Chapter 13.1-13.4 AP Chem Chemical Equilibrium Chapter 13 Table of Contents • • • • • • • 13.1 13.2 13.3 Pressures 13.4 13.5 Constant 13.6 13.7 Copyright © Cengage Learning.

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Transcript Chapter 13.1-13.4 AP Chem Chemical Equilibrium Chapter 13 Table of Contents • • • • • • • 13.1 13.2 13.3 Pressures 13.4 13.5 Constant 13.6 13.7 Copyright © Cengage Learning.

Chapter 13.1-13.4
AP Chem
Chemical Equilibrium
Chapter 13
Table of Contents
•
•
•
•
•
•
•
13.1
13.2
13.3
Pressures
13.4
13.5
Constant
13.6
13.7
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The Equilibrium Condition
The Equilibrium Constant
Equilibrium Expressions Involving
Heterogeneous Equilibria
Applications of the Equilibrium
Solving Equilibrium Problems
Le Châtelier’s Principle
2
Chapter 13
Table of Contents
• WEEK OUTLOOK
• Monday - Notes 13.1-13.4 with problems w/sheet due
Tuesday - should be able to complete in class today.
• *Be sure all reports are turned in and made up TODAY!
• Tuesday - Notes 13.5-13.7 with emphasis on Le
Chatelier’s Principle emphasized & problems assigned
due Wed. - some time in class to complete
• Kaci & Jonathan - library 2nd floor 7:30 with ACT invent.
• Wednesday- Lab
• Thursday - CAPS - No class
• Friday - Good Friday - No school
• Tuesday - April 2nd - ACT Testing 11th graders only.
• Test probably next Thursday - just over ch. 13 only.
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3
Chapter 13
Table of Contents
• HANDOUTS - Ch. 13 NMSI Equilibrium Packet (Notes
with practice problems)
• HANDOUT - Equilibrium Homework Sheet #1
• TURN IN Kinetics Lab - will go over pre-lab questions
• HW: Equilibrium w/s #1 should be done today - due
Mon. for grade
• HW: Notes packet #1-6 problems due next week but
keep for studying.
• CW: Notes 13.1-13.4
• VOTE ON KINETICS TESTING CH. 12
• Iodine Clock Rxn. Simulation Lab - as time permits
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4
5
Dynamic Nature of Equilibrium
• When a system reaches equilibrium, the
forward and reverse reactions continue to
occur … but at equal rates.
We are usually concerned
with the situation after
equilibrium is reached.
After equilibrium the concentrations of reactants and
products remain constant.
Prentice Hall © 2005
General Chemistry 4th edition, Hill, Petrucci, McCreary, Perry
Chapter Fourteen
Section 13.1
The Equilibrium Condition
Chemical Equilibrium
• The state where the concentrations of all
reactants and products remain constant with
time.
• On the molecular level, there is frantic activity.
Equilibrium is not static, but is a highly dynamic
situation.
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6
Section 13.1
The Equilibrium Condition
Equilibrium Is:
• Macroscopically static
• Microscopically dynamic
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7
Section 13.1
The Equilibrium Condition
Changes in Concentration
• N2(g) + 3H2(g)
2NH3(g)
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Section 13.1
The Equilibrium Condition
Chemical Equilibrium
• Concentrations reach levels where the rate of
the forward reaction equals the rate of the
reverse reaction.
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9
Section 13.1
The Equilibrium Condition
The Changes with Time in the Rates of Forward and Reverse
Reactions
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Section 13.1
The Equilibrium Condition
Concept Check
•Consider an equilibrium mixture in a closed
vessel reacting according to the equation:
• H2O(g) + CO(g)
H2(g) + CO2(g)
•You add more H2O(g) to the flask. How does
the concentration of each chemical compare to
its original concentration after equilibrium is
reestablished? Justify your answer.
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11
Section 13.1
The Equilibrium Condition
Concept Check
•Consider an equilibrium mixture in a closed
vessel reacting according to the equation:
• H2O(g) + CO(g)
H2(g) + CO2(g)
•You add more H2 to the flask. How does the
concentration of each chemical compare to its
original concentration after equilibrium is
reestablished? Justify your answer.
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12
Section 13.2
Atomic
The
Equilibrium
Masses Constant
Law of Mass Action
Consider the following reaction at equilibrium:
•
jA + kB
K=
•
•
•
•
lC + mD
l
m
j
[A]
[B]k
[C] [D]
A, B, C, and D = chemical species.
Square brackets = concentrations of species at equilibrium.
j, k, l, and m = coefficients in the balanced equation.
K = equilibrium constant (given without units).
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13
Section 13.2
Atomic
The
Equilibrium
Masses Constant
Conclusions About the Equilibrium Expression
• Equilibrium expression for a reaction is the
reciprocal of that for the reaction written in
reverse.
• When balanced equation for a reaction is
multiplied by a factor of n, the equilibrium
expression for the new reaction is the original
expression raised to the nth power;
• thus Knew = (Koriginal)n.
• K values are usually written without units.
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Conclusions about Equilibrium Expressions
 The equilibrium expression for a reaction is
the reciprocal for a reaction written in reverse
2NO2(g)  2NO(g) + O2(g)
2NO(g) + O2(g) 2NO2(g)
Conclusions about Equilibrium Expressions
 When the balanced equation for a reaction is
multiplied by a factor n, the equilibrium
expression for the new reaction is the original
expression, raised to the nth power.
2NO2(g)  2NO(g) + O2(g)
NO2(g)  NO(g) + ½O2(g)
Section 13.2
Atomic
The
Equilibrium
Masses Constant
• K always has the same value at a given
temperature regardless of the amounts of
reactants or products that are present initially.
• For a reaction, at a given temperature, there
are many equilibrium positions but only one
value for K.
 Equilibrium position is a set of equilibrium
concentrations.
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Section 13.3
The Mole Expressions Involving Pressures
Equilibrium
• K involves concentrations - (also called Kc)
• Kp involves pressures for gases.
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Section 13.3
The Mole Expressions Involving Pressures
Equilibrium
Example
•
N2(g) + 3H2(g)
2NH3(g)
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Section 13.3
The Mole Expressions Involving Pressures
Equilibrium
Example
•
N2(g) + 3H2(g)
2NH3(g)
• Equilibrium pressures at a certain temperature:
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Section 13.3
The Mole Expressions Involving Pressures
Equilibrium
Example
•
N2(g) + 3H2(g)
2NH3(g)
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Section 13.3
The Mole Expressions Involving Pressures
Equilibrium
The Relationship Between K and Kp
•
Kp = K(RT)Δn
• Δn = sum of the coefficients of the gaseous
products minus the sum of the coefficients of
the gaseous reactants.
• R = 0.08206 L·atm/mol·K
• T = temperature (in kelvin)
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Section 13.3
The Mole Expressions Involving Pressures
Equilibrium
Example
•
N2(g) + 3H2(g)
2NH3(g)
• Using the value of Kp (3.9 × 104) from the
previous example, calculate the value of K at
35°C.
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Section 13.4
Heterogeneous Equilibria
Homogeneous Equilibria
• Homogeneous equilibria – involve the same
phase:
•
N2(g) + 3H2(g)
2NH3(g)
•
HCN(aq)
H+(aq) + CN-(aq)
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Section 13.4
Heterogeneous Equilibria
Heterogeneous Equilibria
• Heterogeneous equilibria – involve more than
one phase:
•
2KClO3(s)
2KCl(s) + 3O2(g)
•
2H2O(l)
2H2(g) + O2(g)
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Section 13.4
Heterogeneous Equilibria
• The position of a heterogeneous equilibrium
does not depend on the amounts of pure solids
or liquids present.
 The concentrations of pure liquids and solids
are constant.
–
–
2KClO3(s)
2KCl(s) + 3O2(g)
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27
Equilibria Involving Pure
Solids and Liquids
• The equilibrium constant expression does
not include terms for pure solid and liquid
phases because their concentrations do not
change in a reaction.
• Example:
Although the
amounts of
pure solid and
CaCO3(s)
CaO(s) + CO2(g)
liquid phases change during a reaction,
these phases
remain
pure and their
[CaO] [CO
]
2
K
=
––––––––––
Kc = [CO2]
c
concentrations
do
not
change.
[CaCO ]
3
Prentice Hall © 2005
General Chemistry 4th edition, Hill, Petrucci, McCreary, Perry
Chapter Fourteen
Section 13.4
ASSIGNMENTS - 2/20/14
Heterogeneous Equilibria
• W/sheet #1 problems due Monday
• This assignment should be able to be completed today
in class but is due Monday.
• Ch. 13 Equilibrium packet - #1-#6 practice problems answers shown to see if you are doing correctly.
• Prepare for Test on Kinetics.
• HW: Read chapter 13 over the next week.
• Ch. 12 Kinetics Test - VOTED for WEDNESDAY - Feb
26
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