Transcript Nov 10
LT: I will apply my knowledge of projectile motion to calculate a distance to a target Vocab. Relative motion Projectile motion and relative motion notes Labs: dart gun and Bull’s eye Test Next Tues. Friday will be review Homework: Make sure you are caught up on all labs and homework. A golfer practices driving balls off a cliff into the water below. The cliff is 20 meters tall. He launches the ball at an angle of 30 degrees and a speed of 20m/s. How much time is the ball traveling upward? What is the maximum height of the ball? Vxo=20m/s(cos 30)=17.3m/s › V=0 m/s › Vyo=20m/s(sin 30)=10 m/s › Vy=Vyo-gt so t=Vy-Vy0/-g › -10m/s/-9.8 m/s²=1.02 s Y=Yo +Yot-1/2gt² y=20m + (10m/s)(1.02) – ½ (-9.8)(1.02s)² = 25m