Transcript Slide 1

NAZARIN B. NORDIN
[email protected]
What you will learn:
• Strength, elasticity, ductility, malleability,
brittleness, toughness, hardness
• Ferrous/ non-ferrous metals, tensile stress,
yield stress, shear force, percentage of
elongation and percentage of reduction in
plain carbon steel, shear force, bending
moment and fatigue test
7.1 Strength, elasticity, ductility, malleability,
brittleness, toughness, hardness
7.2 Ferrous/non-ferrous metals, tensile stress,
yield stress, shear force, percentage of
elongation, percentage of reduction in plain
carbon steel, shear force, bending moment
and fatigue test
Strength of materials
• Definition: the strength of a material is its
ability to withstand an applied stress without
failure
• For practical purposes, components are
designed to withstand forces and loads that a
device is designed for and, so long as the
instructions for use and maintenance, such as
safe loads and tightening torques, are
observed, problems should not be
experienced.
Elasticity
• Definition:
the tendency of a body to return to
its original shape after it has been
stretched or compressed.
Other terms used in describing materials
• Hardness
• Toughness
Hardness
• A hard material is one that resists
indentation or abrasion by
another material.
Toughness
• A material is said to be tough when a
large amount of energy is required to
fracture it.
Brittleness
• Materials that break without undergoing
local distortion and are unable to
withstand sharp blows are said to be
brittle. Most types of cast iron are brittle.
Ductility
• A material that can be drawn out by
tensile force is said to be ductile. The
steel sheet that is used in the
construction of motor car panels is of a
type known as deep drawing steel and
this is a ductile material.
Malleability
• Metals that can be hammered and bent
without cracking are said to be
malleable. Lead is an example of a
malleable material.
Non-ferrous metals
• These are mainly alloys that contain no iron.
Commonly used non-ferrous alloys are those
made from copper, lead, tin, aluminium or
magnesium. Non-ferrous alloys are used
extensively in automotive engineering.
Stress
• Forces that tend to stretch, or pull something
apart, are known as tensile forces and they
produce two important effects:
• 1. In trying to pull the bolt apart, internal
resisting forces are created and these internal
forces are known as stress.
• 2. The length of the bolt will increase, and this
change in the bolt’s dimensions is known as
strain.
• Stress is calculated by dividing the applied force
by the cross-sectional area of the bolt.
• Stress = Perpendicular Force/Cross-sectional area
Types of stress
• There are three basic forms of stress:
– 1. tensile stress;
– 2. compressive stress;
– 3. shear stress – torsional stress is a form of shear
stress.
Examples of stress measure
• Example 1: A cylinder head bolt with an effective
diameter of 15mm carries a tensile load of 10 kN.
Calculate the tensile stress in the bolt.
• Example 2: A connecting rod has a crosssectional area of 200mm2 and it carries a
compressive force of 2.4 tonnes (in N).
Calculate the compressive stress in the
connecting rod.
• Example 3: The hand brake linkage shown in Figure
carries a tensile force of 600 N. Calculate the shear
stress in the clevis pin, which is 12mm in diameter.
• In this case the shearing action is attempting to shear
the clevis pin across two cross-sectional areas.
• Example 4: A propeller shaft coupling of a
truck is secured by four bolts of 14 mm
diameter that are equally spaced at a radius of
50mm from the centre of the propeller shaft.
Calculate the shear stress in each bolt when
the shaft is transmitting a torque of 500 N.m.
•
Strain
When a load is applied to a metal test bar a change
of shape takes place. A tensile load will stretch the
bar and a compressive load will shorten it. This
change of shape is called strain. The three basic
types of strain are shown in Figure
Example strain measure
• A steel rod 200mm in length stretches by
0.12mm when it is subjected to a tensile load
of 2 tonnes. Determine the strain.
• Solution
Strain = change in length/original length
= 0.12mm/200mm
Tensile strain in the steel rod = 0.0006
Note: strain does not have any units.
Stress- Strain graph and Hooke’s Law
Stress- Strain graph for mild steel