Transcript Power Point from class (more review for Quiz 1)

1. Solve without a calculator. Be
sure to show your work.
5 + 6(5 • 2 – 14  2)2
5 + 6(10 – 14  2)2
2
5 + 6(10 – 7)
2
5 + 6(3)
5 + 6(9)
5 + 54 = 59
1
2
1 + 2 = 180
2.10x – 10 + 5x + 10 = 180
a) What
do
you
call
1
&
2?
15x = 180
a linear
pair
x = 12
b)m1
if 1= =10x
10x– –1010, 2 = 5x + 10,
Find=m
1. – 10
10(12)
= 110
D
3
E
2C
4
B A
1
F
1
BCF
FCB
FCA
3. Give another name for:
a) CA
CB
AC, or AE
b) AB
c) DC
CD
CD, DF, CF, FD, FC
d) DC
NOT A!
e) ACF
D
3
E
2C
4
A
B
1
F
4. Name:
a) a pair of vertical angles
1 & 3
2 & 4
b) a linear pair 1 & 4 1 & 2
3 & 4 3 & 2
c) 3 collinear points
D,C,F A,B,C
A,B,E A,C,E
B,C,E
5.
1
1 is acute. Find the restrictions on
x.
0 < 6x – 12 < 90
12 < 6x < 102
2 < x < 17
3
2
1
4
1 = 3
6. 1 = 7x + 7,
7x + 7 = 10x – 2
3 = 10x – 2 ,
9 = 3x
Find m 1.
3=x
m 1 = 7x + 7
= 7(3) + 7
= 28
3
2
1
4
7. If m2 = 98,
a) is 1 right, acute, or obtuse?
(1 & 2 are a linear pair, so 1 = 82), acute
b) is 3 right, acute or obtuse?
(2 & 3 are a linear pair, so 3 = 82), acute
c) is 4 right, acute or obtuse?
(2 & 4 are vertical angles, so 4 = 98), obtuse
R
K
M
8. K is the midpoint of RM
RK = 3x + 1,
RK = KM
KM = 5x – 15 , 3x + 1 = 5x – 15
Find RM.
16 = 2x
8=x
RM = 3x + 1 + 5x – 15
= 3(8) +1 + 5(8) – 15
= 50