Transcript Document

State “exponential growth” or “exponential decay”
(no calculator needed)
a.) y = e2x
k > 0, exponential growth
c.) y = 2–x
b>1 so growth,
but reflect over y-axis, so decay
Pre-Calculus
b.) y = e–2x
k < 0, exponential decay
d.) y = 0.6–x
0<b<1 so decay,
but reflect over y-axis, so growth
1/3/2007
Characteristics of a Basic Exponential Function:
Domain: ( - ,  )
Range:
( 0,  )
Continuity: continuous
Symmetry: none
Boundedness: b = 0
Asymptotes:
Extrema:
End Behavior: lim f(x)
=
x

lim f(x) =
x-
0
Pre-Calculus
none
y=0
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Pre-Calculus
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Question
Use properties of logarithms to rewrite the
expression as a single logarithm.
log x + log y
1/5 log z
log x + log 5
2 ln x + 3 ln y
ln y – ln 3
4 log y – log z
ln x – ln y
4 log (xy) – 3 log (yz)
1/3 log x
3 ln (x3y) + 2 ln (yz2)
Pre-Calculus
1/3/2007
Change of Base Formula
for Logarithms
loga x log x ln x
logb x 

or
loga b log b ln b
Pre-Calculus
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“the” exponential function
the “natural base”
2.718281828459 (irrational, like )
Leonhard Euler (1707 – 1783)
f(x) = a • e kx
for an appropriately chosen real number, k, so ek = b
exponential growth function
exponential decay function
Pre-Calculus
1/3/2007
State “exponential growth” or “exponential decay”
(no calculator needed)
a.) y = e2x
k > 0, exponential growth
c.) y = 2–x
b>1 so growth,
but reflect over y-axis, so decay
Pre-Calculus
b.) y = e–2x
k < 0, exponential decay
d.) y = 0.6–x
0>b>1 so decay,
but reflect over y-axis, so growth
1/3/2007
Rewrite with e; approximate k to the nearest tenth.
a.) y = 2x
e? = 2
y = e0.7x
Pre-Calculus
b.) y = 0.3x
e? = 0.3
y = e–1.2x
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Characteristics of a Basic Logistic Function:
Domain: ( - ,  )

Range:
( 0, 1 )
Continuity: continuous









Symmetry: about ½, but not odd or even

Boundedness: B = 0, b = 0
Asymptotes:
y = 0, 1
Extrema:
End Behavior:
lim f(x) =
x-
0
lim f(x) =
x
1
Pre-Calculus
none
1/3/2007
Based
on
exponential
logistic
growth
growth
models,
will
Mexico’s
will
What
Whichare
model
the
maximum
– exponential
sustainable
ormodels,
logistic
populations
– isMexico’s
more valid
for the
in
population
surpass
of the U.S. and if so, when?
this
two
case?
countries?
Justify
yourthat
choice.
Pre-Calculus
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Logarithmic Functions
inverse of the exponential function
logbn = p
bp = n
logbn = p iff bp = n
find the power
=5
2? = 32
=0
3? = 1
=½
4? = 2
=1
5? = 5
=½
Pre-Calculus
2? = 2
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Basic Properties of Logarithms
(where n > 0, b > 0 but ≠ 1, and p is any real number)
Example
logb1 = 0 because b0 = 1
log51 = 0
logbb = 1 because b1 = b
log22 = 1
logbbp = p because bp = bp
log443 = 3
blogbn = n because logbn = logbn
6log611 = 11
Pre-Calculus
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Evaluating Common Log Expressions
Without a Calculator:
Pre-Calculus
With a Calculator:
log 100 = 2
log 32.6 = 1.5132176
log 710 = 1/7
log 0.59 = –0.22914…
10 log 8 = 8
log (–4) = undefined
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Solving Simple Equations with
Common Logs and Exponents
Solve:
10 x = 3.7
Pre-Calculus
log x = – 1.6
x = log 3.7
x = 10 –1.6
x ≈ 0.57
x ≈ 0.03
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Evaluating Natural Log Expressions
Without a Calculator:
With a Calculator:
ln 3e = 1/3
ln 31.3 ≈ 3.443
log e7 = 7
ln 0.39 ≈ – 0.9416
e ln 5 = 5
Pre-Calculus
ln (–3) = undefined
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Solving Simple Equations with
Natural Logs and Exponents
Solve:
ln x = 3.45
Pre-Calculus
ex = 6.18
x = e 3.45
x = ln 6.18
x ≈ 31.50
x ≈ 1.82
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Logarithmic Functions
ln x
1

 ln x
ln3 ln3
≈ 0.91 ln x
•vertical shrink by 0.91
ln x
1

 ln x ≈ – 0.91 ln x
ln(1/ 3) ln(1/ 3)
•reflect over the x-axis
•vertical shrink by 0.91
log1/ b x   logb x
Pre-Calculus
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Graph the function and state its domain and range:
f(x) = log4x
0.721 ln x
Vertical shrink by 0.721
f(x) = log5x
0.621 ln x
Vertical shrink by 0.621
f(x) = log7(x – 2)
0.514 ln (x – 2)
Vertical shrink by 0.514, shift right 2
f(x) = log3(2 – x)
Pre-Calculus
0.091 ln (–(x – 2)
Vertical shrink by 0.091
Reflect across y-axis
Shift right 2
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Logarithmic Functions
one-to-one functions
u=v
2x = 2 5
x=5
log22x = log27
x = log27
ln7

 2.81
ln 2
isolate the exponential expression
take the logarithm of both sides and solve
Pre-Calculus
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Newton’s Law of Cooling
An object that has been heated will cool to the temperature of the
medium in which it is placed (such as the surrounding air or water).
The temperature, T, of the object at time, t, can be modeled by:
T(t)  Tm  T0  Tm ekt
where Tm = temp. of surrounding medium
T0 = initial temp. of the object
Example: A hard-boiled egg at temp. 96 C is placed in 16 C water to
cool. Four (4) minutes later the temp. of the egg is 45 C.
Use Newton’s Law of Cooling to determine when the egg
will be 20 C.
Pre-Calculus
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Compound Interest
Interest Compounded Annually
A = P (1 + r)t
A = Amount
P = Principal
r = Rate
t = Time
Interest Compounded k Times Per Year
A = P (1 + r/k)kt
k = Compoundings Per Year
Interest Compounded Continuously
A = Pert
Pre-Calculus
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Annual Percentage Yield
Annual Percentage Yield
APY = (1 + r/k)k – 1
Compounded Continuously
APY = er – 1
Pre-Calculus
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Annuities
Future Value of an Annuity
(1  i)  1
FV  R
i
n
R = Value of Payments
i = r/k = interest rate per compounding
n = kt = number of payments
# 11
(p. 324)
Pre-Calculus
$14,755.51
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Annuities
For loans, the bank uses a similar formula
Present Value of an Annuity
1  (1  i)
PV  R
i
n
R = Value of Payments
i = r/k = interest rate per compounding
n = kt = number of payments
Pre-Calculus
1/3/2007
Annuities
1  (1  i)
PV  R
i
n
If you loan money to buy a truck for $27,500, what are the monthly payments if the annual percentage rate (APR) on the loan is 3.9% for 5 years?
  0.039  12(5) 
 1 1


12 



27500  R


0.039


12


Pre-Calculus
 1  0.8231
27500  R 

 0.00325 
R  $505.29
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