Transcript 251GASLAWS_U_DO_NOW

GAS LAWS-U DO IT NOW
12/13/06-LESSON
A POODLE OF 10 L VOLUME IS PLACED IN A PRESSURE COOKER, THE EXTERNAL
PRESSURE APPLIED TO THE POODLE CHANGES FROM 101.0 kPa TO 404.0 kPa:
WHAT LAW IS DEFINED THIS CLOSED SYSTEM AT CONSTANT TEMP!
WHAT IS THE FINAL POODLE VOLUME.
DISCUSS AND/OR DRAW WHAT HAPPENED ACCORDING TO COLLISION
THERORY
V1 = 10L
V2 = X L
VOLUME MUST DECREASE AS
PRESSURE INCREASES, BOYLES LAW
P1 = 101 kPa
P2 = 404 kPa
P1V1 = P2V2
T1
T2
THE NEW
VOLUME IS 4X
SMALLER, 2.5
L
PRESSURE INCREASES 4X THEREFORE
VOLUME DECREASES 4X
P1V1 = P2V2
(101)(10L) = (404)(X)
X = V2 = 2.5L
GAS LAWS-U DO IT NOW
12/13/06-LESSON
A POODLE OF 10 L VOLUME IS PLACED IN A MICROWAVE OVEN THAT IS
HEATED FROM 100K TO 400K:
WHAT LAW IS THIS
WHAT IS THE NEW VOLUME
DESCRIBE THE KINETIC MOLECULAR THEORY OF THIS SITUATION.
V1 = 10L
V2 = X L
VOLUME MUST INCREASE AS
TEMPERATURE INCREASES, CHARLES
LAW
T1 = 100K
T2 = 400K
P1V1 = P2V2
T1
T2
TEMPERATURE INCREASES 4X
THEREFORE VOLUME INCREASES 4X
V1/T1 = V2/T2
(10L)/(100K) = (X)/(400K)
X = V2 = 40.0L
THE NEW
VOLUME IS 4X
BIGGER, 40.0
L
GAS LAWS-U DO IT NOW
12/13/06-LESSON
JOHNNY CLIMBS A MOUNTAIN WITH A GAS PRODUCING URINARY BLADDER
INFECTION FROM DOING BAD THINGS, HIS BLADDER EXPANDED FROM 2.0L TO
4.0L. ( OUCH), THE INITIAL CONDITIONS WERE STP, WHAT WAS THE FINAL
EXTERNAL PRESSURE HIS BLADDER HAD TO BE AT CONSTANT TEMP.
V1 = 2.0L
V2 = 4.0 L
P1 = 1 ATM
P2 = X
VOLUME INCREASE (2X) THEREFORE
PRESSURE DECREASES(2X), BOYLES
LAW
PRESSURE DECREASES 2X AS VOLUME
INCREASES 2X
P1V1 = P2V2
T1
T2
P1V1 = P2V2
(1)/(2.OL) = (X)(4.0L)
X = P2 = 0.5ATM
THE NEW
FINAL
PRESSURE IS
2X LESS, 0.5
ATM
GAS LAWS-U DO IT NOW
12/13/06-LESSON
SHRECK’S HEAD EXPANDS FROM TO A VOLUME OF 500L AS HE
TRAVELS IN OUTER SPACE. THE PRESSURE ON HIS GINOURMOUS
HEAD FALLS FROM SP TO 0.1 ATM, WHAT WAS THE ORIGINAL VOLUME
OF HIS GROTESQUE HEAD?
V1 = X L
V2 = 500L L
P1 = 1 ATM
P2 = 0.1
VOLUME INCREASE (10X) BECAUSE OF
PRESSURE DECREASES(10X), BOYLES
LAW
PRESSURE DECREASES 10X AS
VOLUME INCREASES 10X
P1V1 = P2V2
T1
T2
P1V1 = P2V2
(1)/(X L) = (0.1)(500)
X = V1 = 50 L
THE INITIAL
VOLUME IS
10X LESS
THAN 500,= 50
L