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6.4
Vectors and Dot
Products
Copyright © Cengage Learning. All rights reserved.
What You Should Learn
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Find the dot product of two vectors and use the
properties of the dot product.
Find the angle between two vectors and
determine whether two vectors are orthogonal.
Write vectors as the sums of two vector
components.
Use vectors to find the work done by a force.
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The Dot Product of Two Vectors
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The Dot Product of Two Vectors
So far you have studied two vector operations—vector
addition and multiplication by a scalar—each of which
yields another vector.
In this section, you will study a third vector operation, the
dot product. This product yields a scalar, rather than a
vector.
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The Dot Product of Two Vectors
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Example 2 – Using Properties of Dot Products
Let u = –1, 3, v = 2, –4, and w = 1, –2. Use the vectors
and the properties of the dot product to find the indicated
quantity.
a. (u  v)w
b. u  2v
c. || u||
Solution:
Begin by finding the dot product of u and v and the dot
product of u and u.
u  v = –1, 3  2, –4
= (–1)(2) + 3(–4)
= –14
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Example 2 – Solution
cont’d
u  u = –1, 3  –1, 3
= (–1)(–1) + 3(3)
= 10
a. (u  v)w = –141, –2
= –14, 28
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Example 2 – Solution
cont’d
b. u  2v = 2(u  v)
= 2(–14)
= –28
c. Because ||u||2 = u  u = 10, it follows that
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The Angle Between Two Vectors
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The Angle Between Two Vectors
The angle between two nonzero vectors is the angle ,
0    , between their respective standard position
vectors, as shown in Figure 6.36.
Figure 6.36
This angle can be found using the dot product. (Note that
the angle between the zero vector and another vector is not
defined.)
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The Angle Between Two Vectors
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Example 3 – Finding the Angle Between Two Vectors
Find the angle between
u = 4, 3 and v = 3, 5.
Solution:
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Example 3 – Solution
cont’d
This implies that the angle between the two vectors is
as shown in Figure 6.37.
Figure 6.37
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The Angle Between Two Vectors
The terms orthogonal and perpendicular mean essentially
the same thing—meeting at right angles.
Even though the angle between the zero vector and
another vector is not defined, it is convenient to extend the
definition of orthogonality to include the zero vector.
In other words, the zero vector is orthogonal to every vector
u because 0  u = 0.
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Example 4 – Determining Orthogonal Vectors
Are the vectors
u = 2, –3 and v = 6, 4
orthogonal?
Solution:
Begin by finding the dot product of the two vectors.
u  v = 2, –3  6, 4
= 2(6) + (–3)(4)
=0
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Example 4 – Solution
cont’d
Because the dot product is 0, the two vectors are
orthogonal, as shown in Figure 6.39.
Figure 6.39
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Finding Vector Components
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Finding Vector Components
You have already seen applications in which two vectors
are added to produce a resultant vector. Many applications
in physics and engineering pose the reverse problem—
decomposing a given vector into the sum of two
vector components.
Consider a boat on an inclined
ramp, as shown in Figure 6.40.
The force F due to gravity pulls
the boat down the ramp and
against the ramp.
Figure 6.40
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Finding Vector Components
These two orthogonal forces, w1 and w2, are vector
components of F. That is,
F = w 1 + w 2.
Vector components of F
The negative of component w1 represents the force needed
to keep the boat from rolling down the ramp, and w2
represents the force that the tires must withstand against
the ramp.
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Finding Vector Components
A procedure for finding w1 and w2 is shown below.
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Finding Vector Components
 is acute.
 is obtuse.
Figure 6.41
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Finding Vector Components
From the definition of vector components, you can see that
it is easy to find the component w2 once you have found the
projection of u onto v. To find the projection, you can use
the dot product, as follows.
u = w1 + w2
u = cv + w2
u  v = (cv + w2)  v
w1 is a scalar multiple of v.
Take dot product of each side with v.
u  v = cv  v + w2  v
u  v = c||v||2 + 0
w2 and v are orthogonal.
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Finding Vector Components
So,
and
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Example 5 – Decomposing a Vector into Components
Find the projection of
u = 3, –5 onto v = 6, 2.
Then write u as the sum of two orthogonal vectors, one of
which is
.
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Example 5 – Solution
The projection of onto is
as shown in Figure 6.42.
Figure 6.42
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Example 5 – Solution
cont’d
The other component, w2, is
So,
u = w1 + w2
= 3, –5
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Work
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Work
The work W done by a constant force F acting along the
line of motion of an object is given by
W = (magnitude of force)(distance) = ||F||
as shown in Figure 6.44.
Force acts along the line of motion.
Figure 6.44
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Work
If the constant force F is not directed along the line of
motion (see Figure 6.45),
Force acts at angle  with the line of motion.
Figure 6.45
then the work W done by the force is given by
Projection form for work
Dot product form for work
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Work
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Example 7 – Finding Work
To close a barn’s sliding door, a person pulls on a rope with
a constant force of 50 pounds at a constant angle of 60,
as shown in Figure 6.46.
Figure 6.46
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Example 7 – Finding Work
Find the work done in moving the door 12 feet to its closed
position.
Solution:
Using a projection, you can calculate the work as follows.
= 300 foot-pounds
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Example 7 – Solution
cont’d
So, the work done is 300 foot-pounds.
You can verify this result by finding the vectors F and
and calculating their dot product.
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