Transcript Published by – www.Padasalai.Net Thanks to Mr. Ravi, B.T.Asst., GHS, Arangaldurgam.

Published by – www.Padasalai.Net
Thanks to Mr. Ravi, B.T.Asst., GHS, Arangaldurgam.
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(X+2)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(2X – 1)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(2X – 1)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(2X – 1)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(2X – 1)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)
k/r]`pfpDtfTk: 2x3 + x2 – 5x + 2
+2
+1
–5
+2
0
+2
+3
–2
+2
+3
–2
0
2x2
+ 3x
–2
=
2x2
– 1x
+ 4x
=
(2 x X x X)
– (1 x X)
=
X
(2X – 1)
=
(2X – 1)
(X + 2)
+1
k/r]`kqf =
(X – 1)
(x – 1) oR k/r]`
<p.p.
–4
–2
–
+
+ (2x2xX)
– (1 x 2)
–1
+4
+2
(2X – 1)
(X + 2)
(2X – 1)
$. p. + 3
(+ 3)