CH 6: Thermochemistry Renee Y. Becker Valencia Community College CHM 1045

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Transcript CH 6: Thermochemistry Renee Y. Becker Valencia Community College CHM 1045

CH 6: Thermochemistry

Renee Y. Becker Valencia Community College CHM 1045 1

Energy •

Energy:

is the capacity to do work, or supply heat.

Energy = Work + Heat •

Kinetic Energy:

is the energy of motion.

E

K = 1 / 2

mv

2

(1 Joule = 1 kg

m 2 /s 2 ) (1 calorie = 4.184 J)

Potential Energy:

is stored energy.

2

E k & E p 3

Example 1: KE Which of the following has the greatest kinetic energy?

1. A 12 kg toy car moving at 5 mph?

2. A 12 kg toy car standing at the top of a large hill?

4

Energy •

Thermal Energy

is the kinetic energy of molecular motion • Thermal energy is proportional to the temperature in degrees Kelvin.

E

thermal 

T

(K) •

Heat

is the amount of thermal energy transferred between two objects at different temperatures.

5

In an experiment:

Reactants and products are the

system

; everything else is the

surroundings

.

• Energy flow from the

system

to the

surroundings

has a

negative

energy). (  E or  H) sign (loss of • Energy flow from the

surroundings

to the

system

has a

positive

(+  E or +  H) sign (gain of energy). 6

7

The law of the conservation of energy:

Energy cannot be created or destroyed.

• The energy of an isolated system must be constant.

• The energy change in a system equals the work done on the system + the heat added.

E

=

E

final –

E

initial =

E

2 –

E

1 =

q

+

w q

= heat,

w

= work 8

• Pressure is the force per unit area.

Pressure = Force  Area

F A

(1

N/m 2

= 1

Pa

) (1

atm

= 101,325

Pa

) • Work is a force (

F

) that produces an object’s movement, times the distance moved (

d

): Work = Force x Distance 9

The expansion in volume that occurs during a reaction forces the piston outward against atmospheric pressure, P. Work = -atmospheric pressure * area of piston * distance piston moves 10

Example 2: Work How much work is done (in kilojoules), and in which direction, as a result of the following reaction?

11

• The amount of heat exchanged between the system and the surroundings is given the symbol

q

.

q

=

E

+

P

V

At constant volume ( 

V

= 0):

q v

= 

E

At constant pressure:

q p

= 

E

+

P

V

= 

H

Enthalpy change: 

H

=

H

products –

H

reactants 12

Example 3: Work The explosion of 2.00 mol of solid TNT with a volume of approximately 0.274 L produces gases with a volume of 489 L at room temperature. How much

PV

(in kilojoules) work is done during the explosion? Assume 25 °C.

P

= 1 atm,

T

= 2 C 7 H 5 N 3 O 6 (

s

)  12 CO(

g

) + 5 H 2 (

g

) + 3 N 2 (

g

) + 2 C(

s

) 13

Enthalpies of Physical Change:

Enthalpy is a state function, the enthalpy change from solid to vapor does not depend on the path taken between the two states.  H subl =  H fusion +  H vap 14

Enthalpies of Chemical Change:

Often called heats of reaction ( 

H

reaction ).

Endothermic :

Heat flows into the system from the surroundings and 

H has a positive sign

.

Exothermic :

Heat flows out of the system into the surroundings and 

H has a negative sign

.

15

Bromination vs. Chlorination

41 16

• Reversing a reaction changes the sign of 

H

for a reaction.

C 3 H 8 (

g

) + 5 O 2 (

g

)  3 CO 2 (

g

) + 4 H 2 O(

l

) 

H

= –2219 kJ 3 CO 2 (

g

) + 4 H 2 O(

l

)  C 3 H 8 (

g

) + 5 O 2 (

g

) 

H

= +2219 kJ • Multiplying a reaction increases 

H

factor.

by the same 3 [C 3 H 8 (

g

) + 15 O 2 (

g

)  9 CO 2 (

g

) + 12 H 2 O(

l

)] 

H

= 3(-2219) kJ 

H

= -6657 kJ 17

Example 4: Heat • How much heat (in kilojoules) is evolved or absorbed in each of the following reactions?

a) Burning of 15.5 g of propane: C 3 H 8 (

g

) + 5 O 2 (

g

)  3 CO 2 (

g

) + 4 H 2 O(

l

) 

H

= –2219 kJ/mole b) Reaction of 4.88 g of barium hydroxide octahydrate with ammonium chloride: Ba(OH) 2 ·8 H 2 O(

s

) + 2 NH 4 Cl(

s

)  BaCl 2 (

aq

) + 2 NH 3 (

aq

) + 10 H 2 O(

l

) 

H

= +80.3 kJ/mole 18

Thermodynamic Standard State:

Most stable form of a substance at 1 atm pressure and 25 °C; 1 M concentration for all substances in solution.

• These are indicated by a superscript ° to the symbol of the quantity reported. • S

tandard enthalpy change

symbol 

H

°.

is indicated by the 19

Example 5: Is an endothermic reaction a favorable process thermodynamically speaking?

1) Yes 2) No 20

Hess’s Law •

Hess’s Law:

The overall enthalpy change for a reaction is equal to the sum of the enthalpy changes for the individual steps in the reaction.(not a physical change, chemical change) 3 H 2 (

g

) + N 2 (

g

)  2 NH 3 (

g

) 

H

° = –92.2 kJ 21

• Reactants and products in individual steps can be added and subtracted to determine the overall equation.

(1) 2 H 2 (

g

) + N 2 (

g

)  (2) N 2 H 4 (

g

) + H 2 (

g

)  (3) 3 H 2 (

g

) + N 2 (

g

)  N 2 H 4 (

g

) 

H

° 1 = ?

2 NH 3 (

g

) 

H

° 2 = –187.6 kJ 2 NH 3 (

g

) 

H

° 3 = –92.2 kJ 

H

° 1 + 

H

° 2 = 

H

° reaction Then 

H

° 1 = 

H

° reaction 

H

° 2 

H

° 1 = 

H

° 3 – 

H

° 2 = ( –92.2 kJ) – (–187.6 kJ) = +95.4 kJ 22

Example 6: Hess’s Law • The industrial degreasing solvent methylene chloride (CH 2 Cl 2 , dichloromethane) is prepared from methane by reaction with chlorine: CH 4 (

g

) + 2 Cl 2 (

g

)  CH 2 Cl 2 (

g

) + 2 HCl(

g

) Use the following data to calculate 

H

° (in kilojoules) for the above reaction: CH 4 (

g

) + Cl 2 (

g

)  

H

° = –98.3 kJ CH 3 Cl(

g

) + HCl(

g

) CH 3 Cl(

g

) + Cl 2 (

g

)  

H

° = –104 kJ CH 2 Cl 2 (

g

) + HCl(

g

) 23

Standard Heats of Formation (

H

° f ):

The enthalpy change for the formation of 1 mole of substance in its standard state from its constituent elements in their standard states.

• The standard heat of formation for any element in its standard state is defined as being ZERO.

H

° f

= 0 for an element in its standard state

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Standard Heats of Formation •

Calculating

H

° for a reaction:

H

° =

H

°

f

(Products) –

H

°

f

(Reactants)

• For a balanced equation, each heat of formation must be multiplied by the stoichiometric coefficient.

aA + bB  cC + dD 

H

° = [c 

H

° f (C) + d 

H

° f (D)] – [a 

H

° f (A) + b 

H

° f (B)] 25

Standard Heats of Formation

Some Heats of Formation,

H

f

°

(kJ/mol)

CO(

g

) CO 2 (

g

) H 2 O(

l

) NH 3 (

g

) N 2 H 4 (

g

) HCl(

g

) -111 -394 -286 -46 95.4

-92 C 2 H 2 (

g

) C 2 H 4 (

g

) C 2 H 6 (

g

) CH 3 OH(

g

) C 2 H 5 OH(

g

) C 6 H 6 (

l

) 227 52 -85 -201 -235 49 Ag + (

aq

) Na + (

aq

) NO 3 (

aq

) Cl (

aq

) AgCl(

s

) Na 2 CO 3 (

s

) 106 -240 -207 -167 -127 -1131 26

Example 7: Standard heat of formation Calculate 

H

° (in kilojoules) for the reaction of ammonia with O 2 to yield nitric oxide (NO) and H 2 O(

g

), a step in the Ostwald process for the commercial production of nitric acid.

27

Example 8: Standard heat of formation Calculate 

H

° (in kilojoules) for the photosynthesis of glucose and O 2 from CO 2 and liquid water, a reaction carried out by all green plants.

28

Example 9: Which of the following would indicate an endothermic reaction? Why?

1.  H 2. +  H 29

Heat of Phase Transitions from  H  f Calculate the heat of vaporization,  H  vap water, using standard enthalpies of of formation H H 2 2 O O (g) (l)  H  f -241.8 kJ/mol -285.8 kJ/mol 30

Calorimetry and Heat Capacity •

Calorimetry

is the science of measuring heat changes (

q

) for chemical reactions. There are two types of calorimeters: • Bomb Calorimetry: A bomb calorimeter measures the heat change at constant volume such that

q

= 

E

.

• Constant Pressure Calorimetry: A constant pressure calorimeter measures the heat change at constant pressure such that

q

= 

H

.

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Constant Pressure Bomb

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Calorimetry and Heat Capacity •

Heat capacity (C)

is the amount of heat required to raise the temperature of an object or substance a given amount.

Specific Heat:

The amount of heat required to raise the temperature of 1.00 g of substance by 1.00

°C.

q = s x m x  t q = heat required (energy) s = specific heat m = mass in grams  t = T f - T i 33

Calorimetry and Heat Capacity •

Molar Heat:

The amount of heat required to raise the temperature of 1.00 mole of substance by 1.00

°C.

q = MH x n x  t q = heat required (energy) MH = molar heat n = moles  t = T f - T i 34

Example 10: Specific Heat What is the specific heat of lead if it takes 96 J to raise the temperature of a 75 g block by 10.0

°C?

35

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Example 11: Specific Heat How much energy (in J) does it take to increase the temperature of 12.8 g of Gold from 56  C to 85  C?

37

Example 12: Molar Heat • How much energy (in J) does it take to increase the temperature of 1.45 x10 4 moles of water from 69  C to 94  C?

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