Solve Each Question before you click. Check you answers, look at your notes if you need. Solving Equations by 2-12 Multiplying Insert Lesson Title Here or Dividing Lesson.

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Transcript Solve Each Question before you click. Check you answers, look at your notes if you need. Solving Equations by 2-12 Multiplying Insert Lesson Title Here or Dividing Lesson.

Solve Each Question before you click. Check you answers, look at your notes if you need.

2-12 Lesson Quiz: Part 1 Solve the equation. Check your answer.

1. 12 = 4x x = 3 2. 18z = 90 3. 12 =

x

4 4. 840 = 12y

5.

h

22 = 9 z = 5 x = 48 y = 70 h = 198

Course 2

2-12 Lesson Quiz: Part 2

6. The cost of each ticket at the carnival was $0.25.

Li bought $7.50 worth of tickets. How many tickets did she buy?

30

Course 2

Warm Up Solve.

1. n + 9 = 17 2. 6x = 42 3. 71 – z = 55

4.

y

8 = 9 n = 8 x = 7 z = 16 y = 72

Combine Like Terms

1) 5x + 4y – x + 3x 7x + 4y 3) 35 + 3x + 4g – x + 3g – g + 7 42 + 2x + 6g 2) 7(4y -2) + 2x - y 28x – 14 + 2x -y 30x – 14 - y 4) 3(3x + 2) – x 9x + 6 - x 8x + 6

Combine like terms.

1. 3x + 4 + 2x 5x + 4

Lesson Quiz

2. 13k + 6  8k + 9 + k 6k + 15

Simplify.

3. 4(3x + 6)  7x 5x + 24 4. 6(x + 5) + 3x 9x + 30

Solve.

5. 6y + y = 42 y = 6 6. The accounting department ordered 15 boxes of pens. The marketing department ordered 9 boxes of pens. If the total cost of the combined order was $72, what is the price of each box of pens?

$3

11-1 Lesson Quiz Solve. Check your answers.

1. 6x + 8 = 44 x = 6 2. 14y – 14 = 28

3.

m

7 + 3 = 12

4.

v

–8 – 6 = 8 y = 3 m = 63 v = –112 5. Last Sunday, the Humane Society had a 3-hour adoption clinic. During the week the clinic is open for 2 hours on days when volunteers are available.

If the Humane Society was open for a total of 9 hours last week, how many weekdays was the clinic open?

3 days

Course 2

Insert Lesson Title Here

Lesson Quiz Solve.

1. c + 21 + 5c = 63 c = 7 2. x – 11 + 17x = 53 x = 4 3. w – 16 + 4w = 59 w = 15

4.

4k + 6 5 = 10 k = 11 5. Kelly swam 4 times as many laps as Kathy. Adding 5 to the number of laps Kelly swam gives you the number of laps Julie swam. If Julie swam 9 laps, how many laps did Kathy swim?

1 lap

11-3 Solving Equations with Variables on Both Sides Warm Up Solve.

1. 6n + 8 – 4n = 20 n = 6 2. –4w + 16 – 4w = –32 w = 6 3. 25t – 17 – 13t = 67 t = 7

4.

4k + 9 –25 k = –6

Course 2

11-3 Lesson Quiz Group the terms with variables on one side of the equal sign, and simplify.

1.

2.

14

n

–14 = 11

k n

+ 81 + 12 = –18

k

3

n

= 81 4

k

= –12

Solve.

3.

58 + 3

y

= –4

y

– 19

4.

– 3 4

x

= 1 8

x

– 14

y x

= –11 = 16

Course 2

11-3 Lesson Quiz Group the terms with variables on one side of the equal sign, and simplify.

1. 14n = 11n + 81 3n = 81 2. –14k + 12 = –18k 4k = –12

Solve.

3. 58 + 3y = –4y – 19 4. – 3 4 x = 1 8 x – 14 y = –11 x = 16

Course 2

11-3 Solving Equations with Variables on Both Sides Additional Example 3: Consumer Math Application Christine can buy a new snowboard for $136.50. She will still need to rent boots for $8.50 a day. She can rent a snowboard and boots for $18.25 a day. How many days would Christine need to rent both the snowboard and the boots to pay as much as she would if she buys the snowboard and rents only the boots for the season?

Course 2

11-3 Solving Equations with Variables on Both Sides Additional Example 3 Continued

Let d represent the number of days.

18.25d = 136.5 + 8.5d 18.25d – 8.5d = 136.5 + 8.5d 9.75d = 136.5

– 8.5d

Subtract 8.5d

from both sides.

Simplify.

9.75d = 136.5

9.75

9.75

d = 14

Divide both sides by 9.75.

Christine would need to rent both the snowboard and the boots for 14 days to pay as much as she would have if she had bought the snowboard and rented only the boots.

Course 2

11-3 Try This: Example 3 A local telephone company charges $40 per month for services plus a fee of $0.10 a minute for long distance calls. Another company charges $75.00 a month for unlimited service. How many minutes does it take for a person who subscribes to the first plan to pay as much as a person who subscribes to the unlimited plan? Course 2

11-3 Try This: Example 3 Continued

Let m represent the number of minutes.

75 75 = 40 + 0.10m – 40 = 40 – 40 + 0.10m 35 = 0.10m 35 0.10m 0.10

= 0.10

350 = m

Subtract 40 from both sides.

Simplify.

Divide both sides by 0.10.

If you are going to use more than 350 minutes, it will be cheaper to subscribe to the unlimited plan.

Course 2

Homework Work Sheet – go see Mr. Todd