Surface Area Word Problems

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Transcript Surface Area Word Problems

Please hand in your Surface Area of 3D objects worksheets at the front of the class Find a partner and sit next to your partner at a table

Math 10 A&W – Class Starter

Answering Word Problems

Ask yourself the following question

: What approach do I take to answering a word problem in math class?

Discuss the question with your partner, in 3 minutes I will ask you to share your approach with the class.

Ex: I read the question at LEAST twice before starting the problem

Answering Word Problems

With your partner, come to the front board and share your strategies to answering word problems If you agree with another group, write your initials next to other strategies

Questions to Ask yourself

1. What is the question asking me to do? 2. What information is the question giving me? 3. Is all the information I’m given relevant?

4. What approach/strategy should I take to find an answer?

5. Is there anything in my data booklet that could help?

Word Problems Practice

1. Take out your Data Booklet and collect a ruler, calculator and at least 2 pieces of paper 2. One partner will sit facing the board the other with their back to the board (do not turn to face the projection at any time) 3. The partner facing the board will use verbal cues to guide his/her partner 4. The partner facing the board is NOT allowed to write or use ANY visual cues (i.e. pointing) 5. The with the back to the board will solve the problem with the guidance of their partner

Easy to Hard

We will start nice and easy… Please start by drawing the object Please show ALL work and calculations

Partner 1

Find the perimeter of a rectangle with a length of 5 m and a width of 8 m.

P = 5m + 5m + 8m + 8m = 26m

Partner 2

Find the circumference of a circle with a radius of 2 m’s.

C = π x 2 x r C = π x 2 x 2m = 12.6m

SWITCH

Partner 1

What is the area of a rectangle with perimeter 177.6 mm and base length 39.9 mm?

P = 2 x W + 2 x L W = 48.9 mm A = W x L A = 48.9 mm x 39.9 mm =1951.1 mm

Partner 2

If the base of a rectangle is 22 cm and the area is 484 cm 2 the height of the rectangle?

, what is A = b x h ÷ 2 H = A x 2 ÷ b H = 484 cm 2 x 2 ÷ 22 cm = 44 cm

SWITCH

Partner 1

Find the area of a pie that measures 20 cm’s from one side of the pie through the middle to the other side.

r = D ÷ 2 R = 20 cm ÷ 2 = 10 cm A = π x r 2 = π x (10 cm) 2 = 314.2 cm 2

Partner 2

Find the 2-D area of Ancient Redwood tree stump that measures 3.14 m around the stump.

C = 3.14 m r = C ÷ (2 x π) = 3.14 m ÷ (2 x π) = 0.5 m A = π x r 2 = π x (0.5 cm) 2 = 0.8 cm 2

SWITCH

Partner 1

Find the surface area of the cinder-cone volcano shown to the right.

Ans: 35.9 mi 2

Partner 2

The local college has a greenhouse that is shaped like a square pyramid, as shown below. The lateral faces of the greenhouse are made of glass. Find the surface area of the glass on the greenhouse.

Ans: 297 m 2

SWITCH

Partner 1

The top and sides of the cake shown below are to be covered in frosting. Calculate the area that will be covered with frosting.

Ans: 192 in 2

Partner 2

Phil is planning to shingle the triangular roof on his barn shown below. How many square feet will he be shingling?

Ans: 2918.4 ft 2

SWITCH

Partner 1

The top of a costume hat is shaped like a triangular pyramid, as shown below. How much black felt is needed to cover the sides of the pyramid?

Ans: 148.5 in 2

Partner 2

When the butterfly net shown below is fully extended, it forms the shape of a cone with a diameter of 12 inches and a slant height of 26 inches. Calculate the amount of mesh material needed to make the butterfly net. (note: the opening of the cone does not require mesh.

Ans: 490.0 in 2

SWITCH

Partner 1

Jim has been hired to make a jewelry box. If the box is 12 inches long, 6 inches deep and 9 inches tall, how much veneer will it take to cover the all the exterior except the base, assuming no waste. Ans: 396.0 in 2

Partner 2

A rectangular pyramid in Egypt has a base of 80 meters, a height of 60 meters and a slant height of 72 meters. What is the surface area of the pyramid assuming it was floating about the ground!

Ans: 12240 m 2

Challenging 3D Objects

Collect the Worksheet for Challenging 3D Objects Find the Surface Area (Area of surface exposed) I will collect this at the end of class and you will be allowed time to work through the problems next class