The Area Between Two Curves Lesson 6.1 When f(x) • Consider taking the definite integral for the function shown below. a b b  f (

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Transcript The Area Between Two Curves Lesson 6.1 When f(x) • Consider taking the definite integral for the function shown below. a b b  f (

The Area Between Two Curves
Lesson 6.1
When f(x) < 0
• Consider taking the definite integral for the
function shown below.
a
b
b
 f ( x)dx
f(x)
a
• The integral gives a ___________ area
• We need to think of this in a different way
Another Problem
• What about the area between the curve and the
x-axis for y = x3
• What do you get for
the integral?
2
3
x
 dx
2
• Since this makes no sense – we need another way
to look at it
Solution
• We can use one of the properties of integrals
___
b
 f ( x)dx  
a
___
f ( x )dx 
___

f ( x )dx
___
• We will integrate separately for
_________ and __________
2
3
x
 dx 
2
0
2
2
0
3
3
x
dx

x

 dx
We take the absolute
value for the interval
which would give us a
negative area.
General Solution
• When determining the area between a
function and the x-axis
• Graph the function first
• Note the ___________of the function
• Split the function into portions
where f(x) > 0 and f(x) < 0
• Where f(x) < 0, take
______________ of the
definite integral
Try This!
• Find the area between the function
h(x)=x2 – x – 6 and the x-axis
• Note that we are not given the limits of
integration
• We must determine ________
to find limits
• Also must take absolute
value of the integral since
specified interval has f(x) < 0
Area Between Two Curves
• Consider the region between
f(x) = x2 – 4 and g(x) = 8 – 2x2
• Must graph to determine limits
• Now consider function inside
integral
• Height of a slice is _____________
• So the integral is
The Area of a Shark Fin
• Consider the region enclosed by
f ( x)  9  9x
g( x)  9  x
x  axis
• Again, we must split the region into two parts
• _________________ and ______________
Slicing the Shark the Other Way
f ( x)  9  9x
g( x)  9  x
x  axis
• We could make these graphs as ________________
1
j ( y )  x   9  y 2  and
9
• Now each slice is
_______ by (k(y) – j(y))
k ( y)  x  9  y 2
Practice
• Determine the region bounded between the
given curves
• Find the area of the region
y x
y  x2  6
Horizontal Slices
• Given these two equations, determine the
area of the region bounded by the two curves
• Note they are x in terms of y
x  8 y
x y
2
2
Assignments A
• Lesson 7.1A
• Page 452
• Exercises 1 – 45 EOO
Integration as an Accumulation Process
• Consider the area under the curve y = sin x
b
• Think of integrating as an accumulation of the
areas of the rectangles from 0 to b
___

0
sin x dx
Integration as an Accumulation Process
• We can think of this as a function of b
b
______   sin x dx   cos ( x) 0   cos b  1
b
0
• This gives us the accumulated area under the
curve on the interval [0, b]
Try It Out
• Find the accumulation function for
1 2

F ( x)    t  2  dt
2

0
x
• Evaluate
• F(0)
• F(4)
• F(6)
Applications
• The surface of a machine part is the region
between the graphs of y1 = |x| and
y2 = 0.08x2 +k
• Determine the value for k if the two functions
are tangent to one another
• Find the area of the surface of the machine
part
Assignments B
• Lesson 7.1B
• Page 453
• Exercises 57 – 65 odd, 85, 88
Volumes – The Disk Method
Lesson 7.2
Revolving a Function
• Consider a function f(x)
f(x)
on the interval [a, b]
a
• Now consider revolving
b
that segment of curve
about the x axis
• What kind of functions generated these solids
of revolution?
Disks
f(x)
• We seek ways of using
integrals to determine the
volume of these solids
• Consider a disk which is a
slice of the solid
• What is the radius
• What is the thickness
• What then, is its volume?
Volume of slice = ___________
dx
Disks
• To find the volume of the
whole solid we sum the
volumes of the disks
• Shown as a definite integral
V  _____________
f(x)
a
b
Try It Out!
• Try the function y = x3 on the interval
0 < x < 2 rotated
about x-axis
Revolve About Line Not a Coordinate Axis
• Consider the function y = 2x2 and the
boundary lines y = 0, x = 2
• Revolve this region about the line x = 2
• We need an
expression for
the radius
_______________
Washers
• Consider the area
between two functions
rotated about the axis
f(x)
g(x)
a
• Now we have a hollow solid
• We will sum the volumes of washers
• As an integral
b
V    __________  _________dx
a
b
Application
• Given two functions y = x2, and y = x3
• Revolve region between about x-axis
What will be the
limits of
integration?
1
V    _______________ dx
0
Revolving About y-Axis
• Also possible to revolve a function about the
y-axis
• Make a disk or a washer to be ______________
• Consider revolving a parabola about the
y-axis
• How to represent the
radius?
• What is the thickness
of the disk?
Revolving About y-Axis
• Must consider curve as
x = f(y)
• Radius ____________
• Slice is dy thick
• Volume of the solid rotated
about y-axis
____
V  ______
  f ( y) dy
2
____
Flat Washer
• Determine the volume of the solid generated
by the region between y = x2 and y = 4x,
revolved about the y-axis
• Radius of inner circle?
• f(y) = _____
• Radius of outer circle?
• f ( y)  ______
• Limits?
• 0 < y < 16
Cross Sections
• Consider a square at x = c
with side equal to
side s = f(c)
a c
• Now let this be a thin
slab with thickness Δx
• What is the volume of the slab?
• Now sum the volumes of all such slabs
ba
__________

n
i 1
n
f(x)
b
Cross Sections
ba
 f ( xi ) 

n
i 1
n
2
f(x)
• This suggests a limit
and an integral
a
c
ba
lim   f ( xi ) 
 _____________
n 
n
i 1
n
2
b
Cross Sections
• We could do similar
summations (integrals)
for other shapes
• Triangles
• Semi-circles
• Trapezoids
f(x)
a
c
b
Try It Out
• Consider the region bounded
• above by y = cos x
• below by y = sin x
• on the left by the y-axis
• Now let there be slices of equilateral triangles
erected on each cross section perpendicular
to the x-axis
• Find the volume
Assignment
• Lesson 7.2A
• Page 463
• Exercises 1 – 29 odd
• Lesson 7.2B
• Page 464
• Exercises 31 - 39 odd, 49, 53, 57
Volume: The Shell Method
Lesson 7.3
4
3
Find the volume generated when2
this shape is revolved about the 1
y axis.
0
1
2
3
y
4

5
6
4 2
x  10 x  16
9
7
8

We can’t solve for x, so
we can’t use a
horizontal slice
directly.

4
3
2
1
If we take a
____________slice
and revolve it
about the y-axis
we get a cylinder.
0
1
2
3
y
4

5
6
4 2
x  10 x  16
9
7
8


Shell Method
• Based on finding volume of cylindrical shells
• Add these volumes to get the total volume
• Dimensions of the shell
• _________of the shell
• _________of the shell
• ________________
The Shell
• Consider the shell as one of many of a solid of
dx
revolution
f(x)
f(x) – g(x)
x
g(x)
• The volume of the solid made of the sum of
the shells
Try It Out!
• Consider the region bounded by x = 0,
y = 0, and
y  8  x2
V  2
2 2

0
x  8  x 2 dx
Hints for Shell Method
•
•
•
•
Sketch the __________over the limits of integration
Draw a typical __________parallel to the axis of revolution
Determine radius, height, thickness of shell
Volume of typical shell
2  ____ radius  ________ thickness
• Use integration formula
b
Volume  2    radius  height  thickness
a
Rotation About x-Axis
• Rotate the region bounded by y = 4x and
y = x2 about the x-axis
thickness = _____
_______________ = y
• What are the dimensions needed?
• radius
• height
• thickness
height = _________
y

V  2  y   y   dy
4

0
16
Rotation About Non-coordinate Axis
• Possible to rotate a region around any line
g(x)
f(x)
x=a
• Rely on the basic concept behind the shell
method
Vs  2    radius  height  thickness
Rotation About Non-coordinate Axis
• What is the radius?
r
g(x)
f(x)
a–x
• What is the height?
x=c
x=a
f(x) – g(x)
• What are the limits?
c<x<a
• The integral:
a
V   __________  f ( x)  g ( x) dx
c
Try It Out
• Rotate the region bounded by 4 – x2 ,
x = 0 and, y = 0 about the line x = 2
• Determine radius, height, limits
Try It Out
• Integral for the volume is
2
V  2  __________________ dx
0
Assignment
• Lesson 7.3
• Page 472
• Exercises 1 – 25 odd
• Lesson 7.3B
• Page 472
• Exercises 27, 29, 35, 37, 41, 43, 55
Arc Length and Surfaces of
Revolution
Lesson 7.4
Arc Length
• We seek the distance
along the curve from
f(a) to f(b)
P0
P1
Pi
•
••
•
• •
b
a
• That is from P0 to Pn
Pn
• The distance formula for each pair of points
d ( Pi 1 , Pi ) 
What is another way
of representing this?


 xi  xi 1    f ( xi )  f ( xi 1 )
2
2
 xi    yi 
2
2
xi
Why?
Arc Length
• We sum the individual lengths
n
L   1   f '( xi ) dx
2
i 1
• When we take a limit of the above, we get the
integral
L  ___________________
Arc Length
• Find the length of the arc of the function for
1<x<2
4
x
1
y
4

8x2
Surface Area of a Cone
• Slant area of a cone
A   r s
s
h
r
• Slant area of
frustum

A  2 

L

L

Surface Area
• Suppose we rotate the
f(x) from slide 2 around
the x-axis
• A surface is formed
• A slice gives a __________
Δx
P0
P1
•
••
a
Pi
Pn
•
• •
xi •
b
Δs
2
 Rr 
S  2 
 s  2  _______ 1   f '( x) x
 2 
Surface Area
• We add the cone frustum areas of all the slices
• From a to b
• Over entire length of the curve
b
S   _________ 1   f '( xi )  dx
2
a
b
 2  ________ 1   f '( xi )  dx
2
a
Surface Area
• Consider the surface generated by the curve
y2 = 4x for 0 < x < 8 about the x-axis
y  4x
Surface Area
• Surface area =
Limitations
• We are limited by what functions we can
integrate
b
S  2  f ( x) 1   f '( xi ) dx
2
a
• Integration of the above expression is not
_________________________
• We will come back to applications of arc
length and surface area as new integration
techniques are learned
Assignment
• Lesson 7.4
• Page 383
• Exercises 1 – 29 odd
also 37 and 55,
Work
Lesson 7.5
Work
• Definition
The product of
• The ____________exerted on an object
• The _______________the object is moved by the
force
• When a force of 50 lbs is exerted to move an
object 12 ft.
• 600 ft. lbs. of work is done
50
12 ft
Hooke's Law
• Consider the work done to
stretch a spring
• Force required is proportional to _________
• When k is constant of proportionality
• Force to move dist x =
k  x  F ( x)
• Force required to move through i th interval, x
• W = F(xi) x
x
a
b
Hooke's Law
• We sum those values using the definite
integral
• The work done by a ____________force F(x)
• Directed along the x-axis
• From x = a to x = b
b
W   F ( x) dx
a
Hooke's Law
• A spring is stretched 15 cm by a
force of 4.5 N
• How much work is needed to stretch the spring 50
cm?
F  kx
• What is F(x) the force function?
0.5
• Work done?
W
 30x dx
0
4.5  k  0.15
30  k
F ( x )  30 x
Winding Cable
• Consider a cable being wound up by a winch
• Cable is 50 ft long
• 2 lb/ft
• How much work to wind in 20 ft?
• Think about winding in y amt
• y units from the top  50 – y ft hanging
• dist = y
• force required (weight) =2(50 – y)
Pumping Liquids
• Consider the work needed to pump a liquid
into or out of a tank
• Basic concept:
Work = weight x _____________
• For each V of liquid
• Determine __________
• Determine dist moved
• Take summation (__________________)
Pumping Liquids – Guidelines
r
• Draw a picture with the
b
coordinate system
a
• Determine _______of thin
horizontal slab of liquid
• Find expression for work needed to lift this
slab to its destination
• Integrate expression from bottom of liquid to
a
the top
W       r 2 _________ dy
0
Pumping Liquids
• Suppose tank has
8
4
• r=4
• height = 8
• filled with petroleum (54.8 lb/ft3)
• What is work done to pump oil over top
• Disk weight? Weight  _________________
___________
• Distance moved?
• Integral?
Work Done by Expanding Gas
• Consider a piston of radius r in a cylindrical
casing as shown here
• Let p = pressure in lbs/ft2
• Let V = volume of gas in ft3
• Then the work increment
involved in moving the piston
Δx feet is
W  __________________
Work Done by Expanding Gas
• So the total work done is the summation of all
those increments as the gas
expands from V0 to V1
W
V1
 p  dV
V0
• Pressure is inversely proportional
V1
to volume
W
so p _________ and
V0
 dV
Work Done by Expanding Gas
• A quantity of gas with initial volume of
1 cubic foot and a pressure of 2500 lbs/ft2
expands to a volume of 3 cubit feet.
• How much work
was done?
Assignment A
• Lesson 7.5
• Page 405
• Exercises 1 – 41 EOO
Moments, Center of Mass,
Centroids
Lesson 7.6
Mass
• Definition: mass is a measure of a body's
____________to changes in motion
• It is ___________ a particular gravitational system
• However, mass is sometimes equated with __________
(which is not technically correct)
• Weight is a type of ___________… dependent on gravity
Mass
• The relationship is Force  __________________
• Contrast of measures of mass and force
System
Measure of
Mass
Measure of
Force
U.S.
Slug
Pound
International
Kilogram
Newton
C-G-S
Gram
Dyne
Centroid
• Center of mass for a system
• The point where all the mass seems to be
concentrated
• If the mass is of constant density this point is
called the __________________
4kg
10kg
•
6kg
Centroid
• Each mass in the system has a "moment"
• The product of ____________________________
from the origin
4kg
10kg
6kg
• "First moment" is the __________of all the
moments
• The centroid is
m1 x1  m2 x2
x
m1  m2
Centroid
• Centroid for multiple points
n
x
m x
i 1
n
i i
 mi
First moment of
the system
Also notated My,
moment about
y-axis
n
i 1
y
• Centroid about x-axis
Also
notated Mx,
moment
about
x-axis
m y
i 1
n
i
i
m
i 1
i
Centroid
• The location of the centroid is the ordered pair
(x, y)
x
My
m
Mx
y
m
• Consider a system with 10g at (2,-1), 7g at (4, 3),
and 12g at (-5,2)
• What is the center of mass?
Centroid
• Given 10g at (2,-1), 7g at (4, 3), and 12g at (5,2)
12g
7g
10g
M y  _______________________
M x  1______________________
m  10  7  12
x ?
y ?
Centroid
• Consider a region under
a curve of a material of
uniform density
•
• We divide the region into
a
b
x
____________
• Mass of each considered to be centered at
_______________________center
• Mass of each is the product of the density, ρ and
the area
• We sum the products of distance and mass
Centroid of Area Under a Curve
• First moment with respect
b
to the y-axis
M y     x  f ( x) dx
a
• First moment with respect
b
to the x-axis
1
Mx 
   f ( x) 

2
2
a
• Mass of the region
b
m     f ( x) dx
a
dx
Centroid of Region Between Curves
• Moments
f(x)
b
M y     x   f ( x)  g ( x)  dx
a
b

g(x)

1
2
2
M x      f ( x)   g ( x) dx
2a
• Mass
b
m      f ( x)  g ( x)  dx
a
Centroid
x
My
m
Mx
y
m
Try It Out!
• Find the centroid of
the plane region
bounded by
y = x2 + 16 and
the x-axis over
the interval 0 < x < 4
• Mx = ?
• My = ?
• m=?
Theorem of Pappus
• Given a region, R, in the plane and L a line in
the same plane and not intersecting R.
• Let c be the centroid and r be the distance
from L to the centroid
L
r
R
c
Theorem of Pappus
• Now revolve the region about the line L
• Theorem states that the volume of the solid of
revolution is V  _______________
where A is the area of R
L
r
R
c
Assignment
• Lesson 7.6
• Page 504
• Exercises 1 – 41 EOO
also 49
Fluid Pressure and Fluid Force
Lesson 7.7
Fluid Pressure
• Definition:
The pressure on an object at depth h is
Pressure  P  ____________
• Where w is the weight-density of the liquid
per unit of volume
• Some example densities
water
62.4 lbs/ft3
mercury
849 lbs/ft3
Fluid Pressure
• Pascal's Principle: pressure
exerted by a fluid at depth
h is transmitted _______in
all __________________
• Fluid pressure given in terms of force per unit
area
F  P  A  wh  A
Fluid Force on Submerged Object
• Consider a rectangular metal sheet measuring
2 x 4 feet that is submerged in 7 feet of water
• Remember
Pressure  P  w  h
so P = 62.4 x 7 = 436.8
• And F = P x A
so F = 436.8 x 2 x 4 = 3494.4 lbs
Fluid Pressure
• Consider the force of fluid
against the side surface of the container
• Pressure at a point
• Density x g x depth
• Force for a horizontal slice
• Density x g x depth x Area
• Total force
d
F    h( y)  L( y) dy
c
Fluid Pressure
• The tank has cross section
of a trapazoid
• Filled to 2.5 ft with water
• Water is 62.4 lbs/ft3
• Function of edge
• Length of strip
• Depth of strip
• Integral
(-4,2.5)
(4,2.5)
2.5 - y
(-2,0)
(2,0)
Assignment A
• Lesson 7.7
• Page 511
• Exercises 1-25 odd