Section 5.3 Special Products Copyright © 2013, 2009, 2006 Pearson Education, Inc. Objective #1 Use FOIL in polynomial multiplication. Copyright © 2013, 2009, 2006 Pearson Education,

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Transcript Section 5.3 Special Products Copyright © 2013, 2009, 2006 Pearson Education, Inc. Objective #1 Use FOIL in polynomial multiplication. Copyright © 2013, 2009, 2006 Pearson Education,

Slide 1

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 2

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 3

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 4

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 5

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 6

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 7

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 8

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 9

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 10

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 11

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 12

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 13

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 14

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 15

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 16

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 17

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 18

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 19

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 20

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 21

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 22

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 23

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 24

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 25

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 26

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 27

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 28

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 29

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 30

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32


Slide 31

Section 5.3
Special
Products

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

1

Objective #1
Use FOIL in polynomial multiplication.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

11

Objective #2
Multiply the sum and difference of two terms.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

17

Objective #3
Find the square of a binomial sum.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

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22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

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23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

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24

Objective #4
Find the square of a binomial difference.

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25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

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30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
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32


Slide 32

Section 5.3
Special
Products

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1

Objective #1
Use FOIL in polynomial multiplication.

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2

Special Products
In this section we will use the distributive property to develop patterns that will
allow us to multiply some special binomials quickly.
We will find the product of two binomials using a method called FOIL.
We will learn a formula for finding the square of a binomial sum. We will also
learn formula for finding the product of the sum and difference of two terms.

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3

Multiplying Polynomials - FOIL

Using the FOIL Method to Multiply Binomials
last
first

F

O

I

L

ax  bcx  d   ax  cx  ax d  b  cx  b  d
inside
outside

Product of
First terms

Product of
Outside terms

Product of
Inside terms

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

Product of
Last terms

4

Multiplying Polynomials - FOIL
EXAMPLE

Multiply 4 x  35x  1 .

SOLUTION
last

F

O

I

L

first

4x  35x  1  4 x  5x  4 x 1  3  5x  3 1
inside
outside

 20x 2  4 x  15x  3

Multiply

 20x 2  19x  3

Combine like terms

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5

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
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6

FOIL Method
EXAMPLE

Multiply: (5x + 2)(x + 7)
F

O

I

L

(5x + 2)(x + 7) = 5x·x + 5x·7 + 2·x + 2·7
Product
of the
first
terms

Product
of the
outside
terms

Product
of the
inside
terms

Product
of the
last
terms

=5x2 + 35x + 2x +14
=5x2 + 37x +14
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7

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

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8

Objective #1: Example

1a. Multiply: ( x  5)( x  6)
F

O

I

L

( x  5)( x  6)  x  x  6  x  5  x  5  6
 x 2  6 x  5 x  30
 x 2  11x  30

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9

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

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10

Objective #1: Example

1b. Multiply: (7 x  5)(4 x  3)
F

O

I

L

(7 x  5)(4 x  3)  7 x  4 x  7 x( 3)  5  4 x  5( 3)
 28 x 2  21x  20 x  15
 28 x 2  x  15

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11

Objective #2
Multiply the sum and difference of two terms.

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12

Multiplying the Sum and Difference of Two Terms

(A + B)(A – B) = A2 – B2
The product of the sum and the difference of
the same two terms is the square of the first
term minus the square of the second term.

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13

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

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14

Objective #2: Example

2a. Multiply: (7 y  8)(7 y  8)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

second term
squared

(7 y  8)(7 y  8)  (7 y ) 2 

82

 49 y 2  64

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

15

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

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16

Objective #2: Example

2b. Multiply: (2a3  3)(2a3  3)
Since this product is of the form ( A  B)( A  B) ,
use the special–product formula ( A  B)( A  B)  A2  B2 .
first term
squared

(2a3  3)(2a3  3)  (2a3 ) 2 

second term
squared

32

 4a 6  9

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17

Objective #3
Find the square of a binomial sum.

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18

The Square of a Binomial Sum
(A + B)2 = A2 + 2AB + B2

The square of a binomial sum is the first
term squared plus two times the product
of the terms plus the last term squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

19

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 4x  y 2 .

SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



4x  y 2 



A2

4x 2

2

+

2 AB
2  Product



B2

+

 Last 


Term



+

y2

of theT erms

+

2  4x  y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 16x 2  8xy  y 2

20

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

21

Objective #3: Example

3a. Multiply: ( x  10)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  10) 2 

x2

2  product
of the terms

last term
squared

 2 10 x  102

 x 2  20 x  100

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

22

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

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23

Objective #3: Example

3b. Multiply: (5 x  4)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(5 x  4) 2  (5 x) 2  2  20 x 

last term
squared

42

 25 x 2  40 x  16

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24

Objective #4
Find the square of a binomial difference.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

25

The Square of a Binomial Difference
(A – B)2 = A2 – 2AB + B2
The square of a binomial difference is the
first term squared minus two times the
product of the terms plus the last term
squared.

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

26

Multiplying Polynomials – Special Formulas
EXAMPLE

Multiply 3x  4 y 2 .
SOLUTION

Use the special-product formula shown.

A  B2 

 First 


Term



3x  4 y 2 



A2

3x 2

2



2 AB
2  Product



B2

+

 Last 


Term



+

4y 2

of theT erms



2  3x  4 y

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

2

= Product
 9x 2  24xy  16y 2

27

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

28

Objective #4: Example

4a. Multiply: ( x  9)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

( x  9) 2 

x2

last term
squared

2  product
of the terms



2  9x



92

 x 2  18 x  81

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

29

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

30

Objective #4: Example

4b. Multiply: (7 x  3)2
Use the special-product formula ( A  B)2  A2  2 AB  B2 .
first term
squared

2  product
of the terms

(7 x  3) 2  (7 x) 2  2  21x 

last term
squared

32

 49 x 2  42 x  9

Copyright © 2013, 2009, 2006 Pearson Education, Inc.

31

Multiplying Polynomials – Special Formulas
The Square of a Binomial Sum

A  B2  A2  2 AB  B2
The Square of a Binomial Difference

A  B2  A2  2 AB  B2
The Product of the Sum and
Difference of Two Terms

 A  BA  B  A2  B2
Copyright © 2013, 2009, 2006 Pearson Education, Inc.

32