5.5 Inequalities in One Triangle Geometry Mrs. Spitz Fall, 2004 Objectives: • Use triangle measurements to decide which side is longest or which angle is largest. • Use.
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Geometry Mrs. Spitz Fall, 2004
5.5 Inequalities in One Triangle
Objectives:
• Use triangle measurements to decide which side is longest or which angle is largest.
• Use the Triangle Inequality
Assignment
pp. 298-300 #1-25, 34
Objective 1: Comparing Measurements of a Triangle
• In activity 5.5, you may have discovered a relationship between the positions of the longest and shortest sides of a triangle and the position of its angles.
The diagrams illustrate Thms. 5.10
and 5.11.
longest side smallest angle largest angle shortest side
Theorem 5.10
If one side of a triangle is longer than another side, then the angle opposite the longer side is larger than the angle opposite the shorter side.
A 3 m A B > m C 5 C
Theorem 5.11
If one ANGLE of a triangle is larger than another ANGLE, then the D 60 ° 40 ° SIDE opposite larger angle is the F longer than the side opposite the smaller angle.
EF > DF You can write the measurements of a triangle in order from least to greatest. E
Ex. 1: Writing Measurements in Order from Least to Greatest
Write the measurements of the triangles from least to greatest.
a. m G < m H < m J H JH < JG < GH 45 ° J 100° 35 ° G
Ex. 1: Writing Measurements in Order from Least to Greatest
Write the measurements of the triangles from least to greatest.
Q 8 5 7 b. QP < PR < QR m R < m Q < m P P R
Paragraph Proof – Theorem 5.10
A Given►AC > AB Prove ►m ABC > m C 2 D 1 3 B Use the Ruler Postulate to locate a point D on AC such that DA = BA. Then draw the segment BD. In the isosceles triangle ∆ABD, 1 ≅ 2. Because m ABC = m 1+m 3, it follows that C m ABC > m 1. Substituting m 2 for m 1 produces m ABC > m 2. Because m 2 = m 3 + m C, m 2 > m C. Finally because m ABC > m 2 and m 2 > m C, you can conclude that m ABC > m C.
NOTE:
The proof of 5.10 in the slide previous uses the fact that 2 is an exterior angle for m ∆BDC, so its measure is the sum of the measures of the two nonadjacent interior angles. Then 2 must be greater than the measure of either nonadjacent interior angle. This result is stated in Theorem 5.12
Theorem 5.12-Exterior Angle Inequality
• The measure of an exterior angle of a triangle is greater than the measure of either of the two non adjacent interior angles.
• m 1 > m A and m 1 > m B A 1 C B
Ex. 2: Using Theorem 5.10
• DIRECTOR’S CHAIR. In the director’s chair shown, AB ≅ AC and BC > AB. What can you conclude about the angles in ∆ABC?
A B C
Ex. 2: Using Theorem 5.10
Solution
• Because AB ∆ABC is isosceles, so B ≅ ≅ AC, C. Therefore, m B = m C. Because BC>AB, m A > m C by Theorem 5.10. By substitution, m A > m B. In addition, you can conclude that m A >60 ° , m B< 60 ° , and m C < 60 ° .
B A C
Objective 2: Using the Triangle Inequality
• Not every group of three segments can be used to form a triangle. The lengths of the segments must fit a certain relationship.
Ex. 3: Constructing a Triangle
a. 2 cm, 2 cm, 5 cm b. 3 cm, 2 cm, 5 cm c. 4 cm, 2 cm, 5 cm Solution: Try drawing triangles with the given side lengths. Only group (c) is possible. The sum of the first and second lengths must be greater than the third length.
Ex. 3: Constructing a Triangle
a. 2 cm, 2 cm, 5 cm b. 3 cm, 2 cm, 5 cm c.
4 cm, 2 cm, 5 cm 2 5 2 A 3 5 C D 2 B A 4 5 D 2 B
Theorem 5.13: Triangle Inequality
• The sum of the lengths of any two sides of a Triangle is greater than the length of the third side.
AB + BC > AC AC + BC > AB AB + AC > BC C B A
Ex. 4: Finding Possible Side Lengths
• A triangle has one side of 10 cm and another of 14 cm. Describe the possible lengths of the third side • SOLUTION: Let x represent the length of the third side. Using the Triangle Inequality, you can write and solve inequalities.
x + 10 > 14 x > 4 10 + 14 > x 24 > x ►So, the length of the third side must be greater than 4 cm and less than 24 cm.
#24 - homework
x + 2 A • Solve the inequality: AB + AC > BC.
B 3x - 2 x + 3 C (x + 2) +(x + 3) > 3x – 2 2x + 5 > 3x – 2 5 > x – 2 7 > x
5. Geography
AB + BC > AC MC + CG > MG 99 + 165 > x 264 > x 99 miles Masbate x + 99 < 165 x < 66 Cadiz 165 miles 66 < x < 264 Guiuan