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Configuration Space

• The state of a system of

n

particles & subject to

m

constraints connecting some of the

3n

rectangular coordinates is completely specified by

s = 3n – m generalized coordinates .

 Sometimes its convenient to represent the state of such a system by a point in an abstract

s

-dimensional space called

CONFIGURATION SPACE

. Each dimension in this space corresponds to one of the coordinates

q j

. This point specifies the

CONFIGURATION

of the system at a particular time. As the

q j

change in time (governed by the eqtns of motion) this point traces out a curve in configuration space. The exact curve depends on the initial conditions. Often we speak of “the path” of the system as it “moves” in configuration space. • Obviously, this is

NOT

the same as the particle path as it moves in ordinary 3d space!

Lagrange’s Equations in Generalized Coordinates

Section 7.4

• In light of the preceding discussion we can now restate

Hamilton’s Principle

in slightly different language:

Of all of the possible paths along which a dynamical system may move from one point to another in configuration space within a specified time interval, the ACTUAL PATH followed is that which minimizes the time integral of the Lagrangian for the system.

• Repeat

Hamilton’s Principle & Lagrange Equations

derivation in terms of

generalized coordinates

: • Use the fact that the Lagrangian 

L L

is a

SCALAR

.

is invariant under coordinate transformation (Ch. 1). –

Also allowed:

Transformations which change

L

but leave the equations of motion unchanged. For example it can easily be shown that if

L

L + (d[f(q j ,t)]/dt),

this obviously changes

L

but leaves Lagrange Equations of motion unchanged. (Valid for

ANY f(q j ,t)!

).

• Always use the definition

L = T - U

. This is valid in a proper set of generalized coordinates.

L

can also contain an

arbitrary constant

. This comes from the arbitrary constant in PE

U

.

It doesn’t matter if we express L in terms of rectangular coordinates & velocities x α,i generalized coordinates & velocities q j & x & q j .

α,i or L = T(x α,i ) - U(x α,i ) (1)

• The transformation between rectangular & generalized coordinates & velocities is of the form:

x α,i = x α,i (q j ,t); x α,i = x α,i (q j ,q j ,t)

So, we also have 

Note!

L = T(q j ,q j ,t) - U(q j ,t) (2)

• The Lagrangians in

(1)

&

(2)

are the same! From

(2),

in generalized coordinates we have

L

L(q j ,q j ,t)

Hamilton’s Principle in generalized coordinates:

δ∫L(q

j

,q

j

,t) dt = 0

• This is again

identical

(limits

t 1 < t < t 2

) to the abstract calculus of variations problem of Ch. 6

with the replacements:

δJ

δ∫Ldt, x

t, y i (x)

q j (t) y i

(x)

(dq j (t)/dt) = q j (t) f[y i (x),y i

(x);x]

L(q j ,q j ,t)

The Lagrangian L satisfies Euler’s equations with these replacements!

• These become

Lagrange’s Equations in generalized coordinates:

(

L/

q

j

) - (d/dt)[(

L/

q

j

)] = 0 (A)

• For a system with

s

degrees of freedom and

m

constraints, there are

j = 1,2, ..,s

coupled

equations like

(A)

+

m

constraint equations.  Together, these

s +

m equations

give a complete description of the system motion

!

• Note that the

validity of Lagrange’s Equations requires

that: –

All forces

(other than constraint forces)

must be conservative

(that is a PE,

U

must exist).

• However, in graduate mechanics, it is shown how to generalize the Lagrangian formalism to dissipative (non-conservative) forces!

– The equations of constraint must be relations that connect the coordinates of particles & they may be functions of time:

f k (x α,i ,t) = 0, k = 1,2, .. m (B)

• Constraints which may be expressed in the form

(B)

Holonomic Constraints

.

• If the constraint equations,

(B)

, do not explicitly contain the time 

Fixed or Scleronomic Constraints

.

• Time dependent constraints 

Rhenomic Constraints

.

• Here, we only consider conservative forces & holonomic constraints.

Simple Example 7.3

• Projectile motion (with no air resistance). Find the equations of motion in both Cartesian & polar coordinates.

Cartesian: x

= horizontal,

y

= vertical

T = (½)mx 2 + (½)my 2 , U = mgy

L = T - U = (½)m(x 2

Lagrange’s Equations:

+ y 2 ) - mgy (

L/

x) - (d/dt)[(

L/

x)] = 0, (1) (

L/

x) = 0, (

L/

x) = mx, (d/dt)[(

L/

x)] = mx, (1)

x = 0 (

L/

y) - (d/dt)[(

L/

y)] = 0, (2). (

L/

y) = -mg, (

L/

y) = my (d/dt)[(

L/

y)] = my. (2)

mg + my = 0; y = -g

Polar: x = r cosθ , y = r sinθ r 2

=

x 2

+

y 2 ; tanθ = (y/x) T = (½)mr 2 + (½)mr 2 θ 2 U = mgr sinθ

L = T- U = (½)m(r 2 + r 2 θ 2 ) - mgr sinθ

Lagrange’s Eqtns:

(

L/

r) - (d/dt)[(

L/

r)] = 0, (3) (

L/

r) = mrθ 2 – mg sinθ, (

L/

r) = mr, (d/dt)[(

L/

r)] = mr (3)

rθ 2 – g sinθ - r = 0 (

L/

θ) - (d/dt)[(

L/

θ)] = 0, (4) (

L/

θ) = - mgr cosθ, (

L/

θ) = mr 2 θ (d/dt)[(

L/

θ)] = m(2rr θ + r 2 θ) (4)

gr cosθ + 2rr θ + r 2 θ = 0

Clearly, its simpler using Cartesian coordinates as the generalized coordinates!

Example 7.4 - Non-trivial!

• A particle, mass

m

, is constrained to move on the inside surface of a smooth cone of half angle

α

(figure). It is subject to gravity. Determine a set of generalized coordinates & determine the constraints. Find Lagrange’s Equations of motion.

Worked on the board!!

m Constraint: z = r cotα

Example 7.5

• See figure. The point of support of a simple pendulum of length

b

moves on a massless rim of radius

a

, rotating with a constant angular velocity

ω

. Obtain the expressions for the Cartesian components of the velocity and the acceleration of the mass

m

.

m (x,y)

 Obtain also the angular acceleration for the angle

θ

shown in the figure. Worked on the board!

Example 7.6

• See figure. Find the frequency of

small oscillations

of a simple pendulum placed in a railroad car that has a constant acceleration

a

in the

x

-direction. Worked on the board!!

Note: the railroad car is not an inertial frame!

g

Example 7.7

• A bead slides along a smooth wire bent in the shape of a parabola,

z = cr 2

as in the figure. The bead rotates in a circle or radius

R

when the wire is rotating about its vertical symmetry axis with angular velocity

ω

. Find the value of

c

. Worked on the board!

Example 7.8

• Consider the double pulley system shown in the figure. Use the coordinates indicated and determine the equations of motion. Worked on the board!