Potential Dividers and their application as sensors Electricity Lesson 9 Learning Objectives To know that a potential divider is a source of variable potential.
Download ReportTranscript Potential Dividers and their application as sensors Electricity Lesson 9 Learning Objectives To know that a potential divider is a source of variable potential.
Potential Dividers and their application as sensors
Electricity Lesson 9
Learning Objectives
To know that a potential divider is a source of variable potential difference.
To derive and know how to use the potential divider equation.
To know that the load affects the output of a potential divider To know the applications of potential dividers; to detect temperature or light levels.
Question
How do we get a variable supply voltage from a fixed one?
How can we measure physical changes in position, temperature or light level etc.
Answer
A potential divider is one way of producing a variable p.d.
A combination of a suitable sensor (angle / position sensor, thermistor or LDR) and a potential divider enables measurement / monitoring / control of physical changes.
V S R 2 V 2 R 1 V 1
Deriving Potential divider equation
For an unloaded potential divider the current is the same through both resistors
V V
2 1
IR IR
2 1
So the voltage is proportional to the resistance V V
2 1
R R
2 1
Potential divider equation
If R1 >> R2 then V1 is more or less the supply voltage
If R1 << R2 then V1 is close to 0 V.
VS as an input to the potential divider and V1 as an output. The circuit itself provides a way to tap off a voltage between 0 V and VS.
V INV V out
Alternative formula
The potential divider equation can be derived by rearranging the ratios above to give:
V output = R1 / (R1+R2) V input.
Using potential dividers
Use as a volume, brightness or contrast control.
Making and designing a circuit to use as a temperature sensor Making and designing a circuit to use as a light sensor Controlling logic devices
Effect of different resistive loads
Output voltage is affected by load resistance Connecting a resistor across the output reduces the output voltage Shorting out across a bulb reduces the total resistance of the bulb – the wire is in parallel with the bulb
Example
6 V 50 A 100 B
Questions
A series circuit is connected as shown in the diagram.
1. What is the potential difference between A and B?
2. An additional resistor of 100 W is connected between the 50 W resistor and the cells. What is the potential difference between A and B now?
3. The additional 100 W resistor is now connected in parallel with the first 100 W resistor. What is the potential difference between A and B now?