Combined Gas Law
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Transcript Combined Gas Law
Combined Gas Law
The combined gas law combines
Boyle’s Law and Charles’ Law
Combined Gas Law
Boyle’s Law P1V1 = P2V2
Charles’ Law
V1
V2
=
T1
T2
Combined Gas Law
P1V1 P2V2
=
T1
T2
Combined Gas Law
For
example: If I initially have a gas
at a pressure of 12 atm, a volume of
23 L and a temperature of 200 K,
then I raise the pressure to 14 atm
and increase the temperature to 300
K, what is the new volume of the
gas?
Combined Gas Law
Begin
by converting to Kelvin. It is
not necessary in this problem.
Combined Gas Law
Next, write down the information you
know and want to know.
P1 =
V1 =
T1 =
P2 =
V2 =
T2 =
Combined Gas Laws
Next, write down the information you
know and want to know.
P1 = 12 atm
V1 =
T1 =
P2 =
V2 =
T2 =
Combined Gas Law
Next, write down the information you
know and want to know.
P1 = 12 atm
V1 = 23 L
T1 =
P2 =
V2 =
T2 =
Combined Gas Law
Next, write down the information you
know and want to know.
P1 = 12 atm
V1 = 23 L
T1 = 200K
P2 =
V2 =
T2 =
Combined Gas Law
Next, write down the information you
know and want to know.
P1 = 12 atm
V1 = 23 L
T1 = 200K
P2 = 14 atm
V2 =
T2 =
Combined Gas Law
Next, write down the information you
know and want to know.
P1 = 12 atm
V1 = 23 L
T1 = 200K
P2 = 14 atm
V2 = x
T2 =
Combined Gas Law
Next, write down the information you
know and want to know.
P1 = 12 atm
V1 = 23 L
T1 = 200 K
P2 = 14 atm
V2 = x
T2 = 300 K
Combined Gas Law
Now plug in the information you have . . .
P1V1 P2V2
=
T1
T2
12atm(23L) 14 atm (x)
=
200K
300K
Combined Gas Law
Cross multiply to solve for x
12atm(23 L)(300K) = 200 K (14L)(x)
82800 = 2800x
x = 29.57 Liters