Circular Geometry Robust Constructions Proofs Chapter 4 Axiom Systems: Ancient and Modern Approaches • Euclid’s definitions  A point is that which has no part  A.

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Transcript Circular Geometry Robust Constructions Proofs Chapter 4 Axiom Systems: Ancient and Modern Approaches • Euclid’s definitions  A point is that which has no part  A.

Circular Geometry
Robust Constructions
Proofs
Chapter 4
Axiom Systems:
Ancient and Modern Approaches
• Euclid’s definitions
 A point is that which has no part
 A line is breadthless length
 A straight line is a line which lies evenly with
the points on itself
 etc.
• We need clarification
Axiom Systems:
Ancient and Modern Approaches
• David Hilbert redefined, clarified
 Cleaned up ambiguities
• Basic objects of geometry
 point
 line
considered undefined terms
 plane
• Many geometry texts use Hilbert’s axioms
Language of Circles
• Definition:
 Set of points
 Fixed distance from point A
 Distance called the radius
 A called the center
• Interior: P : d ( A, B)  r
• Exterior: P : d ( A, B)  r
Language of Circles
• Chord of a circle:
Line segment joining
two points on the circle
• Diameter: a chord
containing the center
• Tangent: a line containing exactly one
point of the circle
 Will be perpendicular to radius at that point
Language of Circles
• Circumference:
Length of the
perimeter
• Sector:
Pie shaped portion
bounded by arc and
two radii
Language of Circles
• Segment:
Region bounded by
arc and chord
• Central angle
CAB, center is the
angle vertex
Language of Circles
• Inscribed angle
CDB Vertex is on the
circle
 Also called an angle
subtended by chord CB
Inscribed Angles
• Recall results of recent activity 1.4, 1.5 …
• Note fixed relationship between central
and inscribed angle subtending same arc
Language of Circles
• What would the conjecture of Activity 1.7
have to do with this figure from Activity 1.9
• What conjecture would you make here?
Language of Circles
• Recall conjecture made in Activity 1.8
• This also is a consequence of what we
saw in Activity 1.7
Language of Circles
• Any triangle will be cyclic (vertices lie on a
circle)
• Is this true for any four non collinear
points?
Language of Circles
• Some quadrilaterals will be cyclic
• Again, note the properties of such a
quadrilateral
Language of Circles
• Using the results of this activity
• Construct a line through a point exterior to
a circle and tangent to a circle
Robust Constructions
Developing visual proof
• Distinction between
 “drawing” and
 “construction”
• In Sketchpad and Goegebra
 Allowable constructions based on Euclid’s
postulates
• Constructions develop visual proof
 Guide us in making step by step proofs
Step-by-Step Proofs
• Each line of the proof presents
 A new idea or concept
• Together with previous steps
 Produces new result
Allowable Argument Justifications
• Site the given conditions
• Base argument on
 Definitions
 Postulates and axioms
• Constructions implicitly linked to axioms,
postulates
Allowable Argument Justifications
• Any previously proved theorem
• Previous step in current proof
• “Common notions”
 Properties of equality, congruence
 Arithmetic, algebraic computations
 Rules of logic
Methods of Proof
1. Start by being sure of what is given
2. Clearly state the conjecture or theorem
a) P  Q
b)
If hypotheses then conclusion
3. Note the steps of Geogebra construction
a) Steps of proof may well follow similar order
4. Proof should stand up to questioning of
colleagues
Direct Proof
• Start with given, work step by step towards
conclusion
• Goal is to show P  Q using modus
ponens
 Based on P, show sufficient conditions to
conclude Q
• Use syllogism: P  R, R  S, S  Q
then
PQ
Indirect Proof
• Use logic role of modus tollens
P  Q is equivalent to  Q   P
• We assume  Q
• Then work step by step to show that P
cannot be true
 That is  P
Indirect Proof
• Alternatively we use this fact
 P  Q  P  Q
• Begin by assuming P and not Q
• Use logical reasoning to look for
contradiction
• This gives us  P  Q
• Which means that P  Q must be true
Counter Examples
• Consider a conjecture you make P  Q
 You create a Geogebra diagram to illustrate
your conjecture
• Then you discover a specific example
where all the requirements of P hold true
 But Q is definitely not true
• This is a counter example to show that
 P  Q 
If-And-Only-If Proofs
• This means that P  Q and
• Also written P  Q
QP
• Proof must proceed in both directions
 Assume P, show Q is true
 Assume Q, show P is true
Proofs
• Constructed diagrams provide
 visual proof
 demonstration of geometric theorems
• Consider this diagram
• How might it help
us prove that the
non adjacent angles of
a cyclic quadrilateral
are supplementary.
Proof of Theorem 4.3
• Assume ABCD cyclic
• Consider pair of non-adjacent
angles BAD, BCD
• Let arc BAD be arc subtending
angle a, BCD be arc subtending b
1
• We know a + b = 360 and 2 (a  b)  180
• Also ½ a = BAD , ½ b = BCD
• So BAD  BCD  180
• And they are supplementary
Incircles and Excircles
• Consider concurrency of angle bisectors of
exterior angles
• Perpendicular
PJ gives radius
for excircle
• Note the other
exterior angles
are congruent
• How to show tangency points M and N?
Incircles and Excircles
• Proof : Drop perpendiculars from P to
lines XY and
XZ
• Look for
congruent
right triangles
• Finish the
proof
Families of Circles
• Orthogonal circles:
Tangents are
perpendicular at
points of intersection
• Describe how you
constructed these in Activity 8.
• How would you construct more circles
orthogonal to circle A?
Orthogonal Circles
• Describe what happens when point Q
approaches infinity.
Families of Circles
• Circles that share a common chord
• Note centers are collinear
 Use this to construct more circles with chord AB
The Arbelos and Salinon
• Figures bounded by semicircular arcs
• What did you discover about the arbelos in
Activity 7?
The Arbelos and Salinon
• Note the two areas – the arbelos and the
circle with diameter RP
The Arbelos
Algebraic proof
• Calculate areas of all
the semicircles
• Calculate the are of circle
with diameter RP
• Show equality
Power of a Point
• We are familiar with the concept of a
2
3
function
f ( x)  6 x  9 x
 Examples:
g ( x, y)  3x  7 xy  4 y 2
• Actually Geogebra commands are
functions that take points and/or lines as
parameters
Power of a Point
• Consider a mathematical function
involving distances with a point and a
circle
Power of a Point
• This calculation clams to be another way
to calculate Power (P, C)
Power of a Point
• Requirements for calculating Power (P, C)
 Given radius, r, of circle O and distance d
(length of PO) use
d r
2
or …
2
 Given line intersecting circle O at Q and R
with collinear point P use
PQ  PR
Point at Infinity
• Recall stipulation P
cannot be at O
• As P approaches
O, P’ gets infinitely
far away
• This is a “point at infinity” (denoted by )
• Thus Inversion(O, C) = 
The Radical Axis
• Consider Power as a measure of
 Distance d from P to given circle
• If radius = 0, Power is d2
• Consider two circles, centered at A, B
 Point P has a power for each
 There will be some points P where Power is
equal for both circles
 Set of such points called radical axis
The Radical Axis
• Set of points P with Power equal will be 
bisector of segment AB
• Construction when circles do not
intersect?
The Radical Axis
• Suppose three circles are given for which
the centers are not collinear.
 Each pair of circles determines a radical axis,
 These three radical axes are concurrent.
Nine-Point Circle (2nd Pass)
• Recall circle which intersects feet of
altitudes (Activity 2.8)
Nine-Point Circle
• Note all the points which lie on this circle
Nine-Point Circle
• Additional phenomena
 Nine point circle tangent to incircle and
excircles
Circular Geometry
Robust Constructions
Proofs
Chapter 4