviation from the
hypothesized value.”
“The test which can detect a
smaller deviation is the more
powerful one.”
What is “power” in terms of , ?
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H0 true
we accept H0
No Error
1-
we reject H0
Type I
error
H0 false
Type II
error
No Error
1-
= P (acc. H0 / H0 false)
a correct
1- = P (rej. H0 / H0 false) = conclusion
1- = “POWER”
(of a test)
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For ANOVA (with one factor) we have,
POWER = f ( , 1, 2,
= significance level
1 = df of numerator (of Fcalc)
2 = df of denominator (of Fcalc)
“Non-Centrality Parameter”
1
R (• j - ••)2
C
= A MEASURE OF HOW DIFFERENT THE
’s ARE FROM ONE ANOTHER
(includes “sample size” by including R & C)
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1-=
Function of a distribution called “noncentral F dist’n” (which is NOT the
same as the regular F distribution)
However, typically, we don’t know or the
values.
So — in practice, you need to “estimate”
from data and “suppose” a value of for
purposes of finding POWER
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Example:
One factor ANOVA with = .05, R = 10, C = 3.
We decide that a working estimate of = 5
and that we (arbitrarily) choose to calculate
(1-) assuming that the ’s are each 1• apart.
(eg., 17 22 27). Then,
=
=
1
5
1
5
10(52 + 02 + 52)
3
(
500
(3)
1/2
1/2
)
12.9
= 2.58
=
5
6
We have
= 2.58
1 = 2 (3 col)
2 = 27 (30-3)
= .05
Now go to “Power Tables”: eg., the one for 1
= 2 (they are “indexed” by the value of 1):
This table is for = .05 and for = .01, and
for various values of 2 and .
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POWER ( , , 2) at 1 = 2
See next page for chart
Our Answer:
( = 30, = .05, = 2.6 )
2
POWER .976
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Figure 3.8 on p.77 (Paul)
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Accept H0 =
All column means are
the same.
All column means are each “<5” apart
with “97.6%” confidence.
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FINDING “REQUIRED”
SAMPLE SIZE
Given C, , 1-, and “” we can find
the minimum sample size required, in
terms of R, the number per column.
= Max (•j) – min (•j)
= Range of ’s
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Sometimes one estimates and
separately; sometimes one estimates the
ratio and not necessarily the separate ,
values.
A common choice of is 2 (i.e., the range
of ’s is 2 standard deviations).
Example:
C= 3
= .05
= .90
= 2
R=8
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Table 3.3 on p.81 (Paul)
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(1-) Confidence Interval (C.I.)
• For • j :
Y. j Z1 / 2
R
• For • j - • k :
(Y. j Y.k ) Z1 / 2
R/2
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If is unknown,
• Replace by
ˆ
MSE
• Replace Z2 by t2 where the df of t is
the df of Error.
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