Transcript Document
“del operator” Gradient: Divergence: Laplacian: Diffusion Equation: ˆ ˆ ˆ i j k x y z w ˆ w w ˆ ˆ w i j k x y z v1 v2 v3 v x y z 2 2 2 f f f 2 f 2 2 x y z 2 h Ss K 2h t “del operator” Gradient: Divergence: Laplacian: Diffusion Equation: ˆ ˆ ˆ i j k x y z w ˆ w w ˆ ˆ w i j k x y z v1 v2 v3 v x y z 2 2 2 f f f 2 f 2 2 x y z 2 h Ss K 2h t “Diffusion Equation” Cartesian Coordinates Cylindrical Coordinates Cylindrical Coordinates, Radial Symmetry ∂h/∂f= 0 Cylindrical Coordinates, Purely Radial Flow ∂h/∂f= 0 ∂h/∂z = 0 h Ss K 2h t 2h + 2h + 2h = S s h K t x2 y2 z2 2 2 1 rh + 1 h + h = S s h r r r r2 2 z2 K t 2h Kr Kr + r r 2 2h + 1 r2 r h r h r 2 h h S + Kz 2 = s z t Ss h =K r t = S h T t Flow beneath Dam Vertical x-section Flow toward Pumping Well, next to river = line source = constant head boundary Plan view River Channel Domenico & Schwartz (1990) Well Drawdown Case 1: Confined aquifier, Constant pumping rate Q, Steady radial flow qv Kh Q / A K h for radial flow r Q h K 2 r m r where m=aquifer thickness h Q r dr dh 2 mK r r h 0 0 Q r0 ln h0 h 2 T r = Drawdown “Equilibrium” eq., or “Theim” equation e.g., Fetter eq 7-38 D&S eq. 5.21 2x 1005 Confined Aquifer Steady Pumping Rate Q Q/2 T = 5 1000 Head, h 995 990 985 -1000 -500 0 Radius, r 500 1000 Potentiometric Surface Q Confined Aquifer m Well Drawdown Case 2: Unconfined aquifier, Constant pumping rate Q, Steady radial flow qv Kh h Q / A K for radial flow r Q h K 2 r h r where m=aquifer thickness h Q r dr h dh 2 K r r h 0 0 Q r0 ln h02 h 2 K r ≠ (Drawdown)2 Unconfined “Theim” equation e.g., Fetter eq 7-39 D&S eq. 5.24 Swindle: 1) Singulatity at r = 0 2) Steady state flux impossible without source this problem requires annular source term 3) Purely radial flow impossible for unconfined case ? ? ? Radial flow h 1 h 1 h 2 r r r D t 2 Transient flow, Confined Aquifer, No recharge Constant pumping rate Q Initial Condition & Boundary conditions: h(r, 0) h0 h(, t ) h0 h Q limr r0 r 2 T for t > 0 Radial flow h 1 h 1 h 2 r r r D t 2 Initial Condition & Boundary conditions: h(r, 0) h0 h Q limr r0 r 2 T h(, t ) h0 Solution: “Theis equation” or “Non-equilibrium Eq.” where Q Drawdown h0 h W (u) 4 T e u W (u) Ei(u) and where for t > 0 W 0 d W 0 r 2S r2 where u = 4tT 4Dt Approximation for t >> 0 2.25 D t Q Drawdown h0 h ln 2 4 T r D&S p. 151 u2 u3 u4 u5 W (u ) Ei(u ) 0.577216 ln u u .... 4 3 3! 4 4! 5 5! W(u) 0.577216 lnu for small u 0.1 ; i.e., long times or small r Pumping of Confined Aquifer Not GW “level” Potentiometric sfc! USGS Circ 1186 Pumping of Unconfined Aquifer USGS Circ 1186 End L21: Now, Spring break! Radial flow h 1 h 1 h 2 r r r D t 2 Initial Condition & Boundary conditions: h(r, 0) h0 h Q limr r0 r 2 T h(, t ) h0 Solution: “Theis equation” or “Non-equilibrium Eq.” where Q Drawdown h0 h W (u) 4 T e u W (u) Ei(u) and where for t > 0 W 0 d W 0 r 2S r2 where u = 4tT 4Dt Approximation for u < 0.1 i.e., t >> 0 2.25 D t Q Drawdown h0 h ln 2 4 T r D&S p. 151 u2 u3 u4 u5 W (u ) Ei(u ) 0.577216 ln u u .... 4 3 3! 4 4! 5 5! W(u) 0.577216 lnu “Euler’s constant” for small u 0.1 ; i.e., long times or small r 8 6 W(u) 4 2 Well Function W(u) = - Ei (-u) 0 W(u) ~ -0.577216 - ln(u) OK f or u < 0.1 -2 0 0.5 1 u 1.5 2 5 "Well Function" W(u) 4 3 W(u) -0.577216 -ln(u) + u -u2/4 2 -0.577216 - ln(u) + u - u 2 /4 3 - u4/96 4 5 + u3+/18 u5/600 u /18 -u /96++u /600 1 0 W(u) -1 -0.577216 - ln(u) -2 0 1 2 3 u 4 5 Potentiometric Surface Q Pumping Well Confined Aquifer Observation Well m Theis Eq. for u < 0.1 Q Drawdown h0 h W (u) 4 T 2.25 D t Q Drawdown h0 h ln 2 4 T r Time Drawdown Method: Use the approximation to calculate T from the head drop in a single observation well at two times, t1 and t2 2.25 D t1 Q h0 h1 ln 2 4 T r 2.25 D t 2 Q h0 h2 ln 2 4 T r Subtract: t1 Q h2 h1 ln 4 T t 2 for u < 0.1 t >> 0 and/or small r 20 Well Function W(u) Drawdown, m 15 y = 5.7248 + 1.2215x R= 1 Assumed values: 10 Q = 0.1 m3/s T = 0.015 m2/s S = 0.0006 D = 25 m2/s 5 Q 2.303 slope 4 T 0 so -5 -10 -5 0 T = 1295 m2/d = 0.015 m2/s 5 Log T, days 10 15 Potentiometric Surface Q Pumping Well Confined Aquifer Observation Well #1 m Observation Well #2 Theis Eq. for t >> 0 Q Drawdown h0 h W (u) 4 T 2.25 D t Q Drawdown h0 h ln 2 4 T r Distance Drawdown Method: Use above to calculate T from head the difference between two different observation wells located at r1 and r2 2.25 D t Q h0 h1 ln 2 4 T r1 Subtract: 2.25 D t Q h0 h2 ln 2 4 T r2 r2 Q h2 h1 ln 2 T r1 for t >> 0 Steady state approximated => “Theim eq” Swindle: 1) Singulatity at r = 0 2) Steady state flux impossible without source this problem requires annular source term 3) Purely radial flow impossible for unconfined case Steady state ? ! ! Swindle: 1) Singulatity at r = 0 2) Steady state flux impossible without source this problem requires annular source term 3) Purely radial flow impossible for unconfined case Steady state ? ! ! Steady Shape Image Wells: No Flow Can duplicate Impermeable Boundary with Pumping Image Well PUMPING WELL PUMPING IMAGE WELL PUMPING WELL WHERE? Image Wells: No Flow Can duplicate Impermeable Boundary with Pumping Image Well PUMPING WELL PUMPING IMAGE WELL PUMPING WELL Image Well Pumping Well t=1 Drawdown 0 t=10 -5 -10 t=100 -15 -20 -4 -2 0 2 4 Radius, r Drawdown Q W u p W ui 4 T Pumping Pumping Well Well t=1 Impermeable Boundary No Flow -5 -10 -15 0 t=10 -5 -10 t=100 -15 DRAWDOWN Drawdown 0 -20 -20 -4 -2 0 2 4 Radius, r Drawdown Q W u p W ui 4 T Initial Condition Pumping @ rate Q1 (note divide) Pumping @ rate Q2 >Q1 USGS Circ 1186 Image Wells: Constant Head Can duplicate Constant Head Boundary with Recharging Image Well PUMPING WELL RECHARGING IMAGE WELL PUMPING WELL Image Wells: Constant Head Can duplicate Constant Head Boundary with Recharging Image Well PUMPING WELL RECHARGING IMAGE WELL PUMPING WELL t = 1, 10, 100 Drawdown Q W u p W ui 4 T Recharge Well (image) Pumping Well Flow toward Pumping Well, next to river = line source = constant head boundary Plan view River Channel Line Source after Domenico & Schwartz (1990) PROBLEMS OF GROUNDWATER USE Overdraft Water table decline Pumpage sometimes many times recharge = Water Mining Phoenix AZ avg 8' drop per year; total drop = 400' (130m) Several CA basins avg 2.5' drop per year; Drop to 6' drop/yr esp. San Joaquin Valley Ogallala aquifer (= High Plains aquifer) Chicago once had artesian wells Water Table Decline or Artesian Pressure Loss >12 m Craig et al Head Decline Craig et al. 1996, after WSP 2275 Cones of depression, Sacramento Valley Criss & Davisson 1996, after DWR 1986 89° 43° 42° 41° 88° 87° Milwaukee Head Decline (1864-1985) Cambrian-OrdovicianAquifer, Chicago-Milwaukee Area Chicago Young et al. (1988) AWRA Mon. 13, p. 55 Santa Cruz River near Tucson AZ 1942 USGS Circ 1186 Santa Cruz River near Tucson AZ 1989 >100’ GW drop USGS Circ 1186 End #23 q v Kh = q m + A t q m 0 u 0 h K 2 = h t Ss Darcy's Law Continuity Equation Steady flow, no sources or sinks Steady, incompressible flow K T Diffusion Eq.,where = D Ss S S y h h h = h + h K t x x y y Boussinesq Eq. for unconfined flow FLOW NETS Impermeble Boundary Constant Head Boundary Water Table Boundary after Freeze & Cherry Pumping Well Boundary Impermeable No Flow Drawdown t=1 t =1 0 t =10 -5 -10 t =100 -15 t=10 t=100 -20 -4 -2 0 2 4 Radius, r Drawdown Q W u p W ui 4 T Santa Cruz River Martinez Hill, South of Tucson AZ 1942 Cottonwoods, Mesquite 1989 >100’ GW drop USGS Circ 1186 Theis Eq. for t >> 0 Q Drawdown h0 h W (u) 4 T 2.25 D t Q Drawdown h0 h ln 2 4 T r Time Drawdown Method: Use approx. to calculate T from the head drop in the observation well at two times, t1 and t2 t1 Q h2 h1 ln 4 T t 2 for t >> 0 Distance Drawdown Method: Use above to calculate T from head difference between two observation wells located at r1 and r2 r2 Q h2 h1 ln 2 T r1 for t >> 0 Steady state approximated => “Theim eq”