Transcript 141.review

Exam III Review
JH.141
At the explosion point, the momentum of the forward piece is the same as the
momentum before explosion doubling the velocity (since mass is halved)
It also doubles the range. Find time from y motion then use it to find pre-explosion
range then double that range
Key Idea: linear speed at the edge is identical
Way 1: balance torques around the edge of the lower brick
a1: put the mg at the edge (i.e. L/2) this makes this torque zero
a2: put the mg of the top at the edge and support force
mg (a2) = (L/2- a2) mg  a2 = L/4
2mg(a3) = (L/2 – a3) mg  a3 = L/6
Way 2: COM from the right edge is calculated