Chapters 4, 5 Force and Laws of Motion

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Transcript Chapters 4, 5 Force and Laws of Motion

Chapters 4, 5 Force and Laws of Motion

What causes motion?

Aristotle (384 BC – 322 BC) •

That’s the wrong question!

Galileo Galilei (1564 – 1642) •

The ancient Greek philosopher Aristotle believed that forces - pushes and pulls - caused motion

The Aristotelian view prevailed for some 2000 years

Galileo first discovered the correct relation between force and motion

Force causes not motion itself but change in motion

Newtonian mechanics

Sir Isaac Newton (1643 – 1727) •

Describes motion and interaction of objects

Applicable for speeds much slower than the speed of light

Applicable on scales much greater than the atomic scale

Applicable for inertial that don’t accelerate reference frames themselves – frames

Force

What is a force?

Colloquial understanding of a force – a push or a pull

Forces can have different nature

Forces are vectors

Several forces can act on a single object at a time – they will add as vectors

Force superposition

Forces applied to the same object vectors – superposition are adding as

The net force – a vector sum of to the same object all the forces applied

Newton’s First Law

If the net force on the body is zero, the body’s acceleration is zero

F net

 0  

a

 0

Newton’s Second Law

If the net force on the body is not zero, the body’s acceleration is not zero

F net

 0  

a

 0 •

Acceleration of the body is directly proportional to the net force on the body

The coefficient of proportionality mass (the amount of substance) of the object

m a

 

F net

a

is equal to the

 

F net m

Newton’s Second Law

SI unit of force kg*m/s 2 = N ( Newton )

Newton’s Second Law can be applied to all the components separately

To solve problems with Newton’s Second Law we need to consider a free-body diagram

If the system consists of more than one body, only external forces acting on the system have to be considered

Forces acting between the bodies of the system are internal and are not considered

Newton’s Third Law

When two bodies interact forces on each other with each other, they exert

The forces that interacting bodies exert on each other, are equal in magnitude and opposite in direction

F

12   

F

21

Forces of different origins

Gravitational force

Normal force

Tension force

Frictional force (friction)

Drag force

Spring force

Gravity force (a bit of Ch. 8)

Any two (or more) massive bodies attract each other

Gravitational force (Newton's law of gravitation)

F

G m

1

m

2

r

2

r

ˆ •

Gravitational constant 6.67*10 –11 m 3 /(kg*s 2 ) G = 6.67*10 –11 N*m – universal constant 2 /kg 2 =

Gravity force at the surface of the Earth

F Crate

G m

1

m

2

r

2

r

ˆ  

G m Earth m Crate

2

R Earth j

ˆ 

F Crate

   

Gm Earth

2

R Earth

 

m Crate j

ˆ    

m Crate j

ˆ

g

= 9.8 m/s 2

Gravity force at the surface of the Earth

The apple is attracted by the Earth

According to the Newton’s Third Law, the Earth should be attracted by the apple with the force of the same magnitude

F Earth

G m

1

m

2

r

2

r

ˆ 

G m Earth m Apple

2

R Earth j

ˆ 

a Earth

G m Earth m Apple

2

R Earth m Earth j

ˆ   

Gm Earth

2

R Earth

 

m Apple m Earth j

ˆ 

m m Apple Earth j

ˆ

Weight

Weight (W) of a body is a force that the body exerts on a support as a result of gravity pull from the Earth

Weight at the surface of the Earth:

W = mg

While the mass of a body is a constant, the weight may change under different circumstances

Tension force

A weightless cord (string, rope, etc.) attached to the object can pull the object

The force of the pull is tension (

T

)

The tension is pointing away from the body

Free-body diagrams

Chapter 4 Problem 56 Your engineering firm is asked to specify the maximum load for the elevators in a new building. Each elevator has mass 490 kg when empty and maximum acceleration 2.24 m/s 2 . The elevator cables can withstand a maximum tension of 19.5 kN before breaking. For safety, you need to ensure that the tension never exceeds two-thirds of that value. What do you specify for the maximum load? How many 70-kg people is that?

Normal force

When the body presses against the surface (support), the surface deforms and pushes on the body with a normal force (

n

) that is perpendicular to the surface

The nature of the normal force – reaction of the molecules and atoms to the deformation of material

Normal force

The normal force is not always gravitational force of the object equal to the

Free-body diagrams

Free-body diagrams

Chapter 5 Problem 19 If the left-hand slope in the figure makes a 60 ° angle with the horizontal, and the right-hand slope makes a 20 ° angle, how should the masses compare if the objects are not to slide along the frictionless slopes?

Spring force

Spring in the relaxed state

Spring force (restoring force) acts to restore the relaxed state from a deformed state

Hooke’s law

For relatively small deformations

F s

 

k d

 Robert Hooke (1635 – 1703) •

Spring force is proportional to the deformation and opposite in direction

k

– spring constant

Spring force is a variable force

Hooke’s law can be applied not to springs only, but to all elastic materials and objects

Frictional force

Friction (

f

) - resistance to the sliding attempt

Direction of friction – opposite to the direction of attempted sliding (along the surface)

The origin of friction – bonding between the sliding surfaces (microscopic cold-welding )

Static friction and kinetic friction

Moving an object: static friction vs. kinetic

Friction coefficient

Experiments show that friction is related to the magnitude of the normal force

Coefficient of static friction

μ s f s

, max  

s n

Coefficient of kinetic friction

μ k f k

 

k n

Values of the friction coefficients depend on the combination of surfaces in contact and their conditions (experimentally determined)

Free-body diagrams

Free-body diagrams

Chapter 5 Problem 30 Starting from rest, a skier slides 100 m down a 28 ° slope. How much longer does the run take if the coefficient of kinetic friction is 0.17 instead of 0?

Drag force

Fluid – a substance that can flow (gases, liquids)

If there is a relative motion between a fluid and a body in this fluid, the body experiences a resistance (drag)

Drag force (

R

)

R = ½DρAv 2

D

drag coefficient ;

ρ

– fluid density;

A

– effective cross-sectional area of the body (area of a cross section taken perpendicular to the velocity);

v

- speed

Terminal velocity

When objects falls in air, the drag force points upward (resistance to motion)

According to the Newton’s Second Law

ma = mg – R = mg – ½DρAv 2

As

v

grows,

a

decreases. At some point acceleration becomes zero, and the speed value riches maximum value – terminal speed

½DρAv t 2 = mg

Terminal velocity

Solving

½DρAv t 2 = mg

we obtain

v t

 2

mg D

A

v t = 300 km/h v t = 10 km/h

Centripetal force

For an object in a uniform circular motion, the centripetal acceleration is

a c

v

2

R

According to the Newton’s Second Law, a force must cause this acceleration – centripetal force

F c

ma c

mv

2

R

A centripetal force accelerates a body by changing the direction of the body’s velocity without changing the speed

Centripetal force

Centripetal forces may have different origins

• • •

Gravitation can be a centripetal force Tension can be a centripetal force Etc.

Centripetal force

Centripetal forces may have different origins

• • •

Gravitation can be a centripetal force Tension can be a centripetal force Etc.

Free-body diagram

Chapter 5 Problem 25 You’re investigating a subway accident in which a train derailed while rounding an unbanked curve of radius 132 m, and you’re asked to estimate whether the train exceeded the 45-km/h speed limit for this curve. You interview a passenger who had been standing and holding onto a strap; she noticed that an unused strap was hanging at about a 15 ° angle to the vertical just before the accident. What do you conclude?

Answers to the even-numbered problems Chapter 4 Problem 20 7.7 cm

Answers to the even-numbered problems Chapter 4 Problem 26 590 N

Answers to the even-numbered problems Chapter 4 Problem 38 5.77 N; 72.3

°

Answers to the even-numbered problems Chapter 5 Problem 28 580 N; opposite to the motion of the cabinet

Answers to the even-numbered problems Chapter 5 Problem 50 110 m