Case Study 2b

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Transcript Case Study 2b

Case study 2, group B
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
CASE STUDY PRESENTATION
Case number 2 :
Design a Nb-Ti superconducting quadrupole with
a 120mm aperture for the upgrade of the LHC
interaction region operating at 1.9K
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
Our quadrupole design
Case study 2, group B
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
Parameters:
π‘€π‘‘π‘œπ‘‘ = 32π‘šπ‘š
Rutherford cable :
Number of cable layers : 2
π‘€π‘π‘Žπ‘π‘™π‘’ = 16π‘šπ‘š
π‘‘π‘Žπ‘£βˆ’π‘π‘Žπ‘π‘™π‘’ = 1.44π‘šπ‘š
(πΎπ‘’π‘¦π‘ π‘‘π‘œπ‘›π‘’ π‘Žπ‘›π‘”π‘™π‘’ = 0.8°)
𝐢𝑒
= 1.56
𝑆𝐢
βˆ…π‘†π‘‘π‘Ÿπ‘Žπ‘›π‘‘ = 0.8π‘šπ‘š
π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘†π‘‘π‘Ÿπ‘Žπ‘›π‘‘π‘  = 2 × 20
(Rutherford-like cable)
Pitch angle 14.9°
Pitch length = 120 mm
π‘‘π‘Žπ‘£βˆ’π‘π‘Žπ‘π‘™π‘’
π‘€π‘π‘Žπ‘π‘™π‘’
Quadrupole :
π‘€π‘‘π‘œπ‘‘
Compaction:
π‘€π‘–π‘‘π‘‘β„Ž = βˆ’6.67%
π‘‘β„Žπ‘–π‘π‘˜π‘›π‘’π‘ π‘  = βˆ’10.0%
Insulator : π‘‘β„Žπ‘–π‘π‘˜π‘›π‘’π‘ π‘  = 0.1π‘šπ‘š
Filling factor : πœ… = 0.295
Case study 2, group B
Our quadrupole design
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
Gradient as a function of coil width
175
Nb-Ti 1.9 K
150
Gradient (T/m)
125
100
75
50
25
Aperture diameter =120(mm),
Aperture radius = 60(mm)
0
0
20
40
60
80
Coil width (mm)
r=60 mm
100
120
Our choices :
β€’ Gradient = 140(T/m)
β€’ Coil width = 32(mm) / divided in 2 cables of 16(mm)
Our quadrupole design
Case study 2, group B
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
Typical values of pitch angle
Typical values of strand diameters
NbTi Nb3Sn
NbTi Nb3Sn
Our choice : 0.8 mm
Our choice : 14.93°
Flükiger, CAS, Erice (I) 25 April - 4 May 2013
Typical values of Cu/SC ratio
(ratio btw. area of Cu and area of SC material)
Bruzzone, CAS, Erice (I) 25 April - 4 May 2013
Typical values width/thickness compaction
NbTi Nb3Sn
NbTi Nb3Sn
Our choice : Cw = -6.67%
Cth= -10%
Our choice : 1.56
4
Flükiger, CAS, Erice (I) 25 April - 4 May 2013
Bruzzone, CAS, Erice (I) 25 April - 4 May 2013
Load Line Calculation
Case study 2, group B
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
80%
π½π‘ π‘βˆ’π‘œπ‘ = 80%π½π‘ π‘βˆ’π‘ π‘  = 1340𝐴/π‘šπ‘š2
𝐽0βˆ’π‘œπ‘ = 396 𝐴/π‘šπ‘š2
πΊπ‘œπ‘ = 112 𝑇/π‘š
π΅π‘π‘’π‘Žπ‘˜βˆ’π‘œπ‘ = 7.74 𝑇
πΌπ‘œπ‘ = 10.5 π‘˜π΄
Margin :
π΅π‘šπ‘Žπ‘Ÿπ‘”π‘–π‘› = 2.56 𝑇
𝐽𝑠𝑐 = 1330 𝐴/π‘šπ‘š2
Limit temperature : 4 K
Δ𝑇 = 2.1 𝐾
𝑀
= 0.53
π‘Ÿ
πœ† = 1,15
5000
Critical current density Jc (A/mm2)
100 %
Intersection : π΅π‘π‘’π‘Žπ‘˜βˆ’π‘ π‘  = 9.68 𝑇
𝐽𝑠𝑐_𝑠𝑠 = 1680 𝐴/π‘šπ‘š2
π½π‘œβˆ’π‘ π‘  = πœ…π½π‘ π‘βˆ’π‘ π‘  = 495 𝐴/π‘šπ‘š2
π΅π‘π‘’π‘Žπ‘˜βˆ’π‘ π‘ 
𝐺𝑠𝑠 =
= 140𝑇/π‘š
πœ†π‘Ÿ
𝐼𝑠𝑠 = π½π‘œβˆ’π‘ π‘  × π‘†π‘π‘Žπ‘π‘™π‘’ = 13,2 π‘˜π΄
4500
4000
3500
NbTi
1.9 K
Nb3Sn
, 1.9 K
3000
2500
2000
1500
1000
500
0
0 1 2 3 4 5 6 7 8 Field
9 1011121314151617181920
(T)
Comparison with Nb3Sn
Case study 2, group B
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
Same parameters of the cables with Nb3Sn
100 %
π΅π‘π‘’π‘Žπ‘˜βˆ’π‘ π‘  = 13.5 𝑇
𝐽𝑠𝑐_𝑠𝑠 = 2470 𝐴/π‘šπ‘š2
π½π‘œβˆ’π‘ π‘  = 730 𝐴/π‘šπ‘š2
𝐺𝑠𝑠 = 207𝑇/π‘š
𝐼𝑠𝑠 = 19.4 π‘˜π΄
80% :
π½π‘ π‘βˆ’π‘œπ‘ = 1980𝐴/π‘šπ‘š2
𝐽0βˆ’π‘œπ‘ = 584 𝐴/π‘šπ‘š2
πΊπ‘œπ‘ = 166 𝑇/π‘š
π΅π‘π‘’π‘Žπ‘˜βˆ’π‘œπ‘ = 10.8𝑇
πΌπ‘œπ‘ = 15.5 π‘˜π΄
Margin :
π΅π‘šπ‘Žπ‘Ÿπ‘”π‘–π‘› = 3,68 𝑇
π½π‘šπ‘Žπ‘Ÿπ‘”π‘–π‘› = 2720𝐴/π‘šπ‘š2
π‘‡π‘šπ‘Žπ‘Ÿπ‘”π‘–π‘› = 4.6𝐾
Comparison 80% :
NbTi – Vs – Nb3Sn
Ξ”πΊπ‘œπ‘ = 54 𝑇/π‘š
Ξ”π΅π‘šπ‘Žπ‘Ÿπ‘”π‘–π‘› = 1.12 𝑇
Ξ”π½π‘šπ‘Žπ‘Ÿπ‘”π‘–π‘›
= 1400 𝐴/π‘šπ‘š2
Ξ”π‘‡π‘šπ‘Žπ‘Ÿπ‘”π‘–π‘› = 2.5𝐾
Case study 2, group B
Possible Layout
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
Cancel: 𝐡6 , 𝐡10 , 𝐡14 :
sin π‘›πœƒ1 βˆ’ sin π‘›πœƒ2 + sin π‘›πœƒ3 = 0, 𝑛 = [6; 10; 14]
Possible solution:
πœƒπ‘– = [21.6°; 26.1°; 33.7°]
Source : Todesco, USPAS 2012
Case study 2, group B
EM forces and stress at operational conditions
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
Sector approximation
β€’
β€’
β€’
a1 = 0.06 (m)
a2 = 0.0924 (m)
Jo-op = 396 (A/mm2) = 3.96 108 (A/m2)
Fx ο€½ 
Fy ο€½ ο€­
2  0 J 02

2  0 J 02

3  1 12a24 ο€­ 36a14  a1 1 οƒΆ 3 οƒΉ
  ln  οƒ·οƒ·a1 οƒΊ ο€½ 726kN / m
οƒͺ
12  72
a2
 a2 3 οƒΈ 
οƒΆ 3οƒΉ
3  5 ο€­ 2 3 3 1 a14 2 ο€­ 3 a1 3 1  3

οƒ·a1 οƒΊ ο€½ ο€­1520kN / m
a


ln
a

ο€­
2
οƒͺ
2
1

οƒ·
2 οƒͺ 36
12 a2
6
a2
9 2
οƒΈ 
2  0 J 02 3  1 7 a24  9a14 1  a1 4 οƒΆ 3 οƒΉ 1
  _ mid ο€­ plane _ av ο€½ ο€­
  ln  οƒ·οƒ·a1 οƒΊ
ο€½ 614 MPa
οƒͺ

2  36
a2
3  a2 3 οƒΈ  a2 ο€­ a1
170
Stress on mid-plane (MPa)
ο€­ 173.205
175
180
|πœŽπ‘Žπ‘£ | = 614π‘€π‘ƒπ‘Ž
185
190
 midd( r) 195
200
Comparison LHC Dipoles: 150 π‘€π‘ƒπ‘Ž.
205
210
ο€­ 211.885
215
220
0.025
a1
0.03
0.035
r
Radius (m)
0.04
0.045
a2
Dimensioning
Case study 2, group B
FERRAND, G./JECKLIN, N. / PURUSHOTHAMAN, S. / STODEL, M.H. / YUE, W.
90 % of short-sample conditions :
Iron shield: π‘‘π‘–π‘Ÿπ‘œπ‘› ≃
π‘Ÿ2𝐺
2π΅π‘ π‘Žπ‘‘
≃ 280π‘šπ‘š.
Maximum force applied to the collar : πΉπ‘π‘œπ‘™π‘™π‘Žπ‘Ÿ = 2 2𝐹π‘₯
= 2.1 (MN/m).
Strain :
πΉπ‘π‘œπ‘™π‘™π‘Žπ‘Ÿ
πœ– = πœŽπ‘π‘œπ‘™π‘™π‘Žπ‘Ÿ 𝐸 ∝
.
π‘‘π‘π‘œπ‘™π‘™π‘Žπ‘Ÿ
From LHC dipole collars data (including margins):
π‘‘π‘π‘œπ‘™π‘™π‘Žπ‘Ÿβˆ’π‘‘π‘–π‘π‘œπ‘™π‘’ =10 mm for 𝐹π‘₯_π‘‘π‘–π‘π‘œπ‘™π‘’ = 0.7 𝑀𝑁/π‘š.
By analogy, for our quadrupole, 15 (mm) must be
enough, including margins.