Transcript Lesson 7.1

Bell Ringer
1. 𝐴 = 25π‘π‘š2
2. 𝐴 = 28𝑖𝑛2
3. 𝐴 = 11.5π‘π‘š2
4. 𝐴 = 1.5𝑓𝑑 2
7-1 Areas of
Parallelograms
and Triangles
𝐴 = π‘β„Ž
𝐴 = 5𝑖𝑛 βˆ™ 4𝑖𝑛
2
𝐴 = 20𝑖𝑛
𝐴 = π‘β„Ž
𝐴 = 2π‘π‘š βˆ™ 3.5π‘π‘š
2
𝐴 = 7π‘π‘š
𝐴 = π‘β„Ž
𝐴 = 12π‘š βˆ™ 9π‘š
2
𝐴 = 108π‘š
Practice
𝐴 = 807.3 π‘šπ‘– 2
𝐴 = 55.2 𝑦𝑑 2
𝐴 = 68.9 𝑦𝑑 2
𝐴 = 1617.56 π‘π‘š2
𝐴 = 12,698,200π‘š2
𝐴 = 1269.82π‘π‘š2
𝐴 = π‘β„Ž
𝐴 = 10𝑖𝑛 βˆ™ 12𝑖𝑛
𝐴 = 120𝑖𝑛2
The Area of ABCD is 120𝑖𝑛2
𝐴 = π‘β„Ž
120𝑖𝑛2 = 13𝑖𝑛 βˆ™ 𝐢𝐹
120
= 𝐢𝐹
13
CF is 9.2𝑖𝑛
1
𝐴 = π‘β„Ž
2
1
𝐴 = βˆ™ 10𝑓𝑑 βˆ™ 6.4𝑓𝑑
2
𝐴 = 32𝑓𝑑 2
1
𝐴 = π‘β„Ž
2
1
𝐴 = βˆ™ 12π‘π‘š βˆ™ 5π‘π‘š
2
𝐴 = 30π‘π‘š2
Practice
𝐴 = 33,512π‘π‘š2
𝐴 = 639.6𝑓𝑑 2
𝐴 = 517π‘π‘š2
𝐴 = 934.2𝑓𝑑 2
Classwork
β€’Pg. 351-352: #1-3, 8-10, 11-24