Loop Transfer Function
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Transcript Loop Transfer Function
Imaginary
-1 is called the
-1
critical point
Plane of the Open Loop
Transfer Function
B (i )
Stable
Unstable
-B(iw)
B(0)
Real
B(iw)
Professor Walter W. Olson
Department of Mechanical, Industrial and Manufacturing Engineering
University of Toledo
Loop Transfer Function
Outline of Today’s Lecture
Review
Partial Fraction Expansion
real distinct roots
repeated roots
complex conjugate roots
Open Loop System
Nyquist Plot
Simple Nyquist Theorem
Nyquist Gain Scaling
Conditional Stability
Full Nyquist Theorem
Partial Fraction Expansion
When using Partial Fraction Expansion, our objective is to
turn the Transfer Function
K i 1 ( s zi ) i 1 ( s 2 iwni s wni 2 )
m
G( s)
k
s r i 1 ( s pi ) i 1 ( s 2 iwni s wni 2 )
n
q
into a sum of fractions where the denominators are the
factors of the denominator of the Transfer Function:
Bq ( s)
K A1 ( s ) A2 ( s )
An ( s )
B1 ( s )
G( s) r
...
...
s
s p1 s p2
s pn s 2 1wn1s wn12
s 2 qwnq s wnq 2
Then we use the linear property of Laplace Transforms and
the relatively easy form to make the Inverse Transform.
Case 1: Real and Distinct Roots
G( s)
...
s i 1 ( s pi )
n
Put the transfer function in the form of
G( s)
a0
a
a2
an
1
...
s s p1 s p2
s pn
where the ai are called the residue at the pole pi
and determined by
a0 sG s s 0
a3 ( s p3 )G ( s ) s p
3
a1 ( s p1 )G s s p
...
1
a2 s p2 G s s p
2
an s pn G s s p
n
Case 1: Real and Distinct Roots
Example
G( s)
s 2 s 4
s s 1 s 5
a0
a
a
1 2
s s 1 s 5
s 2 s 4 a0 s 1 s 5 a1s s 5 a2 s s 1
G( s)
s 2 6s 8 a0 s 2 6s 5 a1 s 2 5s a2 s 2 s
a0 a1 a2 1
a1 a2 0.6
a1 0.75
6
a
5
a
a
6
0
1
2
5
a
a
3.6
a2 0.15
5a 8 a 1.6 1 2
0
0
1.6 0.75 0.15
s s 1 s 5
g (t ) 1.6 0.75e t 0.15e 5t
G( s)
Case 2: Complex Conjugate Roots
G( s)
...
... i 1 ( s 2 2 iwi s wi 2 )
q
We can either solve this using the method of matching coefficients
which is usually more difficult or by a method similar to that
previously used as follows:
s 2 1w1s w12 s 1w1 w1 12 1 s 1w1 w1 12 1
then the term
A( s )
a1
a2
s 2 2 iwi s wi 2 s 1w1 w1 12 1 s 1w1 w1 12 1
proceeding as before
s w w
1 G s
a1 s 1w1 w1 12 1 G s s w w
a2
1 1
1
12
1 1
1
12 1
s 1w1 w1 12 1
Case 3: Repeated Roots
G( s)
...
...( s pi ) n ...
Form the equation with the repeated terms expanded as
G ( s ) ...
an
an 1
a1
...
...
n
n 1
( s pi )
( s pi )
s pi
an ( s pi ) n G ( s ) s p
i
d
( s pi ) n G s
s p
ds
d2
an 2 2 ( s pi ) n G s
s p
ds
d3
an 3 3 ( s pi ) n G s
s p
ds
...
an 1
d n 1
a1 n 1 ( s pi ) n G s
s p
ds
Heaviside Expansion
n
A bi bi t
A s
Heaviside Expansion Formula: L1
e
B s i 1 d
B bi
ds
where bi are the n distinct roots of B( s )
15( s 2)
s( s 2 2 s 25)
Roots of the denominator are 0, 1 i 4.899, and 1 i 4.899
Example:
G( s)
d
B s ( s 2 2 s 25) 2 s 2 2 s 3s 2 4 s 25
ds
3
15( s 2)
si t
1
L G s 2
e
i 1 3s 4 s 25 s si
g (t )
30 0t
15. 73.485i 1i 4.899 t
15. 73.485i 1i 4.899 t
e
e
e
25
48.00 9.798i
48.00 9.798i
g (t ) 1.2 0.6 1.408i e
1i 4.899 t
0.6 1.408i e
1i 4.899 t
Loop Nomenclature
Reference
Input
R(s)
Prefilter
F(s)
+-
Error
signal
E(s)
Disturbance/Noise
Controller
C(s)
Open Loop
Signal
B(s)
+-
Plant
G(s)
Output
y(s)
Sensor
H(s)
The plant is that which is to be controlled with transfer function G(s)
The prefilter and the controller define the control laws of the system.
The open loop signal is the signal that results from the actions of the
prefilter, the controller, the plant and the sensor and has the transfer function
F(s)C(s)G(s)H(s)
The closed loop signal is the output of the system and has the transfer function
F ( s)C ( s)G( s)
1 C ( s )G( s ) H ( s )
Closed Loop System
Input
r(s)
++
Error
signal
E(s)
Controller
C(s)
Open Loop
Signal
B(s)
Plant
P(s)
Output
y(s)
-1
The closed loop transfer function is
nc s n p s
dc s d p s
nc s n p s
C s P s
y( s)
G yr ( s )
n s n p s d c s d p s nc s n p s
r( s) 1 C s P s
1 c
dc s d p s
The characteristic polynomial is
( s ) 1 C s P s d c s d p s nc s n p s
For stability, the roots of ( s ) must have negative real parts
While we can check for stability, it does not give us design guidance
Note: Your book uses L(s) rather than B(s)
To avoid confusion with the Laplace transform, I will use B(s)
Open Loop System
Input
r(s)
++
Error
signal
E(s)
Controller
C(s)
Open Loop
Signal
B(s)
Sensor
-1
Plant
P(s)
Output
y(s)
nc s n p s
b( s )
The open loop transfer function is B( s )
C s P s
r( s)
dc s d p s
If in the closed loop, the input r(s) were sinusoidal and if the signal were
to continue in the same form and magnitude after the signal were disconnected,
it would be necessary for
nc s n p s
B(iw0 )
1
dc s d p s
Open Loop System
Nyquist Plot
Error
signal
E(s)
Input
r(s)
++
Controller
C(s)
Open Loop
Signal
B(s)
nc s n p s
B(iw0 )
1
dc s d p s
Imaginary
-1
B (i )
B(-iw)
Sensor
-1
Plane of the Open Loop
Transfer Function
B(0)
B(iw)
-1 is called the
critical point
Plant
P(s)
Real
Output
y(s)
Simple Nyquist Theorem
Error
signal
E(s)
Input
r(s)
++
Controller
C(s)
Open Loop
Signal
B(s)
Imaginary
-1 is called the
-1
critical point
Plant
P(s)
Sensor
-1
-B(iw)
Plane of the Open Loop
Transfer Function
B (i )
Stable
B(0)
Real
B(iw)
Unstable
Simple Nyquist Theorem:
For the loop transfer function, B(iw), if B(iw) has no poles in the right
hand side, expect for simple poles on the imaginary axis, then the
system is stable if there are no encirclements of the critical point -1.
Output
y(s)
Example
Plot the Nyquist plot for B( s)
B (iw )
1
iw iw 2wi 2
2
B (0) i
1
s s 2 2s 2
-1
Re
B (1i ) 0.4 0.2i
B (1i ) 0.4 0.2i
B (2i ) 0.1 0.05i
B (2i ) 0.1 0.05i
Im
Stable
Example
Plot the Nyquist plot for B( s)
10
s s 2s 2
Im
20 20 10w i
B(iw )
4
2
w
4
iw iw 2wi 2
10
B(0) i
B(1i ) 4 2i
-1
B( 1i ) 4 2i
B(2i ) 1 0.5i
B( 2i ) 1 0.5i
B(4i ) 0.077 0.135i
B( 4i ) 0.077 135i
Unstable
Re
Nyquist Gain Scaling
The form of the Nyquist plot is scaled by the system gain
B( s )
K
s s 2s 2
Show with Sisotool
Conditional Stabilty
While most system increase stability by decreasing gain,
some can be stabilized by increasing gain
Show with Sisotool
K (0.25s 2 0.12 s 1)
B( s )
s 1.69 s 2 1.09 s 1
Full Nyquist Theorem
Assume that the transfer function B(iw) with P poles has
been plotted as a Nyquist plot. Let N be the number of
clockwise encirclements of -1 by B(iw) minus the
counterclockwise encirclements of -1 by B(iw)Then the
closed loop system has Z=N+P poles in the right half plane.
Show with Sisotool
B( s )
K ( s 5 2i )( s 5 2i )
s s .5 2i s .5 2i s 2 6i s 2 6i
Summary
Im
Open Loop System
Nyquist Plot
Simple Nyquist Theorem
Nyquist Gain Scaling
-1
Conditional Stability
Full Nyquist Theorem
Unstable
Next Class: Stability Margins
Re