Transcript Monday, Oct. 15, 2012
• • • • • •
PHYS 3313 – Section 001 Lecture #12
Monday, Oct. 15, 2012 Dr.
Jaehoon Yu The Schrödinger Wave Equation Time-Independent Schrödinger Wave Equation Probability Density Wave Function Normalization Expectation Values Operators – Position, Momentum and Energy Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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Announcements
• Reminder Homework #4
– End of chapter problems on CH5: 8, 10, 16, 24, 26, 36 and 47 – Due: This Wednesday, Oct. 17
• Reading assignments
– CH6.1 – 6.7 + the special topic
• Colloquium this week
– 4pm, Wednesday, Oct. 17, SH101 – Drs. Musielak and Fry of UTA Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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Special project #5
Prove that the wave function =A[sin(kx t)+icos(kx t)] is a good solution for the time dependent Schrödinger wave equation. Do NOT use the exponential expression of the wave function. (10 points) Determine whether or not the wave function =Ae |x| satisfy the time-dependent Schrödinger wave equation. (10 points) Due for this special project is Monday, Oct. 22.
You MUST have your own answers!
Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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The Schrödinger Wave Equation
The Schrödinger wave equation in its time-dependent form for a particle of energy E moving in a potential V in one dimension is
i
h
t
h 2 2
m
2
x
2
V
The extension into three dimensions is
i
h
t
h 2 2
m
2
x
2 2
y
2 2
z
2
V
x
,
y
,
z
,
t
• where is an imaginary number Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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Ex 6.1: Wave equation and Superposition
The wave equation must be linear so that we can use the superposition principle to. Prove that the wave function in Schrodinger equation is linear by showing that it is satisfied for the wave equation x,t 1 x,t 2 x,t where a and b are constants and 1 x,t and 2 x,t describe two waves each satisfying the Schrodinger Eq.
t a
1
t
b
2
a
1
b
2
i
h
a
t
1 1
t
h 2 2
m b
t
2 2 1
x
2
V
1
x
x
a
1
b
2
a
1
x
b
2
x i
h
t
2 h 2 2
m
2 2
x
2
V
2 2
x
2
x
a
1
x
b
2
x
a
2 1
x
2
b
2 2
x
2
i
h
t
h 2 2
m
2
x
2
V
Rearrange terms
i
h
t
h 2 2
m
2
x
2
V
i
h
t
h 2 2
m
2
x
2
V
0
i
h
t
i
h
a
1
t
b
2
t
h 2 2
m
a
2 1
x
2
b
2 2
x
2 1
b
2 h
t
1 h 2 2
m
2 1
x
2
V
1 h
t
2 h 2 2
m
2 2
x
2
V
2 0 Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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General Solution of the Schrödinger Wave Equation
The general form of the solution of the Schrödinger wave
equation is given by:
Ae i kx
t
A
cos
kx
t
i
sin
kx
t
• which also describes a wave propergating in the x direction. In general the amplitude may also be complex. This is called the
wave function of the particle
.
The wave function is also not restricted to being real. Only the physically measurable quantities (or
observables
) must be real. These include the probability, momentum and energy.
Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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Ex 6.2: Solution for wave equation
Show that Ae i(kx t) satisfies the time-dependent Schrodinger wave Eq.
x
Ae i kx
t
t
t
Ae i kx
t
iA
e i kx
t
i
x
Ae i kx
t
iAke i kx
t
ik
2
x
2
i
h
t
x i
h The Energy:
E
i
hf
The wave number:
k
ik
x
h
h
2 2 2
h p ik iAke
h 2 2
m
h 2
h i kx
k
2
p
p
h
t
V
Ak
2
e i kx
t
k
2
E
h 2
k
2 2
m p
2 2
m
The momentum:
p
From the energy conservation:
E
So Ae i(kx t)
K
V
p
2
V
2
m
is a good solution and satisfies Schrodinger Eq.
E
V
V
h
k p
2 2
m
0
V
0 Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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0
Ex 6.3: Bad solution for wave equation
Determine x,t Asin(kx t) is an acceptable solution for the time dependent Schrodinger wave Eq.
x
A
sin
kx
x
A
sin
kx
t
t
t
t kA
cos
kx
A
sin
kx
t
t
A
cos
kx
t
2
x
2
i
h
i
h cos
kx
x
cos
t
kA
cos
kx
t
h 2
k
2 2
m
kx
V
sin
t
h 2 2
m
kx
t
k
2
iE k
2
A
sin cos sin
kx
kx
kx
t
t
This is not true in all x and t. So (x,t)=Asin(kx
t
V p
2 2
m k
sin 2
kx
V
sin
t
kx
t) is not an acceptable solution for Schrodinger Eq.
Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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t
Normalization and Probability
The probability P(x) dx of a particle being between x and X + dx was given in the equation
dx
*
dx
• Here * denotes the complex conjugate of The probability of the particle being between x 1 is given by
P
x
2
x
1 *
dx
and x 2 The wave function must also be normalized so that the probability of the particle being somewhere on the x axis is 1.
*
dx
1 Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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Ex 6.4: Normalization
Consider a wave packet formed by using the wave function that Ae 1/ , and between 1/ and 2/ . x , where A is a constant to be determined by normalization. Normalize this wave function and find the probabilities of the particle being between 0 and
Ae
x
Probabilit y density
*
dx
Ae
x
*
Ae
x
dx
A
*
e
x
Ae
x
dx
A
2
e
2
x dx
2 0
A
2
e
2
x dx
2
A
2 2
e
2
x
0
A
Monday, Oct. 15, 2012
Normalized Wave Function
PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu 0
A
2 1
e
11
x
Ex 6.4: Normalization, cont’d
Using the wave function, we can compute the probability for a particle to be with 0 to 1/ and 1/ to 2/ .
e
x
For 0 to 1/ :
P
0 1 *
dx
0 1
e
2
x dx
2
e
2
x
1 0 1 2
e
2 1 0.432
For 1/ to 2/ :
P
1 2 *
dx
1 2
e
2
x dx
2
e
2
x
2 1 1 2
e
4
e
2 0.059
How about 2/ : to ∞?
Monday, Oct. 15, 2012 PHYS 3313-001, Fall 2012 Dr. Jaehoon Yu
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