Transcript Example 12 page 132  dsin ( 4t ) dt  sin (4t )  sin(4t ) Definitely a Chain Rule Problem.

Example 12 page 132

d
3
sin (4t )
dt

sin (4t )  sin( 4t ) 
3
3
Definitely a Chain Rule Problem
d
3
sin( 4t ) 
dt
d
sin( 4t )
 3sin( 4t ) 
dt
Outside
2
Now do Inside
d
sin( 4t )  cos(4t )[4] Inside
Outside
dt
Chain rule again
d
3
sin( 4t ) 
dt
 3sin( 4t )  cos( 4t ) (4) 
2
2
12 sin (4t ) cos( 4t )