7.05 Le Châtelier’s Principle Le Châtelier’s Principle Equilibrium A state in which opposing forces or influences are balanced. • What would happen if he.
Download ReportTranscript 7.05 Le Châtelier’s Principle Le Châtelier’s Principle Equilibrium A state in which opposing forces or influences are balanced. • What would happen if he.
7.05 Le Châtelier’s Principle Le Châtelier’s Principle Equilibrium A state in which opposing forces or influences are balanced. • What would happen if he puts more weigh on his right foot? Definition • Le Châtelier’s Principle: When stress is applied to a system in equilibrium, the reaction will shift in a direction that relieves the stress, and a new equilibrium will be established. • Applied Stresses – Changes in concentration. – Changes in Pressure. – Changes in temperature. Four Scenarios A+B C+D Concentration 3 • If A reactant/product is added to the system at equilibrium, the equilibrium position will shift away from what was added to lower the concentration of the added component. • If a reactant/product is removed from a reaction system at equilibrium, the equilibrium system will shift toward the substance that was removed in order to replace some of what was removed. Practice – Which way does the reaction go? • 1.) 2H2+O2 2H2O • 2.) 2NO+O2 2NO2 (If you increase O2 ) (If you increase NO2 ) • 3.) A + B C (If you decrease C ) • 4.) A + B C (If you decrease A ) Pressure & Volume When the pressure of a system at equilibrium is increased, due to a decrease in volume, the system will shift in the direction that decreased the total moles of gas in the system to minimize the stress. (Shift towards side with less moles) Pressure & Volume Decrease volume/Increase Pressure – By shifting to the right, 4 moles of reactant are used up to produce every 2 moles of product, thus reducing the overall moles of gas present in the system. Pressure & Volume (4 total moles) (2 total moles) The opposite is true if the volume of the container is increased. The system will compensate for the increase in volume and decrease in pressure by shifting toward the side of the equation that has a greater total number of moles of gas. Pressure & Volume - Practice (4 total moles) ( ___ total moles) 1.) How many moles of ammonia gas are on the right side of the equation (product side)? 2.) Which way would the reaction shift if there is a increase in pressure? 3.) If the volume was decreased (increase in pressure) would there be more or less collisions between the reactants? Effect of a Change in Temperature • If the forward reaction is endothermic, write energy as a reactant on the left side of the equation. (+ΔH) Energy + A + B C+D • If the forward reaction is exothermic, write energy as a product on the right side of the equation. (–ΔH) A+B C + D + Energy Temperature - Practice A+B C+D 1.) If energy was added to the reactants side of the above equation which way would the system shift? 2.) Label the following reactions as Endothermic or Exothermic. a.) Energy + N2O4 b.) C + O2 2NO2 CO2 + Energy Additional Practice – Circle the correct answer H2 + O2 H2O 1.) Adding more of H2 or O2 will cause the system to shift Left / Right to reach a new equilibrium. 2.) Adding more of H2O will cause the system to shift Left / Right to reach a new equilibrium. 3.) For a gaseous reaction If the pressure was decreased there would be more / less collisions between the reactants. 4.) The system will shift towards/away from the side of the equation where energy is written.