Transcript Slide 1
Stoichiometry By: Taylor Sirch Period 8 Here’s the question! Silver nitrate and sodium phosphate are reacted in equal amounts of 200. g each. How many grams of silver phosphate are produced? What’s to do first? Set Up An Equation Turn off the computer Do a mole to mole conversion Wrong!!! Go Back Good Job! …but what is the correct equation? AgNO₃ + Na₃PO₄ → Ag₃PO₄ + NaNO₃ AgNO₄ + Na₄PO₃ → Ag₄PO₃ + NaNO₄ FeNo₃ + Cl₃PO₄ → Fe₃PO₄ + ClNO₃ Correct! Now balance it! AgNO₃ + Na₃PO₄ → Ag₃PO₄ + NaNO₃ 3AgNO₃ + 4Na₃PO₄ → Ag₃PO₄ + 6NaNO₃ 3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃ Great! Now tell me, what kind of problem is this? A regular one Limiting reagent Yes, limiting reagent! Okay what’s the first step? GFM 1 ---------------------200. g AgNO₃ 200. g AgNO₃ ---------------------1 1 ----------------------200. g Na₂PO₄ 200. g Na₂PO₄ --------------------1 Right. What’s the next step? 200. g AgNO₃ -----------------1 X 200. g Na₂PO₄ ------------------- X 1 Mole to mole conversion GFM Gram to Liters conversion Wonderful! Next..? 200. g AgNO₃ -----------------1 1 mol -------------X X 169.9 g AgNO₃ 200. g Na₂PO₄ 1 mol ------------------- X --------------- X 1 164 g Na₃PO₄ Done! Mole to mole conversion Multiply by 6.02 x 10 to the 23 You’re on a roll! Neeexxxtt. 200. g AgNO₃ -----------------1 X 1 mol AgNO₃ -------------- X 169.9 g AgNO₃ 200. g Na₂PO₄ 1 mol Na₃PO₄ X --------------------------------- X 1 164 g Na₃PO₄ Okay, now we’re done. 1 mol Ag₃PO₄ -----------------3 mol AgNO₃ 1 mol Ag₃PO₄ -------------------1 mol Na₃PO₄ One more GFM Convert to molecules So close! This is the answer 200. g AgNO₃ -----------------1 X 200. g Na₂PO₄ ------------------- X 1 1 mol AgNO₃ -------------169.9 g AgNO₃ 1 mol Na₃PO₄ --------------164 g Na₃PO₄ 1 mol Ag₃PO₄ X ------------------ X 3 mol AgNO₃ X 1 mol Ag₃PO₄ -------------------1 mol Na₃PO₄ 418.7 g Ag₃PO₄ -------------------------1 mol Ag₃PO₄ 418.7 g Ag₃PO₄ X -------------------------1 mol Ag₃PO₄ Solve How many grams of silver phosphate are produced? 675 g 511 g 164 g You won!