Transcript Chemical Bonding I: Lewis Theory Chapter 9

Chemistry: A Molecular Approach, 1st Edition
Nivaldo J. Tro
Chapter 9
Chemical
Bonding I:
Lewis Theory
Which of the following compounds will have the highest
magnitude lattice energy value?
a) KBr
b) NaBr
c) LiBr
d) RbBr
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e) All are the same.
f) There is not enough
information to compare.
Which of the following compounds will have the highest
magnitude lattice energy value?
a) KBr
b) NaBr
c) LiBr
d) RbBr
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e) All are the same.
f) There is not enough
information to compare.
Calculate the percent ionic character of a diatomic
molecule with a bond length of 145 pm that has a dipole
moment of 5.2 D.
a)
b)
c)
d)
e)
52 %
45 %
75 %
70 %
85 %
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Calculate the percent ionic character of a diatomic
molecule with a bond length of 145 pm that has a dipole
moment of 5.2 D.
a)
b)
c)
d)
e)
52 %
45 %
75 %
70 %
85 %
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Which of the following sets gives the correct formal
charges for the elements in the Lewis structure below?
a)
b)
c)
d)
e)
S: –2
S: +6
S: –2
S: +1
S: 0
S
C
C: –4
C: +4
C: –4
C: 0
C: 0
N: –3
N: +5
N: –3
N: –1
N: –1
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N
Which of the following sets gives the correct formal
charges for the elements in the Lewis structure below?
a)
b)
c)
d)
e)
S: –2
S: +6
S: –2
S: +1
S: 0
S
C
C: –4
C: +4
C: –4
C: 0
C: 0
N: –3
N: +5
N: –3
N: –1
N: –1
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N
Using average bond energies, calculate ΔHrxn for the
combustion of acetylene.
O
2H
a)
b)
c)
d)
e)
H
+ 5O
O
+1359 kJ
–1359 kJ
+7408 kJ
–7408 kJ
–510 kJ
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4O
C
O
+ 2H
Bond
Bond Energy
(kJ/ mol)
C─H
414
C─C
347
C≡C
837
O═O
498
C═O in CO2
799
O─H
464
H
Using average bond energies, calculate ΔHrxn for the
combustion of acetylene.
O
2H
a)
b)
c)
d)
e)
H
+ 5O
O
+1359 kJ
–1359 kJ
+7408 kJ
–7408 kJ
–510 kJ
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4O
C
O
+ 2H
Bond
Bond Energy
(kJ/ mol)
C─H
414
C─C
347
C≡C
837
O═O
498
C═O in CO2
799
O─H
464
H
Rank the following in order of increasing bond polarity:
H─F
a)
b)
c)
d)
e)
H─Br
F─F
H─F < H─Br < F─F < Na─Cl
F─F < H─F < H─Br < Na─Cl
H─Br < H─F < F─F < Na─Cl
F─F < H─Br < H─F < Na─Cl
Na─Cl < H─F < H─Br < F─F
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Na─Cl
Rank the following in order of increasing bond polarity:
H─F
a)
b)
c)
d)
e)
H─Br
F─F
H─F < H─Br < F─F < Na─Cl
F─F < H─F < H─Br < Na─Cl
H─Br < H─F < F─F < Na─Cl
F─F < H─Br < H─F < Na─Cl
Na─Cl < H─F < H─Br < F─F
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Na─Cl