Heat Transfer in Structures Dr M Gillie
Download
Report
Transcript Heat Transfer in Structures Dr M Gillie
Heat Transfer in Structures
Dr M Gillie
Heat Transfer
Fundamental to Fire Safety Engineering
Three methods of heat transfer
– Radiation - does not require matter
– Conduction – within matter (normally solids)
– Convection – as a result of mass transfer
CONDUCTION
Some Physics
Heat flow proportional to thermal gradient
Heat flows from hot to cold
k thermal conductivity (material property)
c specific heat capacity give amount of heat
needed to change temperature of mass m by ΔT
as:
E cmT
Fourier’s Law
Heat flux per unit area
dT
q ' ' k
dx
Heat flow proportional
to temperature gradient
Heat flowing from hot
To cold
Insulated
Constant
Temp
a
q’’
Steady-state conditions
Insulated
Constant
Temp
Steady-state 1-d Heat Flow
dT
q ' ' k
dx
q ' '0 k T T 1
L
Assume total heat in bar
does not change with
Time – steady state
T2
k
q ' ' (T 1 T 2)
L
Insulated
T1
A
q’’
Steady-state conditions
L
T2
Transient Heat Flow 1-d
T
q x kAdt
Heat flowing into slice
x
T 2T
q x dx kAdt
2 dx Heat flowing out of slice
x x
ΔE ρcAdxT
Change in energy wit hin slice
Insulated
T1
A
T2
Varying heat
flow
x
dx
L
Transient Heat Flow 1-d
T 2T
T
ρcAdxT kAdt
kAdt
2 dx
x
x x
2T c T
2
dx
k t
Insulated
T1
A
T2
Varying heat
flow
x
dx
L
CONVECTION
Convection
Heat transfer from solid to fluid as a result of mass
transfer
Can be “forced” or “natural”
First studied by Newton for cooling bodies
Governed by
Fluid at
T2
q ' ' h(T 1 T 2 )
h= convective heat transfer coefficient
Solid at T1
h
Convective heat transfer coefficient depends on
–
–
–
–
–
–
Temperature
Free or forced convection
Turbulence
Geometry
Viscosity
Etc etc
Difficult to determine accurately. “Engineering”
values often used.
Radiation
What is Radiative Heat Transfer?
Electromagnetic radiation emitted on account of a
body’s temperature
Requires no medium for transfer
Only a small portion of spectrum transmits heat (0.1100um)
Preliminaries – Absolute Temperature
Absolute temperature needed for radiative
heat transfer problems
Measured in Kelvin (K)
0 K at “Absolute 0” - all atomic motion ceases
A change of 1K equals a change of 1ºC
0 ºC equals 273.15K
Preliminaries – “Black bodies”
Black bodies are hypothetical but useful for
analysis of radiation
Absorb all incoming radiation
No body can emit more radiation at a given
temperature and wavelength
Are diffuse emitters
The Sun is very close to being a black body
Stefan-Boltzmann Equation
2c 2 h5
E ch / KT
for a diffuse black - body
e
1
when integrated wrt results in
2 5 k 4 4
T
E q ' '
2 3
15c h
or
E T 4
where is the Stefan - Boltzmann constant. Grey bodies result in
E T 4
where is the emissivity
E T 4
E T 4
Stefan-Boltzmann Equation in Action
Question: What is the net incident
radiation arriving at B?
Each “piece” of area emits
uniformly in all directions
according to E=εσT4
A
B
T2
A
T1
Hot surface
Stefan-Boltzmann Equation in Action
Question: What is the net incident
radiation arriving at B?
Answer depends on
-The relative temperatures A and B
radiation is a two way process
B
-The geometry of the system –
configuration factors
T2
d
Some radiation
“escapes” and does
not reach B
A
T1
Configuration Factors
Take account of the geometry of radiating bodies
Allow calculation of net radiation arriving at a surface
Calculation involves much integration – only possible
for simple cases
Details not needed for this course
Two kinds
– Point to surface (eg fire to ceiling)
– Surface to surface (e.g. smoke layer to ceiling)
For compartment fires
Thick layer of hot gas, opaque
Fire compartment
Local fire or
flashed over fire
Hot gases are radiating and so
Ceiling “sees” all of the area of
The room. Therefore configuration
factor~1.
Heat Transfer to Steel Structures
Several cases - insulated, uninsulated etc
Simple solution methods presented
More advanced solutions possible but require
LOTS more analysis
Approach is to make conservative assumptions
Un-insulated Steel
Assume constant temperature in cross-section
– lumped capacitance
Apply energy balance to the problem
Solve for small time-steps to get approximate
solution
Involves use of radiative and convective heat
transfer equations
Un-insulated steel
Heat flowing into a unit length of
section in time Δt is equal to the
energy stored in the section
q ' ' Ht *1 cTA *1
Assume steel
at uniform
temperature, Ts
q’’ consists of two parts
Perimeter=H
Area=A
h(Tg Ts) (Tg4 Ts4 )
convection
radiation
Substituting and rearranging results
H t
Ts
hTg Ts Tg4 Ts4
A c
Convection and
radiation to steel from
gas at Tg
Section Factors
Give a measure of how rapidly a section heats
Normally ratio of heated perimeter to area
Given in some tables
Various other measures and symbols used
– Area to volume
Insulated Steel-Sections (1)
Insulation has no
thermal capacity (e.g.
intumescent paint)
Same temp as gas at
outer surface
Same temp as steel at
inner surface
Therefore conduction
problem
Perimeter=H
Area=A
Insulated Steel-Sections (1)
Energy balance approach
used again
q ' ' Ht cAT
q’’ now as a result of conduction only
Perimeter=H
Area=A
k
q ' ' Tg Ts
d
Which gives
k H
Tg Ts t
T
dc A
Insulation thickness d
Insulated Steel-Sections (2)
Insulation has no
thermal capacity (e.g.
cementious spray)
Assume linear
temperature gradient in
insulation
Perimeter=H
Area=A
Insulated Steel-Sections (2)
Energy balance approach
used again
q ' ' Ht s cs AT i ci
q’’ now
Ts
dH
2
Perimeter=H
Area=A
energy in
insulation
k
q ' ' Tg Ts
d
Which gives
Insulation thickness d
s cs
H k
T
Tg Ts t
Hd i ci
A d s c s
s cs
2A
Heat Transfer in Concrete
Very large thermal capacity
– Heat slowly
– Lumped mass approach not appropriate
Complicated by water present in concrete
Usually need computer analysis for nonstandard situation
Results are published for Standard Fire Tests
Heat
penetration
in concrete
beams
Heat penetration in concrete slabs
(mm)