Special Parallelograms LESSON 6-4 Additional Examples Find the measures of the numbered angles in the rhombus. Theorem 6–9 states that each diagonal of a rhombus.
Download ReportTranscript Special Parallelograms LESSON 6-4 Additional Examples Find the measures of the numbered angles in the rhombus. Theorem 6–9 states that each diagonal of a rhombus.
Special Parallelograms LESSON 6-4 Additional Examples
Find the measures of the numbered angles in the rhombus.
Theorem 6 –9 states that
each diagonal of a rhombus bisects two angles of the rhombus,
so
m
1 = 78.
Theorem 6-10 states that
the diagonals of a rhombus are perpendicular,
so
m
2 = 90.
Because the four angles formed by the diagonals all must have measure 90, 3 and
ABD m ABD
= 78,
m
must be complementary. Because 3 = 90 – 78 = 12.
Finally, because
BC
=
DC
, the Isosceles Triangle Theorem allows you to conclude 1 4. So
m
4 = 78.
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Special Parallelograms LESSON 6-4 Additional Examples
One diagonal of a rectangle has length 8
x
+ 2. The other diagonal has length 5
x
+ 11. Find the length of each diagonal.
By Theorem 6-11, the diagonals of a rectangle are congruent. 5
x
+ 11 = 8
x
+ 2 11 = 3
x
+ 2 9 = 3
x
3 =
x
8
x
+ 2 = 8( 3 ) + 2 = 26 5
x
+ 11 = 5( 3 ) + 11 = 26 The length of each diagonal is 26.
Diagonals of a rectangle are congruent.
Subtract 5
x
from each side.
Subtract 2 from each side.
Divide each side by 3.
Substitute.
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Special Parallelograms LESSON 6-4 Additional Examples
The diagonals of
ABCD
are perpendicular.
AB
= 16 cm and
BC
= 8 cm. Can
ABCD
be a rhombus or rectangle?
Explain.
Use indirect reasoning to show why ABCD cannot be a rhombus or rectangle.
Suppose that
ABCD
is a parallelogram. Then, because its diagonals are perpendicular,
ABCD
must be a rhombus by Theorem 6-12.
But
AB
= 16 cm and
BC
= 8 cm. This contradicts the requirement that the sides of a rhombus are congruent. So
ABCD
cannot be a rhombus, or even a parallelogram.
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Special Parallelograms LESSON 6-4 Additional Examples
Explain how you could use the properties of diagonals to stake the vertices of a play area shaped like a rhombus.
• By Theorem 6-7, if the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.
• By Theorem 6-13, if the diagonals of a parallelogram are perpendicular, then the parallelogram is a rhombus.
One way to stake a play area shaped like a rhombus would be to cut two pieces of rope of any lengths and join them at their midpoints. Then, position the pieces of rope at right angles to each other, and stake their endpoints.
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