Transcript Chapter 2

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Lesson 2-1 Relations and Functions

Lesson 2-2 Linear Equations

Lesson 2-3 Slope

Lesson 2-4 Writing Linear Equations

Lesson 2-5 Modeling Real-World Data: Using Scatter Plots

Lesson 2-6 Special Functions

Lesson 2-7 Graphing Inequalities

Example 1 Domain and Range

Example 2 Vertical Line Test

Example 3 Graph Is a Line

Example 4 Graph Is a Curve

Example 5 Evaluate a Function

State the domain and range of the relation shown in the graph. Is the relation a function?

The relation is

(0

,

–2)

,

(–4

,

0) {(1

, ,

(–3 2)

, ,

(3 1)}

.

,

3)

,

Answer:

{–4

,

–3

, The domain is

0

,

1

,

3}

. The range is

{–2

,

0

,

1

,

2

,

3}

. Each member of the domain is paired with exactly one member of the range, so this relation is a function.

State the domain and range of the relation shown in the graph. Is the relation a function? Answer:

The domain is

{–3

, is

0

,

2

,

{–2

,

–1

,

3}

. The range

0

,

1}

. Yes, the relation is a function.

Transportation The table shows the average fuel efficiency in miles per gallon for light trucks for several years. Graph this information and determine whether it represents a function. Year

1995 1996 1997 1998 1999 2000 2001

Fuel Efficiency (mi/gal)

20.5

20.8

20.6

20.9

20.5

20.5

20.4

Year

1995 1996 1997 1998

Fuel Efficiency (mi/gal)

20.5

20.8

20.6

20.9

1999 2000 20.5

20.5

2001 Use the vertical line test. Notice that no vertical line can be drawn that contains more than one of the data points. 20.4

Answer:

Yes, this relation is a function.

Health The table shows the average weight of a baby for several months during the first year. Graph this information and determine whether it represents a function. Age (months)

1 2 4 6 9 12

Weight (pounds)

12.5

16 22 24 25 26

Answer:

Yes, this relation is a function.

Graph the relation represented by

Make a table of values to find ordered pairs that satisfy the equation. Choose values for

x

and find the corresponding values for

y

. Then graph the ordered pairs.

(2, 5)

x

–1 0 1 2

y

–4 –1 2 5 (1, 2) (0, –1) ( –1, –4)

Find the domain and range.

Since

x

can be any real number, there is an infinite number of ordered pairs that can be graphed. All of them lie on the line shown. Notice that every real number is the

x

-coordinate of some point on the line. Also, every real number is the

y

-coordinate of some point on the line.

( –1, –4)

Answer:

The domain and range are both all real numbers. (0, –1) (2, 5) (1, 2)

Determine whether the relation is a function.

This graph passes the vertical line test. For each

x

is exactly one

y

value, there value.

(2, 5) (1, 2)

Answer:

Yes, the equation represents a function.

(0, –1) ( –1, –4)

a. Graph Answer: b. Find the domain and range.

Answer:

The domain and range are both all real numbers.

c. Determine whether the relation is a function.

Answer:

Yes, the equation is a function.

Graph the relation represented by

Make a table. In this case, it is easier to choose

y

and then find the corresponding values for

x

. values Then sketch the graph, connecting the points with a smooth curve.

x

5 2 1 2 5

y

–2 –1 0 1 2 (5, 2) (2, 1) (1, 0) (2, –1) (5, –2)

Find the domain and range.

Every real number is the

y

-coordinate of some point on the graph, so the range is all real numbers. But, only real numbers that are greater than or equal to 1 are

x

-coordinates of points on the graph.

(5, 2) (2, 1) (1, 0) (2, –1) (5, –2)

Answer:

The domain is The range is all real numbers. .

Determine whether the relation is a function.

x

5 2 1 2 5

y

–2 –1 0 1 2 (2, 1) (1, 0) (5, 2) (2, –1) (5, –2) You can see from the table and the vertical line test that there are two

y

values for each

x

value except

x

= 1

.

Answer:

The equation a function. does not represent

a. Graph Answer: b. Find the domain and range.

Answer:

The domain is

{

x| x

–3}

. The range is all real numbers.

c. Determine whether the relation is a function.

Answer:

No, the equation represent a function.

does not

Given , find

Original function Substitute.

Simplify.

Answer:

Given find

Original function Substitute.

Multiply.

Simplify.

Answer:

Given , find

Original function Substitute.

Answer:

Given find each value.

a.

and Answer:

6

b.

Answer:

0.625

c.

Answer:

Example 1 Identify Linear Functions

Example 2 Evaluate a Linear Function

Example 3 Standard Form

Example 4 Use Intercepts to Graph a Line

State whether Explain. is a linear function. Answer:

This is a linear function because it is in the form

State whether Explain. is a linear function. Answer:

This is not a linear function because

x

exponent other than 1. has an

State whether Explain. is a linear function. Answer:

This is a linear function because it can be written as

State whether each function is a linear function. Explain.

a.

b.

c.

Answer:

yes;

Answer:

No;

x

has an exponent other than 1.

Answer:

No; two variables are multiplied together.

Meteorology The linear function can be used to find the number of degrees Fahrenheit,

f

(

C

)

, that are equivalent to a given number of degrees Celsius,

C

.

On the Celsius scale, normal body temperature is

37 

C

. What is normal body temperature in degrees Fahrenheit?

Original function Substitute.

Simplify.

Answer:

Normal body temperature, in degrees Fahrenheit, is 98.6

 F.

There are 100 Celsius degrees between the freezing and boiling points of water and 180 Fahrenheit degrees between these two points. How many Fahrenheit degrees equal 1 Celsius degree?

Divide 180 Fahrenheit degrees by 100 Celsius degrees.

Answer:

1.8

F = 1

C

Meteorology The linear function can be used to find the distance

d

(

s

)

in miles from a storm, based on the number of seconds

s

that it takes to hear thunder after seeing lightning.

a.

If you hear thunder 10 seconds after seeing lightning, how far away is the storm?

Answer:

2 miles

b.

If the storm is 3 miles away, how long will it take to hear thunder after seeing lightning?

Answer:

15 seconds

Write Answer: in standard form. Identify

A

,

B

, and

C

.

Original equation Subtract

3

x

from each side.

Multiply each side by that

A

0

.

–1

so and

Write and

C

. Answer: in standard form. Identify

A

,

B

,

Original equation Subtract

2

y

from each side.

Multiply each side by

–3

so that the coefficients are all integers.

and

Write and

C

. Answer: in standard form. Identify

A

,

B

,

Original equation Subtract

4

from each side.

Divide each side by

2

so that the coefficients have a GCF of

1

.

and

Write each equation in standard form. Identify

A

,

B

, and

C

.

a.

Answer:

and

b.

Answer: c. Answer:

and and

Find the

x

-intercept and the

y

-intercept of the graph of Then graph the equation.

The

x

-intercept is the value of

x

when Original equation Substitute

0

for

y

.

Add

4

to each side.

Divide each side by

–2

.

The

x

-intercept is

–2

. The graph crosses the

x

-axis at

(–2

,

0)

.

Likewise, the

y

-intercept is the value of

y

when Original equation Substitute

0

for

x

.

Add

4

to each side.

The

y

-intercept is

4

. The graph crosses the

y

-axis at

(0

,

4)

.

Use the ordered pairs to graph this equation.

Answer:

The

x

-intercept is

–2

, and the

y

-intercept is

4

. (0, 4) ( –2, 0)

Find the

x

-intercept and the

y

-intercept of the graph of Then graph the equation. Answer:

The

x

-intercept is

–2

, and the

y

-intercept is

6

.

Example 1 Find Slope

Example 2 Use Slope to Graph a Line

Example 3 Rate of Change

Example 4 Parallel Lines

Example 5 Perpendicular Line

Find the slope of the line that passes through

(1

, and

(–2

,

–3)

. Then graph the line.

3) Slope formula and Simplify.

Graph the two ordered pairs and draw the line. Use the slope to check your graph by selecting any point on the line. Then go up 2 units and right 1 unit or go down 2 units and left 1 unit. This point should also be on the line.

Answer:

The slope of the line is

2

. ( –2, –3) (1, 3)

Find the slope of the line that passes through

(2

, and

(–1

,

5)

. Then graph the line.

3)

Answer:

The slope of the line is

Graph the line passing through

(1

,

–3)

with a slope of

Graph the ordered pair

(1

,

–3)

. Then, according to the slope, go down 3 units and right 4 units. Plot the new point at

(5

,

–6)

. Draw the line containing the points. (1, –3) (5, –6)

Graph the line passing through

(2

, of

–3

.

5)

with a slope Answer:

Communication Refer to the graph. Find the rate of change of the number of radio stations on the air in the United States from 1990 to 1998.

Slope formula Substitute.

Simplify.

Answer:

Between 1990 and 1998, the number of radio stations on the air in the United States increased at an average rate of 0.225(1000) or 225 stations per year.

Computers Refer to the graph. Find the rate of change of the number of households with computers in the United States from 1984 to 1998. Answer:

The rate of change is 2.9 million households per year.

Graph the line through

(1

, line with the equation

–2)

that is parallel to the

The

x

-intercept is

–2

y

-intercept is

2

. and the Use the intercepts to graph The line rises 1 unit for every 1 unit it moves to the right, so the slope is 1.

Now, use the slope and the point at

(1

,

–2)

to graph the line parallel to (2, –1) (1, –2)

Graph the line through

(2

, line with the equation

3)

that is parallel to the Answer:

Graph the line through

(2

,

1)

to the line with the equation that is perpendicular

The

x

-intercept is or

1.5

and the

y

-intercept is

–1

. Use the intercepts to graph 2

x

– 3

y

= 3 The line rises 1 unit for every 1.5 units it moves to the right, so the slope is or

Graph the line through

(2

,

1)

to the line with the equation that is perpendicular

The slope of the line perpendicular is the opposite reciprocal of or (2, 1) 2

x

– 3

y

= 3 Start at

(2

,

1)

and go down 3 units and right 2 units. (4, –2) Use this point and

(2

, graph the line.

1)

to

Graph the line through

(–3

, to the line with the equation

1)

that is perpendicular Answer:

Example 1 Write an Equation Given Slope and a Point

Example 2 Write an Equation Given Two Points

Example 3 Write an Equation for a Real-World Situation

Example 4 Write an Equation of a Perpendicular Line

Write an equation in slope-intercept form for the line that has a slope of and passes through

(5

,

–2)

.

Slope-intercept form Simplify.

Add

3

to each side.

Answer:

The

y

-intercept is

1

. So, the equation in slope-intercept form is

Write an equation in slope-intercept form for the line that has a slope of and passes through

(–3

,

–1)

. Answer:

Multiple-Choice Test Item What is an equation of the line through

(2

, and

(–3

,

7)

?

–3)

A B C D Read the Test Item

You are given the coordinates of two points on the line. Notice that the answer choices are in slope-intercept form.

Solve the Test Item

First, find the slope of the line. Slope formula Simplify.

The slope is

–2

. That eliminates choices B and C.

Then use the point-slope formula to find an equation.

Point-slope form point for you can use either . Distributive Property Subtract

3

from each side.

Answer:

D

Multiple-Choice Test Item What is an equation of the line through

(2

, and

(–1

,

3)

?

5)

A C D B Answer:

C

Sales As a part-time salesperson, Jean Stock is paid a daily salary plus commission. When her sales are $100, she makes $58. When her sales are $300, she makes $78.

Write a linear equation to model this situation.

Let

x

be her sales and let

y

be the amount of money she makes. Use the points

(100, 58) (300, 78)

and to make a graph to represent the situation.

Slope formula Simplify.

Now use the slope and either of the given points with the point-slope form to write the equation.

Point-slope form Distributive Property Add

58

to each side.

Answer:

The slope-intercept form of the equation is

What are Ms. Stock’s daily salary and commission rate?

The

y

-intercept of the line is 48. The

y

-intercept represents the money Jean would make if she had no sales. Thus, $48 is her daily salary.

The slope of the line is 0.1. Since the slope is the coefficient of

x

, which is her sales, she makes 10% commission.

Answer:

Ms. Stock’s daily salary is $48, and she makes a 10% commission.

How much would Jean make in a day if her sales were $500?

Find the value of

y

when Use the equation you found in Example 3a.

Replace

x

with

500

.

Simplify.

Answer:

She would make $98 if her sales were $500.

Sales The student council is selling coupon books to raise money for the Humane Society. If the group sells 200 books, they will receive $150 dollars. If they sell 500 books, they will make $375.

a.

Write a linear equation to model this situation.

Answer: b.

Find the percentage of the proceeds that the student council receives.

Answer:

75%

c.

If they sold 1000 books, how much money would they receive to donate to the Humane Society?

Answer:

$750

Write an equation for the line that passes through

(3

,

–2)

and is perpendicular to the line whose equation is

The slope of the given line is

–5

. Since the slopes of perpendicular lines are opposite reciprocals, the slope of the perpendicular line is Use the point-slope form and the ordered pair

(3

, to write the equation.

–2)

Point-slope form Distributive Property Subtract

2

from each side.

Answer:

An equation of the line is

Write an equation for the line that passes through

(3

,

5)

and is perpendicular to the line whose equation is Answer:

Example 1 Draw a Scatter Plot

Example 2 Find and Use a Prediction Equation

Education The table below shows the approximate percent of students who sent applications to two colleges in various years since 1985. Make a scatter plot of the data. Years Since 1985 0 3 6 9 12 15 Percent 20 18 15 15 14 13

Source:

U.S. News & World Report

Graph the data as ordered pairs, with the number of years since 1985 on the horizontal axis and the percentage on the vertical axis.

Safety The table below shows the approximate percent of drivers who wear seat belts in various years since 1994. Make a scatter plot of the data. Years Since 1994 0 1 2 3 4 5 6 7 Percent 57 58 61 64 69 68 71 73

Source: National Highway Traffic Safety Administration

Education The table and scatter plot below show the approximate percent of students who sent applications to two colleges in various years since 1985.

Draw a line of fit for the data. How well does the line fit the data?

Years Since 1985 0 3 6 9 12 15 Percent 20 18 15 15 14 13

Source:

U.S. News & World Report

The points

(3

,

18)

and

(15

,

13)

appear to represent the data well.

Draw a line through these two points.

Education The table and scatter plot below show the approximate percent of students who sent applications to two colleges in various years since 1985.

Draw a line of fit for the data. How well does the line fit the data?

Years Since 1985 0 3 6 9 12 15 Percent 20 18 15 15 14 13

Source:

U.S. News & World Report

Answer:

Except for

(6

,

15)

, this line fits the data fairly well.

Find a prediction equation. What do the slope and

y

-intercept indicate?

Find an equation of the line through

(3

, Begin by finding the slope.

18)

and

(15

,

13)

.

Slope formula Substitute.

Simplify.

Point-slope form Distributive Property Add

18

to each side.

Answer:

One prediction equation is The slope indicates that the percent of students sending applications to two colleges is falling at about 0.4% each year. The

y

-intercept indicates that the percent in 1985 should have been about 19%.

Predict the percent in 2010.

The year 2010 is 25 years after 1985, so use the prediction equation to find the value of

y

when Prediction equation Simplify.

Answer:

The model predicts that the percent in 2010 should be about 9%.

How accurate is this prediction? Answer:

The fit is only approximate, so the prediction may not be very accurate.

Safety The table and scatter plot show the approximate percent of drivers who wear seat belts in various years since 1994.

Years Since 1994 0 1 2 3 4 5 6 7 Percent 57 58 61 64 69 68 71 73

Source: National Highway Traffic Safety Administration

a.

Draw a line of fit for the data. How well does the line fit the data?

Answer:

Except for

(4

,

69)

, this line fits the data very well.

b.

Find a prediction equation. What do the slope and

y

-intercept indicate?

Answer:

Using

(1

,

58)

and

(7

,

73)

, an equation is

y

= 2.5

x

+ 55.5

. The slope indicates that the percent of drivers wearing seatbelts is increasing at a rate of 2.5% each year. The

y

-intercept indicates that, according to the trend of the rest of the data, the percent of drivers who wore seatbelts in 1994 was about 56%.

c.

Predict the percent of drivers who will be wearing seat belts in 2005.

Answer:

83%

d.

How accurate is the prediction?

Answer:

Except for the outlier, the line fits the data very well, so the predicted value should be fairly accurate.

Example 1 Step Function

Example 2 Constant Function

Example 3 Absolute Value Functions

Example 4 Piecewise Function

Example 5 Identify Functions

Psychology One psychologist charges for counseling sessions at the rate of $85 per hour or any fraction thereof. Draw a graph that represents this solution. Explore Plan

The total charge must be a multiple of $85, so the graph will be the graph of a step function.

If the session is greater than 0 hours, but less than or equal to 1 hour, the cost is $85. If the time is greater than 1 hour, but less than or equal to 2 hours, then the cost is $170, and so on.

Solve

Use the pattern of times and costs to make a table, where

x

session and

C

(

x

)

the graph. is the number of hours of the is the total cost. Then draw

x C(x)

85 170 255 340 425

Answer: Examine

Since the psychologist rounds any fraction of an hour up to the next whole number, each segment on the graph has a circle at the left endpoint and a dot at the right endpoint.

Sales The Daily Grind charges $1.25 per pound of meat or any fraction thereof. Draw a graph that represents this situation.

Answer:

Graph

For every value of horizontal line.

x

–2 0 1 0.5

g(x) = –3 g(x)

–3 –3 –3 –3 The graph is a

Answer:

Graph Answer:

Graph and on the same coordinate plane. Determine the similarities and differences in the two graphs.

Find several ordered pairs for each function.

x

0 1 2 3 4 5

| x – 3 |

3 2 1 0 1 2

x

–4 –3 –2 –1 0 1

| x + 2 |

2 1 0 1 2 3

Graph the points and connect them.

Answer:

• The domain of both graphs is all real numbers. • The range of both graphs is • The graphs have the same shape, but different

x

-intercepts. • The graph of

g

(

x

)

graph of

f

(

x

)

is the translated left 5 units.

Graph and on the same coordinate plane. Determine the similarities and differences in the two graphs.

Answer:

• The domain of both graphs is all real numbers. • The range of is is The range of • The graphs have the same shape, but different

y

-intercepts. • The graph of

g

(

x

)

is the graph of translated up 5 units.

f

(

x

)

Graph and range.

Identify the domain Step 1

Graph the linear function for Since

3

satisfies this inequality, begin with a closed circle at

(3

,

2)

.

Graph and range.

Identify the domain Step 2

Graph the constant function Since

x

not satisfy this does inequality, begin with an open circle at

(3

,

–1)

and draw a horizontal ray to the right.

Graph and range.

Identify the domain Answer:

The function is defined for all values of

x

, so the domain is all real numbers. The values that are

y

-coordinates of points on the graph are all real numbers less than or equal to

–2

, so the range is

Graph and range.

Answer:

The domain is all real numbers. The range is

Identify the domain

Determine whether the graph represents a step function, a constant function, an absolute value function, or a piecewise function. Answer:

Since this graph consists of different rays and segments, it is a piecewise function.

Determine whether the graph represents a step function, a constant function, an absolute value function, or a piecewise function. Answer:

Since this graph is V-shaped, it is an absolute value function.

Determine whether each graph represents a step function, a constant function, an absolute value function, or a piecewise function.

a.

b. Answer:

constant function

Answer:

absolute value function

Example 1 Dashed Boundary

Example 2 Solid Boundary

Example 3 Absolute Value Inequality

Graph

The boundary is the graph of Since the inequality symbol is <, the boundary will be dashed. Use the slope-intercept form,

Graph

Test

(0

,

0)

.

Original inequality true Shade the region that contains

(0

,

0)

.

Graph Answer:

Education The SAT has two parts. One tutoring company advertises that it specializes in helping students who have a combined score on the SAT that is 900 or less.

Write an inequality to describe the combined scores of students who are prospective tutoring clients.

Let

x

be the first part of the SAT and let

y

be the second part. Since the scores must be 900 or less, use the  symbol.

The 1 st part

x

Answer:

and 2 nd part together

y

are less than or equal to  900.

900

Graph the inequality.

Since the inequality symbol is  , the graph of the related linear equation is solid. This is the boundary of the inequality.

Graph the inequality.

Test

(0

,

0)

.

Original inequality true

Graph the inequality.

Shade the region that contains

(0

,

0)

. Since the variables cannot be negative, shade only the part in the first quadrant.

Does a student with a verbal score of 480 and a math score of 410 fit the tutoring company’s guidelines?

The point

(480

,

410)

is in the shaded region, so it satisfies the inequality.

Answer:

Yes, this student fits the tutoring company’s guidelines.

Class Trip Two social studies classes are going on a field trip. The teachers have asked for parent volunteers to also go on the trip as chaperones. However, there is only enough seating for 60 people on the bus. a.

Write an inequality to describe the number of students and chaperones that can ride on the bus.

Answer:

b.

Graph the inequality.

Answer: c.

Can 45 students and 10 chaperones go on the trip?

Answer:

yes

Graph

Since the inequality symbol is  , the graph of the related equation is solid. Graph the equation.

Test

(0

,

0)

.

Original inequality Shade the region that contains

(0

,

0)

.

true

Graph Answer:

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